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the world's first mammal to be cloned, was introduced to the public in 1997. In a Pew Research poll taken soon after Dolly's debut, \(63 \%\) of Americans were opposed to the cloning of animals. In a Pew Research poll taken 20 years after Dolly, \(60 \%\) of those surveyed were opposed to animal cloning. Assume this was based on a random sample of 1100 Americans. Does this survey indicate that opposition to animal cloning has declined since 1997 ? Use a \(0.05\) significance level.

Short Answer

Expert verified
To determine if opposition to animal cloning has decreased, compute the z-score using the given statistics, and then calculate the corresponding p-value. Compare the p-value to the given significance level of 0.05 to make the final decision.

Step by step solution

01

Define the Hypotheses

The null hypothesis \(H_0\) is that the proportion of Americans opposing animal cloning has not changed, meaning the proportion \(p\) in 2017 is 0.63 (or 63%). The alternative hypothesis \(H_A\) is that the proportion \(p\) of Americans opposing animal cloning has declined, meaning \(p < 0.63\).
02

Calculate the Test Statistic

In this case, we are dealing with a one-sample z-test for a proportion. The test statistic is calculated using the formula \[Z = \frac{\hat{p} - p_0}{\sqrt{ \frac{p_0(1-p_0)}{n} }}\]where \(\hat{p}\) is the sample proportion, \(p_0\) is the proportion under the null hypothesis, and n is the sample size. Plugging in the information from the problem, we get:\[Z = \frac{0.60 - 0.63}{\sqrt{ \frac{0.63(1-0.63)}{1100} }}\]
03

Find the P-Value

The P-value corresponds to the probability of observing a test statistic as extreme as the one we calculated under the null hypothesis. Because this is a one-tailed test, we can look up the Z-score in a standard normal (Z) table to get the P-value.
04

Make the Decision

If the P-value is less than the significance level (0.05), then we reject the null hypothesis in favor of the alternative. If the P-value is greater than the significance level, then we do not reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-test for proportions
A Z-test for proportions is a statistical method used to determine whether there is a significant difference between an observed sample proportion and a known population proportion. This test helps us, for instance, to check if people's attitudes towards a subject, like animal cloning, have changed over time.

In our case, the focus is on the proportion of Americans who opposed animal cloning. We have two proportions: one from 1997 (63%) and another from the 2017 survey (60%). The Z-test for proportions allows us to evaluate if this difference is statistically significant or simply due to random sampling variation.

The formula used to calculate the Z-statistic is:

\[Z = \frac{\hat{p} - p_0}{\sqrt{ \frac{p_0(1-p_0)}{n} }}\]

Where:
  • \(\hat{p}\) is the sample proportion (0.60 in this case).
  • \(p_0\) is the proportion under the null hypothesis (0.63).
  • \(n\) is the sample size (1100).

Understanding this calculation helps you to ascertain how far the sample statistic is from the population parameter in standard error units.
Null hypothesis
The null hypothesis is a foundational concept in hypothesis testing, represented as \(H_0\). It assumes that any observed difference in the sample is due to random chance and not due to an actual effect.

For the problem concerning the opposition to animal cloning, the null hypothesis \(H_0\) claims that there has been no change in the proportion of Americans opposing cloning between 1997 and 2017. Specifically, it states that the proportion in 2017 remains 0.63, the same as in 1997.

The opposite of the null hypothesis is the alternative hypothesis \(H_A\), which suggests that the proportion in 2017 is less than 0.63, indicating a decline in opposition over the 20 years. Formulating these hypotheses accurately is crucial to correctly conduct statistical tests and interpret their results.
P-value
The P-value is a probability that helps you determine the significance of your statistical test results. It quantifies how likely it is to observe your data, or something more extreme, assuming the null hypothesis \(H_0\) is true.

In the animal cloning example, the P-value tells us whether the observed 60% opposition in 2017 could have happened if the true opposition rate was still 63%. The smaller the P-value, the stronger the evidence against the null hypothesis.

If the P-value is below a predetermined threshold (known as the significance level, usually 0.05), it suggests that the evidence is strong enough to reject the null hypothesis. Thus, a low P-value here would support the claim that opposition to animal cloning has decreased.

Finding the P-value involves calculating the probability associated with the Z-score derived from the test statistic. This can be done via statistical tables or software with standard normal distribution functions.
Significance level
The significance level is a critical concept in hypothesis testing, often denoted as \(\alpha\). It represents the threshold probability for deciding whether to reject the null hypothesis.

In most cases, like in our example about animal cloning, the significance level is set at 0.05 or 5%. This value signifies a 5% risk of concluding there's a difference when, in fact, there isn't (a Type I error).

The significance level is crucial because it balances the risk of error in hypothesis testing. If the P-value is less than 0.05, we reject the null hypothesis, suggesting significant evidence for a change since 1997. If it is higher, we do not reject \(H_0\), indicating that the change in opposition may not be statistically significant.

Understanding the significance level helps in interpreting whether the results of a test are actually meaningful given the data at hand.

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Most popular questions from this chapter

Refer to Exercise \(8.97 .\) Suppose 14 out of 20 voters in Pennsylvania report having voted for an independent candidate. The null hypothesis is that the population proportion is \(0.50 .\) What value of the test statistic should you report?

Taste Test A student was tested to see if he could tell the difference between two different brands of cola. He was presented with 20 samples of cola and correctly identified 12 of the samples. Since he was correct 60 percent of the time, can we conclude that he can correctly tell the difference between two brands of cola based on this sample alone?

In 2016 the Harris poll estimated that \(3.3 \%\) of American adults are vegetarian. A nutritionist thinks this rate has increased. The nutritionist samples 150 American adults and finds that 11 are vegetarian. a. What is \(\hat{p}\), the sample proportion of vegetarians? b. What is \(p_{0}\), the hypothetical proportion of vegetarians? c. Find the value of the test statistic. Explain the test statistic in context.

A true/false test has 50 questions. Suppose a passing grade is 35 or more correct answers. Test the claim that a student knows more than half of the answers and is not just guessing. Assume the student gets 35 answers correct out of \(50 .\) Use a significance level of \(0.05 .\) Steps 1 and 2 of a hypothesis test procedure are given. Show steps 3 and 4, and be sure to write a clear conclusion. $$ \text { Step 1: } \begin{aligned} &\mathrm{H}_{0}: p=0.50 \\ &\mathrm{H}_{\mathrm{a}}: p>0.50 \end{aligned} $$ Step 2: Choose the one-proportion z-test. Sample size is large enough, because \(n p_{0}\) is \(50(0.5)=25\) and \(n\left(1-p_{0}\right)=50(0.50)=25\), and both are more than \(10 .\) Assume the sample is random and \(\alpha=0.05\).

Choose one of the answers given. The null hypothesis is always a statement about a (sample statistic or population parameter).

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