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A study of human body temperatures using healthy men showed a mean of \(98.1{ }^{\circ} \mathrm{F}\) and a standard deviation of \(0.70{ }^{\circ} \mathrm{F}\). Assume the temperatures are approximately Normally distributed. a. Find the percentage of healthy men with temperatures below \(98.6^{\circ} \mathrm{F}\) (that temperature was considered typical for many decades). b. What temperature does a healthy man have if his temperature is at the 76th percentile?

Short Answer

Expert verified
a: The percentage of healthy men with temperatures below 98.6 degrees Fahrenheit can be found in step 2. b: The temperature at the 76th percentile can be found in step 4.

Step by step solution

01

Calculate Z-Score for Part a

The formula for Z-Score: \(Z = \frac{(X - \mu)}{\sigma}\), where X is the value from the dataset, \(\mu\) is the mean and \(\sigma\) is the standard deviation. Substituting the given values: \(Z = \frac{(98.6 - 98.1)}{0.70}\)
02

Find the Percentage for Part a

Look up the Z-score obtained in step 1 on the standard normal distribution table (or use a calculator with a normal distribution function) to find the percentage of men with temperatures below 98.6 degrees Fahrenheit.
03

Find Z-score for 76th Percentile for Part b

The 76th percentile corresponds to a cumulative probability of 0.76. Look up this probability in the Z-table to find the associated z-score.
04

Find Temperature for the 76th Percentile

Use the formula: \(X = Z \cdot \sigma + \mu\) and substitute the z-score obtained in step 3, the given standard deviation (0.70) and mean (98.1). The final result will be the temperature at the 76th percentile.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-Score Calculation
The Z-score is a statistical measurement that describes a value's relationship to the mean of a group of values. It is a way to determine how many standard deviations an element is from the mean. To calculate the Z-score, use the formula: \[ Z = \frac{(X - \mu)}{\sigma} \] Here, \( X \) is the value from the dataset, \( \mu \) is the mean, and \( \sigma \) is the standard deviation. The Z-score helps us understand the likelihood of a given temperature occurring under normal distribution. It effectively standardizes raw scores, enabling the comparison between different data sets or distributions.
  • For example, if we have a body temperature of \( 98.6^{\circ} \mathrm{F} \), mean \( \mu \) of \( 98.1^{\circ} \mathrm{F} \), and standard deviation \( \sigma \) of \( 0.70^{\circ} \mathrm{F} \). You plug these into the formula and calculate the Z-score: \[ Z = \frac{(98.6 - 98.1)}{0.70} \]
This Z-score value can then be used to find the percentile or probability of this temperature within the normal distribution.
Percentile
A percentile is a measure used in statistics indicating the value below which a given percentage of observations fall. In the context of standardized tests or normal distributions, it tells us about the rank of a particular score. If a score is at the 76th percentile, it means that 76 percent of all other scores in the distribution are lower. Using the Z-score and the Z-table are essential steps in finding percentiles:
  • Look up the cumulative probability corresponding to a Z-score in the Z-table. This gives you the percentile rank of a certain score.
  • For example, to find out what temperature corresponds to the 76th percentile, we look up the Z-score for 0.76 (cumulative probability) in a Z-table. This process shows how our value stands in comparison to others in our dataset.
By understanding percentiles, we can effectively analyze data sets by determining how a specific value compares to the distribution as a whole.
Standard Deviation
Standard deviation is a measure of the amount of variation or dispersion in a set of values. A low standard deviation means the data points tend to be close to the mean of the data set, while a high standard deviation means the data points are spread out over a wider range of values. In the context of normal distributions, the standard deviation helps determine the spread of data around the mean. It is crucial for calculating Z-scores and percentiles as it reflects the expected variability of data values:
  • Standard deviation \( \sigma \) can be calculated from the data points but is often provided, as in our exercise, where \( \sigma = 0.70^{\circ} \mathrm{F} \).
The standard deviation is what transforms raw scores into Z-scores via the Z-score formula. Understanding how the standard deviation affects the normal distribution allows for deeper insight into analyzing different probabilistic scenarios or evaluating the variability observed in the dataset.

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Most popular questions from this chapter

Babies in the United States have a mean birth length of \(20.5\) inches with a standard deviation of \(0.90\) inch. The shape of the distribution of birth lengths is approximately Normal. a. How long is a baby born at the 20 th percentile? b. How long is a baby born at the 50 th percentile? c. How does your answer to part b compare to the mean birth length? Why should you have expected this?

The Empirical Rule applies rough approximations to probabilities for any unimodal, symmetric distribution. But for the Normal distribution we can be more precise. Use the figure and the fact that the Normal curve is symmetric to answer the questions. Do not use a Normal table or technology. According to the Empirical Rule, a. Roughly what percentage of \(z\) -scores are between \(-2\) and 2 ? i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) b. Roughly what percentage of \(z\) -scores are between \(-3\) and 3 ? i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) c. Roughly what percentage of \(z\) -scores are between \(-1\) and 1 . i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) d. Roughly what percentage of \(z\) -scores are greater than 0 ? i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) e. Roughly what percentage of \(z\) -scores are between 1 and 2 ? i. almost all iii. \(50 \%\) ii. \(13.5 \%\) iv. \(2 \%\)

Use the table or technology to find the answer to each question. Include an appropriately labeled sketch of the Normal curve for each part. Shade the appropriate region. A section of the Normal table is provided. a. Find the area in a Standard Normal curve to the left of \(1.13\). b. Find the area in a Standard Normal curve to the right of \(1.13\).

The weight of newborn hippopotami is approximately Normal, with a mean of 88 pounds and a standard deviation of 10 pounds. a. What is the probability that a newborn hippo weighs between 90 and 110 pounds? b. Suppose baby hippos that weigh at the 5 th percentile or less at birth are unlikely to survive. What weight corresponds with the 5 th percentile for newborn hippos? c. Fiona the Hippo was born at the Cincinnati Zoo in 2017,6 weeks premature, and weighed only 29 pounds at birth. What percentage of baby hippos are born weighing 29 pounds or less?

According to the 2017 SAT Suite of Assessments Annual Report, the average SAT math score for students in Illinois was \(556 .\) Assume the scores are Normally distributed with a standard deviation of 100 . Answer the following including an appropriately labeled and shaded Normal curve for each question. a. What percentage of Illinois Math SAT takers scored 600 or more? b. What percentage of Illinois Math SAT takers scored between 600 and 650 ? c. Suppose students who scored in the top \(5 \%\) of test takers in the state were eligible for a special scholarship program. What SAT math score would qualify students for this scholarship program?

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