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If you walked around your school campus and asked people you met how many keys they were carrying, would you be obtaining a random sample? Explain.

Short Answer

Expert verified
No, this is not a random sample. While some people on the campus are being asked, others are not given the opportunity; therefore, not everyone has an equal chance of being selected.

Step by step solution

01

Identifying the population

In this case, the population would be all the people in the school campus. This includes students, teachers, staff, and possibly visitors.
02

Analyzing the sampling method

Here, the method being used is physically walking around the school and asking people met along the way about the number of keys they carry. There could be a potential bias in this sampling method as it is not guaranteed that each person in school has an equal chance of being inquired. For instance, those who do not go outside much, like office workers or certain students, may have less chance to be asked.
03

Determine if the sampling is random

With the sampling method described, it's clear that not everyone in the school campus has an equal opportunity of being selected. Therefore, this is not a random sampling method.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sampling Method
The sampling method is a crucial aspect of any statistical study, as it is the technique used to select individual members from a larger population to participate in a survey or experiment. When conducting a sample survey, it's essential that every individual in the full population has an equal chance of being chosen; this ensures that the sample accurately reflects the larger group.

In the context of the exercise, the sampling method involves walking around the school campus and asking people the number of keys they're carrying. This approach seems simple and straightforward, but upon closer evaluation, we can see it's not truly random. Not all potential participants have the same probability of being encountered and surveyed, leading to what is known as sampling bias鈥攚hich will be discussed in more detail in a subsequent section.

To improve upon this sampling method, a more systematic approach could be used, such as random number generation to select participants from a list of all people on campus or a stratified sampling method where different groups (students, teachers, staff) are sampled proportionally according to their size within the population.
Population in Statistics
The term 'population' in statistics refers to the entire pool from which a statistical sample is drawn. Essentially, it is the whole set of individuals or items that are the focus of a statistical analysis. For any given survey or experiment, the population should be clearly defined from the outset, as it determines the scope and relevance of the findings.

In the classroom example, the population isn't just the students, but rather everyone present on the school campus, including teachers, staff, and potentially visitors. It's important for the purpose of statistical accuracy that this population is correctly identified and understood since it represents the total group that the sample outcomes will be generalized to.

For students and researchers conducting statistical sampling, understanding the composition of their population helps to ensure that they select a sample that's truly representative, otherwise, the results may be skewed. Hence, the exact definition and comprehensive understanding of the population are fundamental to any statistical research.
Sampling Bias
Sampling bias occurs when the process used to select a sample causes it to be unrepresentative of the population from which it was drawn. This can happen when some members of the population are less likely to be included in the sample due to the sampling technique used.

In the school example, sampling bias is introduced because the sample would likely exclude individuals who are not frequently in areas where they could easily be approached. This includes people who stay indoors most of the time, such as some staff members or students who are in classes during the stroll. The consequence of sampling bias is that it can distort the data and lead to incorrect inferences about the population, as certain perspectives or characteristics might be over-or underrepresented.

To reduce sampling bias, alternative sampling methods such as using a computer-generated list of individuals to contact, or conducting the survey at various times and locations on campus, could be considered. This way, each member of the population would have a more equal chance to be included in the sample, leading to more reliable and valid results.

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Most popular questions from this chapter

A large collection of one-digit random numbers should have about \(50 \%\) odd and \(50 \%\) even digits, because five of the ten digits are odd \((1,3,5,7\), and 9\()\) and five are even \((0,2,4,6\), and 8\()\). a. Find the proportion of odd-numbered digits in the following lines from a random number table. Count carefully. $$ \begin{array}{lll} 57.283 \mathrm{pt} & 74834 & 81172 \\ \hline 89281 & 48134 & 71185 \end{array} $$ b. Does the proportion found in part a represent \(\hat{p}\) (the sample proportion) or \(p\) (the population proportion)? c. Find the error in this estimate, the difference between \(\hat{p}\) and \(p\) (or \(\hat{p}-p)\).

According to a 2017 survey conducted by Netflix, \(46 \%\) of couples have admitted to "cheating" on their significant other by streaming a TV show ahead of their partner. Suppose a random sample of 80 Netflix subscribers is selected. a. What percentage of the sample would we expect have "cheated" on their partner? b. Verify that the conditions for the Central Limit Theorem are met. c. What is the standard error for this sample proportion? d. Complete the sentence: We expect _____% of streaming couples to admit to Netflix 鈥渃heating,鈥 give or take _____%.

The Perry Preschool Project was created in the early \(1960 \mathrm{~s}\) by David Weikart in Ypsilanti, Michigan. In this project, 123 African American children were randomly assigned to one of two groups: One group enrolled in the Perry Preschool, and the other group did not. Follow-up studies were done for decades. One research question was whether attendance at preschool had an effect on high school graduation. The table shows whether the students graduated from regular high school or not and includes both boys and girls (Schweinhart et al. 2005 ). Find a \(95 \%\) confidence interval for the difference in proportions, and interpret it. $$ \begin{array}{|lcc|} \hline & \text { Preschool } & \text { No Preschool } \\ \hline \text { Grad HS } & 37 & 29 \\ \hline \text { No Grad HS } & 20 & 35 \\ \hline \end{array} $$

According to a Gallup poll, \(45 \%\) of Americans actively seek out organic foods when shopping. Suppose a random sample of 500 Americans is selected and the proportion who actively seek out organic foods is recorded. a. What value should we expect for the sample proportion? b. What is the standard error? c. Use your answers to parts a and b to complete this sentence: We expect _____% of Americans to actively seek out organic foods when shopping, give or take _____%. d. Would it be surprising to find a sample proportion of \(55 \% ?\) Why or why not? e. What effect would decreasing the sample size from 500 to 100 have on the standard error?

A 2017 Gallup poll reported that 658 out of 1028 U.S. adults believe that marijuana should be legalized. When Gallup first polled U.S. adults about this subject in 1969 , only \(12 \%\) supported legalization. Assume the conditions for using the CLT are met. a. Find and interpret a \(99 \%\) confidence interval for the proportion of U.S. adults in 2017 that believe marijuana should be legalized. b. Find and interpret a \(95 \%\) confidence interval for this population parameter. c. Find the margin of error for each of the confidence intervals found in parts a and \(\mathrm{b}\). d. Without computing it, how would the margin of error of a \(90 \%\) confidence interval compare with the margin of error for the \(95 \%\) and \(99 \%\) intervals? Construct the \(90 \%\) confidence interval to see if your prediction was correct.

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