91Ó°ÊÓ

Let, the mean age of the $100$Canadian prostitutes upon entering prostitution was $18$with a standard deviation of six. And the mean age of the $130$United States prostitutes upon entering prostitution was $20$ with a standard deviation of eight.

Let, 2 means, independent sample, and the population standard deviations unknown.
Then the random variable is $\stackrel{¯}{X_1}-\stackrel{¯}{X_2}$
The hypothesis are:
$H_0:{\mathrm{μ}}_1={\mathrm{μ}}_2$
$H_0:{\mathrm{μ}}_1<{\mathrm{μ}}_2$
In Canada, the average age of entry into prostitution is lower than in the United States.

The $p-$value for graph lift tailed:$0.0157$
Decision: do no reject $H_0$.
As a result, there is lack of evidence from the sample data to declare that the mean age of entry into prostitution in Canada is lower than the mean age in the United States at the $1\%$ level of significance.