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A population has a mean is 25 and a standard deviation of five. The sample mean is 24, and the sample size is 108. What distribution should you use to perform a hypothesis test?

Short Answer

Expert verified

When the standard deviation is known and the population size is large, the Normal distribution approach is appropriate for performing the hypothesis test.

Step by step solution

01

Given Information

The population has a mean of 25and a standard deviation of 5. According to the data, the population has a mean of 25and a standard deviation of 5. The sample size is 108people, and the sample mean is 24. Now, for a hypothesis test.

02

Explanation

Typically, a hypothesis test is conducted on a sample of data drawn from a broader population. This test is used to generate results from sample data based on a hypothesis. Because we have the standard mean, standard deviation, sample mean, and population size, the hypothesis test may be performed using the normal distribution approach. The normal distribution is a continuous probability distribution with a bell shape in which all values cluster around the mean.

03

Calculation

We must use the following formula to calculate using the normal distribution:

The sample mean is X, the population mean is μ, the standard deviation is σ, and the sample size is η.

Z=X¯σ-μ/η

24-255/108

=-15/10.3923=-2.078

As a result, the normal distribution approach is suitable for larger populations with established standard deviation values.

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Most popular questions from this chapter

The National Institute of Mental Health published an article stating that in any one-year period, approximately 9.5percent of American adults suffer from depression or a depressive illness. Suppose that in a survey of 100 people in a certain town, seven of them suffered from depression or a depressive illness. Conduct a hypothesis test to determine if the true proportion of people in that town suffering from depression or a depressive illness is lower than the percent in the general adult American population.

a. Is this a test of one mean or proportion?

b. State the null and alternative hypotheses.

H0:

Ha:

c. Is this a right-tailed, left-tailed, or two-tailed test?

d. What symbol represents the random variable for this test?

e. In words, define the random variable for this test.

f. Calculate the following:

i.x=

ii.role="math" localid="1649760873126" n=

iii.p'=

g. Calculate role="math" localid="1649760901479" σx=Show the formula set-up.

h. State the distribution to use for the hypothesis test.

i. Find the p-value.

j. At a pre-conceived α=0.05, what is your:

i. Decision:

ii. Reason for the decision:

iii. Conclusion (write out in a complete sentence):

From generation to generation, the mean age when smokers first start to smoke varies. However , the standard deviation pf that age remains constant of around 2.1years . A survey of 40smokers of this generation was done to see if the mean starting age is at least 19. the sample mean was 18.1 with a sample standard deviation of1.3do the data support the claim at the 5%level?

For statements a-j ( Section: 9.109 ), answer the following in complete sentences.

a. State a consequence of committing a Type I error.

b. State a consequence of committing a Type II error.

"Red tide" is a bloom of poison-producing algae-a few different species of a class of plankton called dinoflagellates. When the weather and water conditions cause these blooms, shellfish such as clams living in the area develop dangerous levels of a paralysis-inducing toxin. In Massachusetts, the Division of Marine Fisheries (DMF) monitors levels of the toxin in shellfish by regular sampling of shellfish along the coastline. If the mean level of toxin in clams exceeds 800μ²µ(micrograms) of toxin per kg of clam meat in any area, clam harvesting is banned there until the bloom is over and levels of toxin in clams subside. Describe both a TypeI and a Type IIerror in this context, and state which error has the greater consequence.

A statistics instructor believes that fewer than 20% of Evergreen Valley College (EVC) students attended the opening midnight showing of the latest Harry Potter movie. She surveys 84 of her students and finds that 11 of them attended the midnight showing. The Type I error is to conclude that the percent of EVC students who attended is ________.

a. at least 20%, when in fact, it is less than 20%.

b. 20%, when in fact, it is 20%.

c. less than20%, when in fact, it is at least 20%.

d. less than 20%, when in fact, it is less than 20%.

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