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Explain the meaning of the probability distribution of a discrete random variable. Give one example of such a probability distribution.

Short Answer

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A discrete random variable is a variable having a countable number of possible outcomes, with each outcome having a distinct probability. Its probability distribution holds a list of each possible outcome and its associated probability. For example, in the case of a fair die, there are six possible outcomes, each with a probability of \(\frac{1}{6}\).

Step by step solution

01

Explanation of a discrete random variable and its probability distribution

A discrete random variable is a variable that can take on a countable number of distinct values. Each of these values has an associated probability which is uploaded by a function known as the probability mass function. On the other hand, a probability distribution of a discrete random variable is a list that displays all the possible outcomes of a random experiment and the probability of each outcome.
02

Example of a probability distribution of a discrete random variable

For instance, consider a fair six-sided die roll, it is an example of a discrete random variable because it can only take on the countable (and finite) values 1, 2, 3, 4, 5, or 6. Each of these outcomes has an equal probability of \(\frac{1}{6}\). Hence, the probability distribution of this discrete random variable (the die roll) is as follows: {(1, \(\frac{1}{6}\)), (2, \(\frac{1}{6}\)), (3, \(\frac{1}{6}\)), (4, \(\frac{1}{6}\)), (5, \(\frac{1}{6}\)), (6, \(\frac{1}{6}\))}.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discrete Random Variable
A discrete random variable is an integral part of understanding probability distributions. Unlike a continuous random variable, which can take on an infinite number of values, a discrete random variable is limited to a countable set of distinct outcomes. These outcomes can usually be listed, making them well-suited for many practical scenarios in probability and statistics.
Consider the toss of a fair coin, a classic example of a discrete random variable. In this case, the possible values the variable could take are "Heads" and "Tails." These outcomes are clear and distinct, showcasing how a discrete random variable functions.
Whenever you are dealing with scenarios that involve a set of categorical outcomes, or whole numbers, you are likely working with a discrete random variable. Examples beyond coin tosses include rolling dice, drawing cards, and selecting colored balls from a bag. Each has a finite number of possible outcomes, clearly defining them as discrete random variables.
Probability Mass Function
The probability mass function (PMF) is a crucial concept when dealing with discrete random variables. In simple terms, the PMF provides a mechanism to define the probability distribution of a discrete random variable by associating each possible outcome with its probability of occurrence.
The PMF is represented as a function, which can be described mathematically. If X is a discrete random variable, the probability mass function, denoted as \( P(X=x_i) \), gives the probability that X equals a particular value \( x_i \). For example, in a dice roll, the PMF assigns a probability of \( \frac{1}{6} \) to each face of a six-sided die.
With a PMF:
  • The sum of all probabilities is always equal to 1. This ensures that we have accounted for every possible outcome.
  • It provides a compact way to view all potential outcomes and their associated likelihood, serving as a blueprint to calculate other probabilities or expectations related to the random variable.
By understanding the PMF, one can compute probabilities for various scenarios, making it essential for statistical analysis and decision-making.
Probability Distribution Example
One of the simplest examples of a probability distribution is the roll of a standard six-sided die. A probability distribution provides a comprehensive view of all possible outcomes of an event and their corresponding probabilities.
When you roll a die, the possible outcomes are 1, 2, 3, 4, 5, or 6. Assuming it's a fair die, each outcome has an equal probability of occurring: \( \frac{1}{6} \). This set of outcomes paired with their probabilities forms a probability distribution:
  • 1 has a probability of \( \frac{1}{6} \)
  • 2 has a probability of \( \frac{1}{6} \)
  • 3 has a probability of \( \frac{1}{6} \)
  • 4 has a probability of \( \frac{1}{6} \)
  • 5 has a probability of \( \frac{1}{6} \)
  • 6 has a probability of \( \frac{1}{6} \)
Such a distribution is intuitive and straightforward, demonstrating the concept that the sum of all probabilities equals 1. Probability distributions help us predict how a random variable behaves over time, crucial for fields such as game theory, risk assessment, and statistical modeling.

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Most popular questions from this chapter

An average of \(6.3\) robberies occur per day in a large city. a. Using the Poisson formula, find the probability that on a given day exactly 3 robberies will occur in this city. b. Using the appropriate probabilities table from Appendix \(\mathbf{B}\), find the probability that on a given day the number of robberies that will occur in this city is \(\begin{array}{lll}\text { i. at least } 12 & \text { ii. at most } 3 & \text { iii. } 2 \text { to } 6\end{array}\)

A review of emergency room records at rural Millard Fellmore Memorial Hospital was performed to determine the probability distribution of the number of patients entering the emergency room during a 1 -hour period. The following table lists this probability distribution. $$ \begin{array}{l|ccccccc} \hline \begin{array}{l} \text { Patients } \\ \text { per hour } \end{array} & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline \text { Probability } & .2725 & .3543 & .2303 & .0998 & .0324 & .0084 & .0023 \\ \hline \end{array} $$ a. Make a histogram for this probability distribution. b. Determine the probability that the number of patients entering the emergency room during a randomly selected 1 -hour period is i. 2 or more ii. exactly 5 iii. fewer than 3 iv. at most 1

In a group of 12 persons, 3 are left-handed. Let \(x\) denote the number of left-handed persons in 2 randomly selected persons from these 12 persons. The following table lists the probability distribution of \(x\). (Because of rounding, probabilities add to \(1.0001\).) $$ \begin{array}{l|ccc} \hline x & 0 & 1 & 2 \\ \hline P(x) & .5455 & .4091 & .0455 \\ \hline \end{array} $$ Calculate the mean and standard deviation of \(x\) for this distribution.

Briefly explain the following. a. A binomial experiment b. A trial c. A binomial random variable

According to a survey conducted at the local DMV, \(50 \%\) of drivers who drive to work stated that they regularly exceed the posted speed limit on their way to work. Suppose that this result is true for the population of drivers who drive to work. A random sample of 13 drivers who drive to work is selected. Use the binomial probabilities table (Table I of Appendix B) or technology to find the probability that the number of drivers in this sample of 13 who regularly exceed the posted speed limit on their way to work is a. at most 5 b. 6 to 9 c. at least 7

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