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Chapter 7: Q. 36 (page 429)

An unknown distribution has a mean of 100, a standard deviation of 100, and a sample size of 100. Let X=one object of interest.

What is P(危x>9,000)?

Short Answer

Expert verified

The value ofP(X>9000)=0.8413.

The graph is

Step by step solution

01

Given Information

The mean is 100, Standard deviation is 100, and a sample size of 100.

And we need to find P(危x>9,000)localid="1648807337983" P(危x>9,000).

02

Calculation

The information is,

鈭�X~Nn渭x,n蟽x

鈭�X~N((100)(100),(100)(100))

Now, we can find the probability that the sum of the 100values is greater than 9000

P(X>9000)=PZ>X鈭�n渭xn蟽x

=PZ>9000鈭�100001000

=P(Z>鈭�1)

P(X>9000)=0.8413

The graph of the answer is

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