/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 St. Louis County is \(24 \%\) Af... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

St. Louis County is \(24 \%\) African American. Suppose you are looking at jury pools, each with 200 members, in St. Louis County. The null hypothesis is that the probability of an African American being selected into the jury pool is \(24 \%\). a. How many African Americans would you expect on a jury pool of 200 people if the null hypothesis is true? b. Suppose pool A contains 40 African American people out of 200 , and pool B contains 26 African American people out of 200 . Which will have a smaller p-value and why?

Short Answer

Expert verified
For part a, if the null hypothesis is true we would expect 48 African Americans on a jury pool of 200 people. For part b, Jury Pool B would have a smaller p-value as it deviates more from the expected value under the null hypothesis.

Step by step solution

01

Understand the Null Hypothesis and Calculate Expectation

The null hypothesis states that the selection of an African American into the jury pool is equally likely as their proportion in the population, which is \(24 \%\). With 200 jury members, the expected number of African Americans in the jury pool can be calculated by multiplying the total number of jury members by the proportion of African Americans in the population. Using the formula for expectation \(E(X) = n*p\), where \(n\) is the total number of trials (in this case 200), and \(p\) is the probability of success (in this case \(24 \%\)), we get \(E(X) = 200*0.24 = 48\). Therefore, we would expect 48 African Americans in the jury pool if the null hypothesis is true.
02

Comparing P-values Part A – Understanding Jury Pool A

Jury Pool A contains 40 African Americans out of 200, which is less than the expected 48 if the null hypothesis is true. However, to make any statistical inference about the validity of the null hypothesis, calculations for a p-value would be necessary. This would involve undertaking a formal hypothesis test such as a binomial test. The p-value would represent the probability of 40 or fewer African Americans being selected given the null hypothesis is true. The actual calculation of this value is beyond what has been asked in this question.
03

Comparing P-values Part B – Understanding Jury Pool B

Jury Pool B has 26 African Americans out of 200, which is less than the expected 48 if the null hypothesis is true. As with Pool A, effectively comparing the pools will necessitate the calculation of a p-value. However, the basic understanding is that Pool B, having fewer African Americans than expected under the null hypothesis, will have an even smaller p-value (closer to 0), than Pool A. In layman's terms, it is less 'likely' to observe a jury pool like B (with only 26 African Americans), given the null hypothesis, than it is to observe a jury pool like A (with 40 African Americans).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Value Calculation
To understand the concept of expected value, let's consider an example involving jury selection. The idea is to predict the average outcome if we were to repeat a process several times. In the context of our exercise, we are asked to calculate the expected number of African Americans in a jury pool of 200 people, provided that the population is 24% African American. This is crucial because the expected value serves as a benchmark to decide whether an observed outcome is unusual under the null hypothesis.

Using the formula for expected value, which in probability theory is given by the formula \( E(X) = n*p \), where \( n \) is the sample size and \( p \) is the probability of the event occurring, we can carry out our own calculations. So if the null hypothesis assumes a perfectly proportional representation, we multiply the number of jury members (200) by the proportion (0.24) to predict an average of 48 African Americans in the jury pool. Whenever you come across such problems, remember that the expected value is not a guarantee of what will happen in a single trial, but a long-term average across many trials.
Binomial Test
When dealing with categorical data, like the number of African Americans in a jury pool, we often use the binomial test to evaluate the observed outcomes against the expected outcomes under the null hypothesis. A binomial test compares the number of successes (in this case, selected African Americans) to what we would expect to see by chance. It’s based on the binomial distribution, which is a type of probability distribution with two possible outcomes: success or failure.

In our example, 'success' is selecting an African American for the jury pool. If the null hypothesis is true, with a jury pool of 200, about 48 members should be African American. Any significant deviation from this expected number might suggest a non-random process at play. To complete a binomial test, we would calculate the probability of observing the actually counted African Americans in the jury pool (e.g., 40 in Pool A and 26 in Pool B), which would then generate a p-value to interpret.
P-value Significance
The p-value is a pivotal concept in statistical hypothesis testing. It measures the probability of an observed result (or one more extreme) occurring by random chance if the null hypothesis is true. A smaller p-value indicates that the observed data is less likely to occur under the null hypothesis, hence suggesting that the null hypothesis may not adequately explain the observed data.

In the context of our jury pool, the p-value for Pool A and Pool B would indicate how likely we are to see such a distribution of African American jurors purely by chance. A lower p-value in Pool B compared to Pool A suggests that a pool with 26 African American members (well below the expected 48) is less likely to occur due to random variability alone. This may prompt further investigation into possible reasons beyond chance that explain this discrepancy. The commonly accepted threshold to determine 'statistical significance' is a p-value lower than 0.05, which suggests that the result is unlikely enough under the null hypothesis that it prompts considering alternative explanations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

According to a 2018 survey by Timex reported in Shape magazine, \(73 \%\) of Americans report working out one or more times each week. A nutritionist is interested in whether this percentage has increased. A random sample of 200 Americans found 160 reported working out one or more times each week. Carry out the first two steps of a hypothesis test to determine whether the proportion has increased. Explain how you would fill in the required TI calculator entries for \(p_{0}, x\), and \(n .\)

Suppose we are testing people to see whether the rate of use of seat belts has changed from a previous value of \(88 \%\). Suppose that in our random sample of 500 people we see that 450 have the seat belt fastened. Which of the following figures has the correct p-value for testing the hypothesis that the proportion who use seat belts has changed? Explain your choice.

A Gallup poll asked a random samples of Americans in 2016 and 2018 if they were satisfied with the quality of the environment. In 2016 , 543 were satisfied with the quality of the environment and 440 were dissatisfied. In 2018,461 were satisfied and 532 were dissatisfied. Determine whether the proportion of Americans who are satisfied with the quality of the environment has declined. Use a \(0.05\) significance level.

Student Loans According to a 2016 report from the Institute for College Access and Success \(66 \%\) of all graduates from public colleges and universities had student loans. A public college surveyed a random sample of 400 graduates and found that \(62 \%\) had student loans. a. Test the hypothesis that the percentage of graduates with student loans from this college is different from the national percentage. Use a significance level of \(0.05\). b. After conducting the hypothesis test, a further question one might ask is what proportion of graduates from this college have student loans? Use the sample data to find a \(95 \%\) confidence interval for the proportion of graduates from the college who have student loans. How does this confidence interval support the hypothesis test conclusion?

A hospital readmission is an episode when a patient who has been discharged from a hospital is readmitted again within a certain period. Nationally the readmission rate for patients with pneumonia is \(17 \% .\) A hospital was interested in knowing whether their readmission rate for pneumonia was less than the national percentage. They found 11 patients out of 70 treated for pneumonia in a two-month period were readmitted. a. What is \(\hat{p}\), the sample proportion of readmission? b. Write the null and alternative hypotheses. c. Find the value of the test statistic and explain it in context. d. The p-value associated with this test statistic is \(0.39\). Explain the meaning of the p-value in this context. Based on this result, does the \(\mathrm{p}\) -value indicate the null hypothesis should be doubted?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.