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A study of human body temperatures using healthy women showed a mean of \(98.4^{\circ} \mathrm{F}\) and a standard deviation of about \(0.70^{\circ} \mathrm{F}\). Assume the temperatures are approximately Normally distributed. a. Find the percentage of healthy women with temperatures below \(98.6^{\circ} \mathrm{F}\) (this temperature was considered typical for many decades). b. What temperature does a healthy woman have if her temperature is at the 76 th percentile?

Short Answer

Expert verified
Part a: The percentage of healthy women with temperatures below 98.6°F needs to be looked up in the Z-table, after calculating the z-score for 98.6°F. Part b: The temperature corresponding to the 76th percentile is calculated by first determining the z-score for the 76th percentile from the Z-table, and then converting that z-score to an actual temperature using the given mean and standard deviation.

Step by step solution

01

Find the Z-Score for 98.6°F

Use the formula for the z-score, Z = (X - μ) / σ, where X = 98.6°F (temperature to analyze), μ = 98.4°F (provided mean), and σ = 0.70°F (provided standard deviation). So, Z = (98.6 - 98.4) / 0.70.
02

Find the Probability/Percentage

Now that you have the z-score, you can find the percentage of women with temperatures below 98.6°F by looking up this z-score in the Z-table. The value you find in the table will be the percentage.
03

Determine the Z-score for the 76th Percentile

Now, for part b, we first need to find the z-score corresponding to the 76th percentile from the Z-table. This is the reverse process of what we did in step 2. The 76th percentile essentially means that 76% of data points lie below this point in a normal distribution.
04

Convert the Z-Score to the Actual Temperature

Once you have the z-score for the 76th percentile, you need to convert it back to the actual temperature. For this, rearrange the z-score formula to solve for X: X = Z * σ + μ. Use your given z-score, σ = 0.70°F, and μ = 98.4°F to find the temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score Calculation
Understanding z-scores is crucial for interpreting data in relation to a normal distribution. A z-score, also known as a standard score, indicates how many standard deviations an element is from the mean. The formula for calculating a z-score is given by:
\[ Z = \frac{ (X - \mu) }{ \sigma } \]
where \( X \) represents the value in question, \( \mu \) is the mean of the distribution, and \( \sigma \) is the standard deviation. In practical application, such as the temperature study, with a body temperature of \( 98.6^\circ F \), a mean temperature of \( 98.4^\circ F \), and a standard deviation of \( 0.70^\circ F \), the z-score would be calculated using the provided data:
\[ Z = \frac{ (98.6 - 98.4) }{ 0.70 } \]
This value then helps in determining how far away the observed temperature is from what's typical within the group of healthy women. A positive z-score indicates a value above the mean, while a negative z-score signifies a value below the mean.

Significance of Z-scores

Z-scores are not only important in indicating the position of an individual data point but are also used in various statistical tests and confidence intervals. They are the backbone for understanding the probability of occurrences within a standard normal distribution.
Probability and Percentages in Statistics
When working with normally distributed data, the concept of probability and percentages is pivotal. Probability, in the context of a normal distribution, expresses the likelihood of a random variable falling within a particular range. Meanwhile, percentages help us convey this probability in a more intuitive way.

After calculating the z-score, the next step often involves using a z-table (also referred to as a standard normal distribution table) to find the corresponding probability. This table shows the probability of a random variable falling between the mean and any z-score within a normal distribution. To convert this to a percentage, you can simply multiply the probability by 100.

For example, if you find a probability of 0.75 from the z-table for a particular z-score, this translates to a 75% chance that the randomly selected value lies between the mean and that z-score. Deciphering such tables and converting probabilities to percentages enables statisticians and data analysts to make predictions and decisions based on the distribution of the data.

Practical Application

In exercise (a) from the original problem, the z-score helps determine the percentage of women with temperatures below \( 98.6^\circ F \). By referring to the z-table with the calculated z-score, we obtain the percentage which represents the probability of finding a woman with a lower temperature—a foundational concept for statistical analysis in various fields.
Percentiles in Statistics
Percentiles are integral to the field of statistics, offering a way to understand and describe the relative standing of a value within a data set. By definition, the k-th percentile is a value below which k percent of observations in a given distribution fall. This concept allows us to compare individual scores to a broader data set.

In a normal distribution, each percentile corresponds to a unique z-score. For instance, the median (50th percentile) has a z-score of 0 because it's precisely at the mean. To find the z-score associated with any other percentile, you can use statistical tables or software designed for this purpose.

Once you have this z-score, you can convert it into the actual value you are looking for by manipulating the z-score formula as mentioned in the original problem's step 4:
\[ X = Z \cdot \sigma + \mu \]
For example, to find the temperature corresponding to the 76th percentile in a given dataset, we start with the z-score associated with that percentile. Using the mean and standard deviation of the data, we can find the exact temperature value. This enables us to say, with a certain degree of confidence, that 76% of temperatures in our data set are below this value, and 24% are above. This is a powerful statistical tool used across research, business, and healthcare industries to make informed decisions based on the distribution of data.

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Most popular questions from this chapter

The distribution of white blood cell count per cubic millimeter of whole blood is approximately Normal with mean 7500 and standard deviation 1750 for healthy patients. Use technology or a table to answer these questions. For each include an appropriately labeled and shaded Normal curve. a. What is the probability that a randomly selected person will have a white blood cell count between 6000 and 10,000 ? b. An elevated white blood cell count can be a sign of infection somewhere in the body. A white blood cell count can be considered elevated if it is over 10,500 . What percentage of people have white blood cell counts in this elevated range? c. A white blood cell count below 4500 is considered low. People in this range may be referred for additional medical testing. What is the probability that a randomly selected person has a white blood cell count below 4500 ?

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