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On average, Pierre, an amateur chef, drops three pieces of egg shell into every two cake batters he makes. Suppose

that you buy one of his cakes.

a. In words, define the random variable X.

b. List the values that Xmay take on.

c. Give the distribution ofX.X~_____(_____,_____)

d. On average, how many pieces of egg shell do you expect to be in the cake?

e. What is the probability that there will not be any pieces of egg shell in the cake?

f. Let’s say that you buy one of Pierre’s cakes each week for six weeks. What is the probability that there will not

be any egg shell in any of the cakes?

g. Based upon the average given for Pierre, is it possible for there to be seven pieces of shell in the cake? Why?

Short Answer

Expert verified

(a) The random variable Xhas the following definition:

X=the number of shell pieces in a single cake.

(b) Because the random variable Xhas a Poisson distribution with an upper bound of 100,the value is given by x=0,1,2,…

(c) The result is X~P(1.5).

(d) the result is μ=1.5.

(e) The result we get P(x=0)=0.2231.

(f) The result P(x=0)=0.0001.

(g) The resultP(x=7)=0.00075.

Step by step solution

01

Explanation (a)

The random variableXhas the following definition:

X=the percentage of seniors who participated in after-school sports throughout their four years of high school.

02

Explanation (b)

Make a list of all the possible values for X.

Because the random variable Xhas a Poisson distribution with an upper bound of 100, the value is given by x=0,1,2,…

03

Explanation (c)

The random variable Xwill be distributed according to the Poisson distribution. In every two cakes, three pieces of egg shell are given, and in each piece of cake, one piece of egg shell is given.

=32

=1.5

X~P(1.5)

04

Explanation (d)

The Poisson distribution predicted is equal to,

μ=1.5

As a result, we you except 1.5egg shell fragments in the cake.

05

Explanation (e)

The required probability can be represented as P(x=0), and it can then be determined with a calculator.

As a result, the chance that there would be no fragments of egg shell in the cake is P(x=0)=0.2231.

06

Explanation (f)

It is provided. If there are 3pieces of egg shell in every 2cakes, then there are 6 pieces of egg shell in each cake.

=32×6=9

The random variable Xwill follow Poisson distribution as below,

X~P(9)

The required probability can be expressed asP(x=0) and then determined with a calculator.

23498041E-4

As a result, the probability P(x=0)=0.0001is the likelihood that no egg shell will be found in any of the cakes.

07

Explanation (g)

Probability can be determined using P(x=7)rather than a calculator. 7.564261847E-4

As a result, based on the average supplied for Pierre, probability P(x=7)=0.00075is not zero; yes, there could be seven pieces of shell in the cake.

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