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Choosing a Test and Naming the Population(s) For each of the following, state whether a one-proportion \(z\) -test or a two-proportion \(z\) -test would be appropriate, and name the population(s). a. A polling agency takes a random sample of voters in California to determine if a ballot proposition will pass. b. A researcher asks a random sample of residents from coastal states and a random sample of residents of non-coastal states whether they favor increased offshore oil drilling. The researcher wants to determine if there is a difference in the proportion of residents who support off-shore drilling in the two regions.

Short Answer

Expert verified
For part a, a one-proportion \(z\) -test is used, and the population is the voters in California. For part b, a two-proportion \(z\) -test is used, and the populations are the coastal and non-coastal state residents.

Step by step solution

01

Identifying the Test and Population for Part a

Given a polling agency is determining if a ballot proposition will pass, a one-proportion \(z\) -test is appropriate here because only one population is looked at. The population in this case is all voters in California.
02

Identifying the Test and Population for Part b

Given a researcher is comparing the opinions of residents from coastal states and non-coastal states, a two-proportion \(z\) -test is appropriate here because there are two different populations that are being compared. The groups are residents from coastal states and residents from non-coastal states.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

One-Proportion z-Test
The one-proportion z-test is a statistical tool used when comparing a sample proportion to a known population proportion to determine if there is a significant difference between them. For instance, in the context of the exercise, when a polling agency wishes to predict the outcome of a ballot proposition, they are essentially assessing if the sample of voters' proportion who support the proposition significantly deviates from a specific threshold (such as 50% for a pass/fail scenario).

The population in this example consists of all eligible voters in California. Thus, the one-proportion z-test allows the agency to infer, with a given level of confidence, whether the sample results can be generalized to the entire voting population. This method assumes a large enough sample size and a binomial distribution (i.e., voters can only be 'for' or 'against' the proposition), and the results are used to estimate the true proportion of the entire population that supports the ballot proposition.
Two-Proportion z-Test
When comparing the proportions from two different populations, as done by the researcher in the exercise who is gauging the opinions on offshore drilling from coastal versus non-coastal residents, the two-proportion z-test becomes our statistical tool of choice. This test evaluates whether there is a significant difference between the population proportions based on sample data. Unlike the one-proportion z-test, which deals with one population, this test is suitable for exercises in population comparison when two distinct groups are involved.

To perform a two-proportion z-test, we must gather independent random samples from both populations. The populations here are defined as residents of coastal states and residents of non-coastal states. The test then calculates a z-score, which indicates how many standard deviations the difference between the two sample proportions lies from zero. A significant z-score suggests that the proportions are different enough to infer a true difference in opinions between the two populations.
Statistical Hypothesis Testing
The overarching framework for both the one-proportion and two-proportion z-tests is statistical hypothesis testing. This method operates on the principles of formulating a null hypothesis (H_0), which states there is no effect or no difference, and an alternative hypothesis (H_A), which states there is a significant effect or difference.

Applying this to our exercises, the null hypothesis for a one-proportion test might posit that the proportion of voters supporting a proposition is equal to 0.5 (indicating no preference), while the alternative hypothesis would suggest that the proportion is different from 0.5. For the two-proportion test, the null hypothesis could assert that the proportions of support for offshore drilling amongst coastal and non-coastal residents are the same, with the alternative hypothesis suggesting they are not. Statistical hypothesis testing includes calculating p-values to assess evidence against the null hypothesis. If the p-value is less than a pre-specified significance level (commonly 0.05), the null hypothesis is rejected in favor of the alternative hypothesis.
Population Comparison
Population comparison is a key concept in statistics used to contrast characteristics, such as averages or proportions, between different groups. Through this comparison, we can understand whether observed differences in sample data are likely reflective of actual differences in the populations.

In the context of the two exercises presented, population comparison involves initially identifying the populations in question. Once identified, statistical tests are used to compare these populations. In scenario 'a', the population is a single group represented by voters in California, while in scenario 'b', two distinct groups are being compared—coastal versus non-coastal residents. When conducting comparisons, it is essential to ensure that comparisons are fair and that samples accurately represent the populations they are drawn from for valid conclusions to be made about the true nature of differences (if any) between populations.

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Most popular questions from this chapter

No-Carb Diet A weight-loss diet claims that it causes weight loss by eliminating carbohydrates (breads and starches) from the diet. To test this claim, researchers randomly assign overweight subjects to two groups. Both groups eat the same amount of calories, but one group eats almost no carbs, and the other group includes carbs in their meals. After 2 months, the researchers test the claim that the no-carb diet is better than the usual diet. They record the proportion of each group that lost more than \(5 \%\) of their initial weight. They then announce that they failed to reject the null hypothesis. Which of the following are valid interpretations of the researchers' findings? a. There were no significant differences in effectiveness between the no-carb diet and the carb diet. b. The no-carb diet and the carb diet were equally effective. c. The researchers did not see enough evidence to conclude that the no-carb diet was more effective. d. The no-carb diet was less effective than the carb diet.

The National Association for Law Placement estimated that \(86.7 \%\) of law school graduates in 2015 found employment. An economist thinks the current employment rate for law school graduates is different from the 2015 rate. Pick the correct pair of hypotheses the economist could use to test this claim. \(\begin{array}{ll}\text { i. } \mathrm{H}_{0}: p \neq 0.867 & \text { ii. } \mathrm{H}_{0}: p=0.867 \\ \mathrm{H}_{\mathrm{a}}: p=0.867 & \mathrm{H}_{\mathrm{a}}: p>0.867 \\ \text { iii. } \mathrm{H}_{0}: p=0.867 & \text { iv. } \mathrm{H}_{0}: p=0.867 \\\ \mathrm{H}_{\mathrm{a}^{\circ}}=p<0.867 & \mathrm{H}_{\mathrm{a}}: p \neq 0.867\end{array}\)

In 2015 a Gallup poll reported that \(52 \%\) of Americans were satisfied with the quality of the environment. In 2018 , a survey of 1024 Americans found that 461 were satisfied with the quality of the environment. Does this survey provide evidence that satisfaction with the quality of the environment among Americans has decreased? Use a \(0.05\) significance level.

Embedded Tutors A college chemistry instructor thinks the use of embedded tutors (tutors who work with students during regular class meeting times) will improve the success rate in introductory chemistry courses. The passing rate for introductory chemistry is \(62 \%\). The instructor will use embedded tutors in all sections of introductory chemistry and record the percentage of students passing the course. State the null and alternative hypotheses in words and in symbols. Use the symbol \(p\) to represent the passing rate for all introductory chemistry courses that use embedded tutors.

Pew Research conducts polls on social media use. In \(2012,66 \%\) of those surveyed reported using Facebook. In 2018 , \(76 \%\) reported using Facebook. a. Assume that both polls used samples of 100 people. Do a test to see whether the proportion of people who reported using Facebook was significantly different in 2012 and 2018 using a \(0.01\) significance level. b. Repeat the problem, now assuming the sample sizes were both 1500 . (The actual survey size in 2018 was \(1785 .\).) c. Comment on the effect of different sample sizes on the p-value and on the conclusion.

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