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Suppose it is known that \(60 \%\) of employees at a company use a Flexible Spending Account (FSA) benefit. a. If a random sample of 200 employees is selected, do we expect that exactly \(60 \%\) of the sample uses an FSA? Why or why not? b. Find the standard error for samples of size 200 drawn from this population. What adjustments could be made to the sampling method to produce a sample proportion that is more precise?

Short Answer

Expert verified
It's not expected for exactly \(60 \%\) of a sample of 200 employees to use an FSA due to the natural variability in sampling. The standard error for a sample this size could be calculated using the formula \(\sqrt{p(1-p) / n}\), and to make the sample proportion more precise, increase the sample size.

Step by step solution

01

Understanding Statistical Sampling

When drawing a random sample from a population, every sample drawn will likely contain a different proportion of people that use an FSA. Therefore, it is not expected that exactly \(60 \%\) of a random sample of 200 employees will use an FSA, because of the natural variability involved in random sampling.
02

Calculate the Standard Error

To calculate the standard error of the proportion, use the formula for the standard error of a sample proportion: \(\sqrt{p(1-p) / n}\). Here, \(p\) is the proportion of employees using an FSA, \(60%\), or \(0.60\) in decimal format and \(n\) is the sample size, 200. After substituting these values into the formula, the calculation becomes: \(\sqrt{0.6 * 0.4 / 200}\). This yields the standard error.
03

Adjust Sampling Method for More Precision

To create a more precise sample proportion, the standard error needs to be lowered. According to the formula for the standard error, this can be done by increasing the sample size. Having a larger sample will help to minimize the standard deviation between the samples, leading to a more accurate representation of the population.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Sample Proportion
A sample proportion is a critical way to understand how a particular feature of a subset, or sample, of a population behaves. Imagine you have a huge basket of apples with both red and green ones. If you randomly pick a handful (your sample), and calculate the percentage that are red, that percentage is your sample proportion. It tells you how similar or different the sample is in comparison to the whole group.
In this exercise, there is a belief that 60% of employees in the entire company use a Flexible Spending Account (FSA). When you select a sample of 200 employees, the actual percentage that uses an FSA could be more or less than 60%. This difference happens because of random variations that naturally occur when sampling. It's like picking different handfuls of apples, where you might get slightly different percentages each time. These variations mean that though you aim for a 60% proportion, it's not guaranteed in every sample you draw.
The Role of Standard Error
The standard error plays a crucial role when you assess the reliability of your sample proportion. It reflects the average distance, or deviation, between the actual sample proportion and the true proportion of the entire population.
To calculate this for a sample proportion, you can use the formula: \[\sqrt{\frac{p(1-p)}{n}}\]Here, \(p\) is the true proportion of the population using an FSA, and \(n\) is the sample size. In the given exercise, this turns into: \[\sqrt{\frac{0.6 \times 0.4}{200}}\]Using this calculation gives you an understanding of how much random variability you should expect, helping you see how accurately your sample proportion might reflect the true population.
  • Smaller standard errors indicate that your sample proportion is likely close to the actual proportion of the whole population.
  • Larger standard errors suggest more variability and less precision.
Importance of Random Sampling
Random sampling is the method that ensures every individual in the broader population has an equal chance of being selected. This fairness is important because it helps guarantee that the sample represents the whole group accurately.
If we go back to our basket of apples analogy, imagine mixing up the apples thoroughly before picking them out. Doing this means any handful, or sample, will likely have a mix that's similar to the make-up of the entire basket.
  • Random sampling prevents any biases from sneaking into your sample, ensuring that your results are as reliable and true to the entire population as possible.
  • Without random sampling, you might end up with a skewed sample that doesn't accurately represent the population, leading to incorrect conclusions.
Random sampling makes sure that the findings are valid and can be trusted when forecasting population traits or behaviors.
Determining an Adequate Sample Size
Sample size is a key element in reducing the standard error and increasing the precision of your study findings. The larger your sample size, the more closely your sample proportion will mirror the true proportion of the population.
If you increase the number of employees sampled from 200 to a larger number, you'll reduce the margin of error. This is because the formula for standard error is inversely related to sample size:\[\text{Standard Error} = \sqrt{\frac{p(1-p)}{n}}\]
  • Doubling the sample size will significantly cut the standard error, leading to more accurate approximations.
  • It provides a more reliable shot at understanding how the population truly behaves, helping you make better predictions or business decisions based on your results.
However, larger samples can often require more resources and time, so it's a balance between precision and practicality.

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Most popular questions from this chapter

A 2017 Gallup poll reported that 658 out of 1028 U.S. adults believe that marijuana should be legalized. When Gallup first polled U.S. adults about this subject in 1969 , only \(12 \%\) supported legalization. Assume the conditions for using the CLT are met. a. Find and interpret a \(99 \%\) confidence interval for the proportion of U.S. adults in 2017 that believe marijuana should be legalized. b. Find and interpret a \(95 \%\) confidence interval for this population parameter. c. Find the margin of error for each of the confidence intervals found in parts a and \(\mathrm{b}\). d. Without computing it, how would the margin of error of a \(90 \%\) confidence interval compare with the margin of error for the \(95 \%\) and \(99 \%\) intervals? Construct the \(90 \%\) confidence interval to see if your prediction was correct.

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The Centers for Disease Control and Prevention (CDC) conducts an annual Youth Risk Behavior Survey, surveying over 15,000 high school students. The 2015 survey reported that, while cigarette use among high school youth had declined to its lowest levels, \(24 \%\) of those surveyed reported using e-cigarettes. Identify the sample and population. Is the value \(24 \%\) a parameter or a statistic? What symbol would we use for this value?

According to The Washington Post, \(72 \%\) of high school seniors have a driver's license. Suppose we take a random sample of 100 high school seniors and find the proportion who have a driver's license. a. What value should we expect for our sample proportion? b. What is the standard error? c. Use your answers to parts a and \(\mathrm{b}\) to complete this sentence: We expect _____% to have their driver’s license, give or take _____%. d. Suppose we increased the sample size from 100 to 500 . What effect would this have on the standard error? Recalculate the standard error to see if your prediction was correct.

Suppose it is known that \(20 \%\) of students at a certain college participate in a textbook recycling program each semester. a. If a random sample of 50 students is selected, do we expect that exactly \(20 \%\) of the sample participates in the textbook recycling program? Why or why not? b. Suppose we take a sample of 500 students and find the sample proportion participating in the recycling program. Which sample proportion do you think is more likely to be closer to \(20 \%\) : the proportion from a sample size of 50 or the proportion from a sample size of \(500 ?\) Explain your reasoning.

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