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Five people were asked how many female first cousins they had and how many male first cousins. The data are shown in the table. Assume the trend is linear, find the correlation, and comment on what it means. $$ \begin{array}{cc} \hline \text { Female } & \text { Male } \\ \hline 2 & 4 \\ \hline 1 & 0 \\ \hline 3 & 2 \\ \hline 5 & 8 \\ \hline 2 & 2 \\ \hline \end{array} $$

Short Answer

Expert verified
The correlation coefficient between the numbers of female and male first cousins is 0.68, which indicates a moderate positive correlation.

Step by step solution

01

Calculate the Mean

First calculate the mean (average) for both data sets. The mean is calculated by summing all the values in a data set, then dividing by the number of values in the data set. For 'Female', the mean is \( (2+1+3+5+2)/5 = 2.6 \); and for 'Male', it's \( (4+0+2+8+2)/5 = 3.2 \)
02

Calculate the Deviations

Next calculate the deviations of each data point from the mean. This is done by subtracting the mean from each data point. Deviations for 'Female' are (2-2.6, 1-2.6, 3-2.6, 5-2.6, 2-2.6) = (-0.6, -1.6, 0.4, 2.4, -0.6), and for 'Male' (4-3.2, 0-3.2, 2-3.2, 8-3.2, 2-3.2) = (0.8, -3.2, -1.2, 4.8, -1.2)
03

Calculate the Sum of Product of Deviations

Next step is to calculate the products of the corresponding deviations and then their sum. Product of deviations are (-0.6*0.8, -1.6*-3.2, 0.4*-1.2, 2.4*4.8, -0.6*-1.2) = (-0.48, 5.12, -0.48, 11.52, 0.72). The sum of these products is -0.48 + 5.12 - 0.48 + 11.52 + 0.72 = 16.4
04

Calculate the Sum of Squares of Deviations

Find the squares of the deviations and sum them for each data set to get \(\Sigma(x_i-\bar{x})^2\) and \(\Sigma(y_i-\bar{y})^2\). For 'Female' they are (0.6^2, 1.6^2, 0.4^2, 2.4^2, 0.6^2) = (0.36, 2.56, 0.16, 5.76, 0.36) and for 'Male' (0.8^2, 3.2^2, 1.2^2, 4.8^2, 1.2^2) = (0.64, 10.24, 1.44, 23.04, 1.44). The sums are 9.2 and 36.8 respectively
05

Calculate the Correlation Coefficient

Substitute these calculated values into the formula of Pearson Correlation Coefficient to get \( r = \frac{16.4}{\sqrt{9.2*36.8}} = 0.68 \)
06

Interpret the Correlation Coefficient

Finally, interpret the correlation coefficient. A coefficient (r) of 0.68 suggests a moderate positive correlation between the number of female and male first cousins. This means that as the number of female first cousins increases, the number of male first cousins also tends to increase, and vice versa

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pearson Correlation Coefficient
The Pearson Correlation Coefficient is a statistical measure that quantifies the strength and direction of a linear relationship between two variables. In simpler terms, it tells us how closely two sets of data are related to each other. This coefficient, often denoted as \( r \), ranges from -1 to +1. A value of +1 indicates a perfect positive relationship, -1 indicates a perfect negative relationship, and 0 suggests no linear relationship at all.

To calculate this coefficient, you must know both the means and the standard deviations of each variable, as well as the covariance between them. The four steps taken in the original example are part of this process. Firstly, you calculate the mean of each set of values. Then, you find the deviation of each value from its mean – which is simply how much each value differs from the average. The third step involves computing the sum of the product of these deviations, which contributes to the numerator of the formula.

Finally, you square the deviations, sum them, and calculate the sums of these squared deviations – also known as the sum of squares. These are vital for the denominator of the Pearson Correlation Coefficient formula. By combining these sums with the sum from the third step, you use the formula \( r = \frac{\text{Sum of Product of Deviations}}{\sqrt{\text{Sum of Squares of Female}*\text{Sum of Squares of Male}}} \), to find the correlation coefficient, which in our case was 0.68, suggesting a moderate positive linear relationship.
Descriptive Statistics
Descriptive statistics are a collection of brief descriptive coefficients that summarize a given data set, which can either be a representation of the entire population or a sample of it. Such statistics are intended to present quantitative descriptions in a manageable form. They include measures of central tendency and measures of variability (spread).

Central tendency includes mean, median, and mode, while variability encompasses standard deviation, variance, range, and percentiles. In the context of the textbook exercise, the mean or average of the female and male cousins count is the starting point for further calculations regarding the correlation.

Understanding these descriptive statistics is crucial because they give you an insight into the standard and behavior of your data before you conduct more complex analysis, such as finding correlation coefficients. These statistics are about describing and summarizing data in a useful and informative manner and are the foundation of most statistical analyses.
Linear Relationship
A linear relationship refers to a direct correlation between two variables when one variable changes as the other does, and this change is consistent and can be graphed as a straight line. Put simply, if you were to plot these two variables against each other on a scatterplot, a linear relationship would imply that the points roughly form a straight line.

Whether this line slopes upward or downward signifies if the relationship is positive or negative, respectively. In our original exercise, assuming the trend is linear means we expect to see a 'line of best fit' that climbs or descends evenly, not one that curves or has a disparate pattern of points.

The Pearson Correlation Coefficient is one way to quantify this kind of relationship. In our example, a Pearson Correlation Coefficient of 0.68 helps us understand that when the number of female first cousins in a family increases, the number of male first cousins also tends to increase in a somewhat proportional and predictable (linear) way, though it's not a perfectly precise one-to-one relationship.

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Most popular questions from this chapter

A doctor is studying cholesterol readings in his patients. After reviewing the cholesterol readings, he calls the patients with the highest cholesterol readings (the top \(5 \%\) of readings in his office) and asks them to come back to discuss cholesterol-lowering methods. When he tests these patients a second time, the average cholesterol readings tend to have gone down somewhat. Explain what statistical phenomenon might have been partly responsible for this lowering of the readings.

In Exercise \(4.1\) there is a graph of the relationship between SAT score and college GPA. SAT score was the predictor and college GPA was the response variable. If you reverse the variables so that college GPA was the predictor and SAT score was the response variable, what effect would this have on the numerical value of the correlation coefficient?

The correlation between house price (in dollars) and area of the house (in square feet) for some houses is 0.91. If you found the correlation between house price in thousands of dollars and area in square feet for the same houses, what would the correlation be?

The distance (in kilometers) and price (in dollars) for one-way airline tickets from San Francisco to several cities are shown in the table. $$\begin{array}{|lcc|} \hline \text { Destination } & \text { Distance (km) } & \text { Price (\$) } \\\ \hline \text { Chicago } & 2960 & 229 \\ \hline \text { New York City } & 4139 & 299 \\ \hline \text { Seattle } & 1094 & 146 \\ \hline \text { Austin } & 2420 & 127 \\ \hline \text { Atlanta } & 3440 & 152 \\ \hline \end{array}$$ a. Find the correlation coefficient for this data using a computer or statistical calculator. Use distance as the \(x\) -variable and price as the \(y\) -variable. b. Recalculate the correlation coefficient for this data using price as the \(x\) -variable and distance as the \(y\) -variable. What effect does this have on the correlation coefficient? c. Suppose a $$\$ 50$$ security fee was added to the price of each ticket. What effect would this have on the correlation coefficient? d. Suppose the airline held an incredible sale, where travelers got a round- trip ticket for the price of a one-way ticket. This means that the distances would be doubled while the ticket price remained the same. What effect would this have on the correlation coefficient?

The table shows the heights (in inches) and weights (in pounds) of 14 college men. The scatterplot shows that the association is linear enough to proceed. $$ \begin{array}{c|c|c|c|} \hline \begin{array}{c} \text { Height } \\ \text { (inches) } \end{array} & \begin{array}{c} \text { Weight } \\ \text { (pounds) } \end{array} & \begin{array}{c} \text { Height } \\ \text { (inches) } \end{array} & \begin{array}{c} \text { Weight } \\ \text { (pounds) } \end{array} \\ \hline 68 & 205 & 70 & 200 \\ \hline 68 & 168 & 69 & 175 \\ \hline 74 & 230 & 72 & 210 \\ \hline 68 & 190 & 72 & 205 \\ \hline 67 & 185 & 72 & 185 \\ \hline 69 & 190 & 71 & 200 \\ \hline 68 & 165 & 73 & 195 \\ \hline \end{array} $$ a. Find the equation for the regression line with weight (in pounds) as the response and height (in inches) as the predictor. Report the slope and the intercept of the regression line, and explain what they show. If the intercept is not appropriate to report, explain why. b. Find the correlation between weight (in pounds) and height (in inches). c. Find the coefficient of determination and interpret it. d. If you changed each height to centimeters by multiplying heights in inches by \(2.54\), what would the new correlation be? Explain. e. Find the equation with weight (in pounds) as the response and height (in inches) as the predictor, and interpret the slope. f. Summarize what you found: Does changing units change the correlation? Does changing units change the regression equation?

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