91Ó°ÊÓ

i. We need to know the mean and standard deviation in order to calculate them. To enter the stat List editor using the SETUP Editor command, press STAT followed by 1.

$\stackrel{¯}{x}=8628.74$

ii. The standard deviation of community college enrolment,$s_x=6944$.

iii. The number of colleges that were polled,

$n=35$

iv. If there are $35$community colleges in all, the value equals $n-1=34$.

The mean enrollment for the sample of 35 community colleges is X, and the enrollment for the community college is X.

With the parameters$tn-1,$ the distribution is.

$t35-1=t34$

i. The confidence interval should be stated.

The confidence interval's output,

$CI=(6243.4,11014)$

ii. The graph is as follows:

iii. The formula is used to compute the error bound.

$EBM=t_{n-1}\left(\frac{\mathrm{Î\pm }}{2}\right)\frac{s}{\sqrt{n}}$

$EBM=t_{35-1}\left(\frac{0.05}{2}\right)\frac{6944}{\sqrt{35}}$

$EBM=2385.3$

As we all know, when the sample size grows by a significant amount, the variability lowers as well. We have a smaller Confidence interval with fewer error boundaries to be taken the genuine population parameter as the variability diminishes. Both will shrink in size as a result of this.