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At Rachel’s 11th birthday party, eight girls were timed to see how long (in seconds) they could hold their breath in a

relaxed position. After a two-minute rest, they timed themselves while jumping. The girls thought that the mean difference

between their jumping and relaxed times would be zero. Test their hypothesis.

Short Answer

Expert verified

Since p- the value is greater than α=0.05,we cannot reject the hypothesis H0and we can conclude that it is insufficient

evidence to conclude that the average difference is not zero.

Step by step solution

01

Given Information 

We need to test the hypothesis

02

Explanation 

We can take X1-X2to represent the difference between jumping and relaxed time.

We want to test this hypothesis:

H0:μ1=μ2H1:μ1≠μ2

In order to test the hypothesis, we are using the Student's test.

03

Simplification 

We need to find the mean and stand deviation of both samples:

μ1=32.375,s1=9.620477μ2=30.625,s2=8.331309

The differences between jumping and relaxed times are given by:

5, 7, 2, 1, - 2, 2, 2 -3

The number of differences is α=1.75:

∑i-18(di-a)2=75.5

Standard deviation differences are:

8=1n-1∑i-18(di-a)2=75.57=3.284

The standard error is: SE=n8=1.161

We can find the value of the test statistic is:

t=μ1-μ2SE=1.507

04

Graphical Presentation 

Using the applet, we get that p-value is 0.17554:

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