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A bridge hand is defined as 13 cards selected at random and without replacement from a deck of 52 cards. In a standard deck of cards, there are 13 cards from each suit: hearts, spades, clubs, and diamonds. What is the probability of being dealt a hand that does not contain a heart?

a. What is the group of interest?

b. How many are in the group of interest?

c. How many are in the other group?

d. Let X = _________. What values does X take on?

e. The probability question is P(_______).

f. Find the probability in question.

g. Find the (i) mean and (ii) standard deviation of X

Short Answer

Expert verified

a. The group of interest is the pack of heart cards.

b. Cards that are not hearts is39

c. Other group includes the number of hearts in a deck which is 13

d. X is the number of cards that are not hearts and the value of X is 0,1,2,3,......,13.

e. The probability isP(X=13)

f. The probability is 0.0128

g. mean is 9.75and standard deviation is 1.3653

Step by step solution

01

Content Introduction

A discrete probability distribution, the hypergeometric distribution. It's utilised when you want to know how likely it is to get a certain number of successes from a given sample size without replacement.

02

Explanation (part a)

The group of interest is the pack of heart cards.

03

Explanation (part b)

The group of interest is hearts.

The pack of cards contain52in total and the pack contains the deck of hearts is13, therefore, the total card52-13=39

04

Explanation (part c)

The total pack of cards is 52which includes hearts, spades, clubs, and diamonds. Other group includes the number of hearts in a deck which is13

05

Explanation (part d)

Random variable in simple terms generally refers to variables whose values are unknown, therefore, in this case X is the number of cards that are not hearts.

The value of X is0,1,2,3,...........,13.

06

Explanation (part e)

The probability question isP(X=13)

07

Explanation (part f)

The probability so formed is

P(X=13)=(39,52)(38,51)(37,50)(36,49)(35,48)(34,47)(33,46)(32,45),....P(X=13)=0.0128
08

Explanation (part g)

To find the mean we are given,

n=13,b=39,r=13

role="math" localid="1649173640357" mean(μ)=n×rr+bmean(μ)=13×3913+39mean(μ)=9.75

standard deviation is δx=μx

δ=9.75δ=1.3653

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