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Babies in the United States have a mean birth length of \(20.5\) inches with a standard deviation of \(0.90\) inch. The shape of the distribution of birth lengths is approximately Normal. a. Find the birth length at the \(2.5\) th percentile. b, Find the birth length at the \(97.5\) th percentile. c. Find the \(z\) -score for the length at the \(2.5\) th percentile. d. Find the \(z\) -score for the length at the \(97.5\) th percentile.

Short Answer

Expert verified
a. The birth length at the 2.5th percentile is approximately 18.236 inches. b. The birth length at the 97.5th percentile is approximately 22.764 inches. c. The z-score for the length at the 2.5th percentile is -1.96. d. The z-score for the length at the 97.5th percentile is 1.96.

Step by step solution

01

Find the Birth Length at 2.5th Percentile

To find the birth length at the 2.5th percentile, we first find the corresponding z -score in a standardized normal distribution table that correlates with 2.5%. The z-score for 2.5% is roughly -1.96. We then use the equation \(X = Zσ + μ\), where X is the value we seek, Z is the z-score, σ is standard deviation and μ is the mean. So, \(X = -1.96(0.9) + 20.5\), we get \(X ≈ 18.236\).
02

Find the Birth Length at 97.5th Percentile

Similarly as in Step 1, first find the corresponding z -score in a standardized normal distribution table that correlates with 97.5%. The z -score for 97.5% is roughly 1.96. Using the same equation \(X = Zσ + μ\), with Z = 1.96, σ = 0.9 and μ = 20.5, we get \(X ≈ 22.764\).
03

Find the Z-Score for Length at 2.5th percentile

The z score we found for the 2.5th percentile in Step 1 is -1.96. This is what we plug into the formula to get the birth length, so the z score for the 2.5th percentile is -1.96.
04

Find the Z-Score for Length at 97.5th percentile

Similarly as in Step 3, the z score we found for the 97.5th percentile in Step 2 is 1.96. This is what we plug into the formula to get the birth length, so the z score for the 97.5th percentile is 1.96.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Percentiles
Percentiles are a way of understanding the relative standing of a value within a dataset. If a value is at a certain percentile, it means that it is larger than that percentage of the values in the dataset. For instance, saying a birth length is at the 2.5th percentile means that only 2.5% of the birth lengths are shorter than this value.
Percentiles help us understand where a particular observation stands in a statistical distribution. They are especially useful in conjunction with normal distribution, where values are evenly spread around the mean. To find a specific percentile in a normal distribution, we often look up its corresponding z-score. This z-score helps us translate our percentile into a real-life measurement like birth length.
Z-score
A z-score measures how many standard deviations an element is from the mean of the dataset. It standardizes scores on different scales to a common scale with a mean of zero and a standard deviation of one. This is very helpful when comparing data that are from different units or scales.
The formula for a z-score is:
  • \( Z = \frac{X - μ}{σ} \)
Where:
  • \(X\) is the value of the variable.
  • \(μ\) is the mean of the data.
  • \(σ\) is the standard deviation of the data.
When finding a specific percentile in a normal distribution, we first identify the z-score and then use it to calculate the actual value using the equation \( X = Zσ + μ \). This transformation helps us relate the z-score directly to our original dataset, like converting a z-score into a birth length.
Standard Deviation
Standard deviation is a measure that quantifies the amount of variation or dispersion of a set of data values. A low standard deviation means that most of the data points tend to be close to the mean, whereas a high standard deviation indicates that the data points are spread out over a wider range.
In the context of our exercise, the standard deviation is used to calculate the actual birth length from the z-score. The formula \( X = Zσ + μ \) highlights this relationship. Here, it helps adjust our mean birth length by the z-score times the standard deviation, giving us the birth length at any given percentile.
Birth Length
Birth length refers to the measurement from the top of a newborn's head to the heel of their foot. It is an important indicator of a newborn's growth and development patterns.
In the exercise, the birth lengths are normally distributed with a mean of 20.5 inches and a standard deviation of 0.9 inches. This means most babies in the dataset have birth lengths close to 20.5 inches, allowing for predictions and insights into where a newborn's length falls relative to others. Understanding these measurements in the context of percentiles helps healthcare providers assess whether infants are growing within typical ranges or may require additional monitoring.

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Most popular questions from this chapter

Toronto drivers have been going to small towns in Ontario (Canada) to take the drivers' road test, rather than taking the test in Toronto, because the pass rate in the small towns is \(90 \%\), which is much higher than the pass rate in Toronto. Suppose that every day, 100 people independently take the test in one of these small towns. a. What is the number of people who are expected to pass? b. What is the standard deviation for the number expected to pass? c. After a great many days, according to the Empirical Rule, on about \(95 \%\) of these days the number of people passing the test will be as low as and as high as d. If you found that on one day, 89 out of 100 passed the test, would you consider this to be a very high number?

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According to a 2017 Gallup poll, \(44 \%\) of Americans report they frequently feel stressed. Suppose 200 Americans are randomly sampled. Find the probability of the following: a. Fewer than 80 frequently feel stressed b. At least 90 frequently feel stressed c. Between 80 and 100 frequently feel stressed d. At most 75 frequently feel stressed

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