/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 107 From Formula 7.2, an estimate fo... [FREE SOLUTION] | 91Ó°ÊÓ

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From Formula 7.2, an estimate for margin of error for a \(95 \%\) confidence interval is \(m=2 \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\) where \(\mathrm{n}\) is the required sample size and \(\hat{p}\) is the sample proportion. Since we do not know a value for \(\hat{p}\), we use a conservative estimate of \(0.50\) for \(\hat{p}\). Replace \(\hat{p}\) with \(0.50\) in the formula and simplify.

Short Answer

Expert verified
After substituting \( \hat{p} \) with 0.50 into the formula for calculating the margin of error, and subsequent simplification, we get \( m = \sqrt{\frac{1.0}{n}} \).

Step by step solution

01

Identify and substitute

From the problem, we know the formula for margin of error \( m \) is \( m = 2 \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \) and that \( \hat{p} \) needs to be replaced with 0.50. After replacing \( \hat{p} \) the new formula now reads, \( m = 2 \sqrt{\frac{0.50(1 - 0.50)}{n}} \).
02

Simplify the fraction inside the square root

Simplifying inside the square root gives \( m = 2 \sqrt{\frac{0.50(0.50)}{n}} \) which reduces to \( m = 2 \sqrt{\frac{0.25}{n}} \).
03

Simplify further

By multiplying the square root by 2, we get the final simplified form of the formula: \( m = \sqrt{\frac{1.0}{n}} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
Understanding the confidence interval is crucial for interpreting the results of statistical tests. The confidence interval provides a range of values that, with a certain degree of confidence, is believed to encompass the true population parameter. Detracting from the textbook solution where the focus is on the formula for margin of error, the confidence interval consists of two parts: the point estimate and the margin of error.

For a 95% confidence level, which is common in many social sciences, we can say that if we were to take numerous samples and compute their confidence intervals, approximately 95 out of 100 of these intervals would contain the true population proportion. This does not mean that there is a 95% probability that the confidence interval calculated from a single sample contains the true parameter, but rather that 95% of such calculated intervals from repeated samples will, in the long run, contain the parameter.

Sample Proportion
The sample proportion, symbolized by \( \hat{p} \), plays a vital role in statistics as it is a point estimate of the population proportion. It's calculated by dividing the number of successes or favorable outcomes in your sample by the total number of observations.

For instance, if you're trying to determine the proportion of left-handed students in a school, and you sample 50 students out of which 10 are left-handed, your sample proportion \( \hat{p} \) would be 0.20 or 20%. This estimation can be used to infer about the entire population of the school. However, without a true value of \( \hat{p} \), calculating the margin of error can be tricky, which is why we often use the most conservative estimate, 0.50, as it maximizes the product \( \hat{p}(1-\hat{p}) \) and therefore the margin of error, ensuring the sample size is large enough for a valid approximation of the population proportion.

Sample Size Calculation
The process of determining the number of observations needed in a sample to estimate a certain parameter with a specified level of confidence and margin of error is known as sample size calculation. It hinges heavily on the margin of error formula presented in the exercise. To reach a meaningful conclusion without excessive or insufficient data, calculating the right sample size is imperative.

As seen with the simplified margin of error formula, \( m = \sqrt{\frac{1.0}{n}} \), the sample size \( n \) is inversely proportional to the square of the margin of error. This means that to achieve a smaller margin of error, a larger sample size is needed. In practice, a researcher decides the acceptable margin of error and the level of confidence needed, and uses these values to calculate the minimum sample size required for the study. For example, with a desired margin of error of 0.05 and using a conservative estimate for \( \hat{p} \), the sample size calculation will ensure that the resulting confidence interval has the width that the researcher is willing to accept in order to make informed decisions.

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Most popular questions from this chapter

Suppose you attend a school that offers both traditional courses and online courses. You want to know the average age of all the students. You walk around campus asking those students that you meet how old they are. Would this result in an unbiased sample?

Assume your class has 30 students and you want a random sample of 10 of them. A student suggests asking each student to flip a coin, and if the coin comes up heads, then he or she is in your sample. Explain why this is not a good method.

Has trust in the legislative branch of government declined? A Gallup poll asked U.S. adults if they trusted the legislative branch of government in 2008 and again in 2017 . The results are shown in the table. $$ \begin{array}{|l|r|} \hline & \mathbf{2 0 0 8} & \mathbf{2 0 1 7} \\ \hline \text { Yes } & 399 & 358 \\ \hline \text { No } & 623 & 664 \\ \hline \text { Total } & 1022 & 1022 \\ \hline \end{array} $$ a. Find and compare the sample proportion for those who trusted the legislative branch in 2008 and in 2017 . b. Find the \(95 \%\) confidence interval for the difference in the population proportions. Assume the conditions for using the confidence interval are met. Based on the interval, has there been a change in the proportion of U.S. adults who trust the legislative branch? Explain.

Pew Research reported that \(46 \%\) of Americans surveyed in 2016 got their news from local television. A similar survey conducted in 2017 found that \(37 \%\) of Americans got their news from local television. Assume the sample size for each poll was 1200 . a. Construct the \(95 \%\) confidence interval for the difference in the proportions of Americans who get their news from local television in 2016 and 2017 . b. Based on your interval, do you think there has been a change in the proportion of Americans who get their news from local television? Explain.

In 2018 Gallup reported that \(52 \%\) of Americans are dissatisfied with the quality of the environment in the United States. This was based on a \(95 \%\) confidence interval with a margin of error of 4 percentage points. Assume the conditions for constructing the confidence interval are met. a. Report and interpret the confidence interval for the population proportion that are dissatisfied with the quality of the environment in the United States in 2018 . b. If the sample size were larger and the sample proportion stayed the same, would the resulting interval be wider or narrower than the one obtained in part a? c. If the confidence level were \(90 \%\) rather than \(95 \%\) and the sample proportion stayed the same, would the interval be wider or narrower than the one obtained in part a? d. In 2018 the population of the United States was roughly 327 million. If the population had been half that size, would this have changed any of the confidence intervals constructed in this problem? In other words, if the conditions for constructing a confidence interval are met, does the population size have any effect on the width of the interval?

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