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A sample of 2000 observations has a mean of 74 and a standard deviation of \(12 .\) Using Chebyshev's theorem, find the minimum percentage of the observations that fall in the intervals \(\bar{x} \pm 2 s, \bar{x} \pm 2.5 s\), and \(\bar{x} \pm 3 s\). Note that \(\bar{x} \pm 2 s\) represents the interval \(\bar{x}-2 s\) to \(\bar{x}+2 s\), and so on.

Short Answer

Expert verified
According to Chebyshev's theorem a minimum percentage of observations that fall in the intervals \( \bar{x} \pm 2 s\), \( \bar{x} \pm 2.5 s\), and \( \bar{x} \pm 3 s\) are 75%, 84%, and 89% respectively.

Step by step solution

01

Determine the intervals

The three intervals given in the exercise are defined as the mean plus or minus a multiple of the standard deviation. These multiples, 2, 2.5, and 3, become our k values for Chebyshev's theorem.
02

Apply Chebyshev's theorem for k = 2

Apply Chebyshev's theorem by replacing k with 2 in the formula, giving us 1-(1/2^2) = 1 - 0.25 = 0.75 or 75%. This means that a minimum of 75% of the observations fall within the interval \(\bar{x} \pm 2s\).
03

Apply Chebyshev's theorem for k = 2.5

This step is the same as the previous step, but this time with k = 2.5. So, 1-(1/2.5^2) = 1 - 0.16 = 0.84 or 84%. Therefore, a minimum of 84% of the observations will fall within the interval \(\bar{x} \pm 2.5s\).
04

Apply Chebyshev's theorem for k = 3

Finally, for k = 3, we get 1-(1/3^2) = 1 - 0.11 = 0.89 or 89%. Thus, a minimum of 89% of the observations fall within the interval \(\bar{x} \pm 3s\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
The standard deviation is a crucial statistical measure that helps us understand how data points are spread out from the mean in a dataset. It is denoted by the symbol \(s\) and is calculated as the square root of the variance. In simple terms, if the standard deviation is small, the data points tend to be very close to the mean, indicating less variability. Conversely, a large standard deviation suggests that the data points are spread out over a wider range.
In our exercise, the standard deviation is given as 12, which means, on average, the data points in the sample stray from the mean, or central value of 74, by about 12 units. This measure is key in determining the intervals around the mean that encompass a given percentage of observations, especially when using Chebyshev's theorem.
Mean
The mean is often referred to as the average and is a fundamental measure of central tendency in statistics. It is calculated by summing up all data points in a dataset and then dividing by the number of data points.
In our exercise, the mean of the sample of observations is given as 74. This value serves as the center point for our intervals when applying Chebyshev's theorem. Understanding the mean is essential because it provides a baseline from which the standard deviation and statistical intervals are measured.
Statistical Intervals
Statistical intervals are ranges designed to contain a specific portion of data points from a dataset. In the context of Chebyshev's theorem, these intervals are centered around the mean and extend a certain number of standard deviations on either side.
For example, the interval \(\bar{x} \pm 2s\) signifies that data is captured within two standard deviations from the mean. In our exercise, with \(\bar{x} = 74\) and \(s = 12\), this interval translates to \([74 - 2(12), 74 + 2(12)]\), which is [50, 98]. Statistical intervals are very effective in estimating how spread out the data is around the mean without knowing the exact distribution of the data.
Minimum Percentage of Observations
Chebyshev's theorem provides a way to estimate the minimum percentage of observations that lie within given intervals around the mean, regardless of the distribution of data. The theorem states that for any dataset, at least \(1 - \frac{1}{k^2}\) of the data points must lie within \(k\) standard deviations from the mean.
This is powerful because it holds for any data distribution, whether it's a normal distribution or not. In our exercise, we calculated the minimum percentage of data points within the intervals of \(\pm 2s\), \(\pm 2.5s\), and \(\pm 3s\), yielding minimum percentages of 75%, 84%, and 89%, respectively. Understanding this theorem allows analysts to make broad predictions about data distribution without detailed insights into actual data movements.

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Most popular questions from this chapter

The mean time taken to learn the basics of a software program by all students is 200 minutes with a standard deviation of 20 minutes. a. Using Chebyshev's theorem, find the minimum percentage of students who learn the basics of this software program in i. 160 to 240 minutes ii. 140 to 260 minutes *b. Using Chebyshev's theorem, find the interval that contains the times taken by at least \(84 \%\) of all students to learn this software program.

The following data give the speeds of 13 cars (in mph) measured by radar, traveling on I-84. $$ \begin{array}{lllllll} 73 & 75 & 69 & 68 & 78 & 69 & 74 \\ 76 & 72 & 79 & 68 & 77 & 71 & \end{array} $$ a. Find the values of the three quartiles and the interquartile range. b. Calculate the (approximate) value of the 35 th percentile. c. Compute the percentile rank of 71 .

The following data give the total food expenditures (in dollars) for the past one month for a sample of 20 families. \(\begin{array}{rrrrrrrrrr}1125 & 530 & 1234 & 595 & 427 & 872 & 1480 & 699 & 1274 & 1187 \\ 933 & 1127 & 716 & 1065 & 934 & 930 & 1046 & 1199 & 1353 & 441\end{array}\) a. Calculate the mean and median for these data. b. Calculate the \(20 \%\) trimmed mean for these data.

The following data give the annual salaries (in thousand dollars) of 20 randomly selected health care workers. \(\begin{array}{llllllllll}50 & 71 & 57 & 39 & 45 & 64 & 38 & 53 & 35 & 62 \\ 74 & 40 & 67 & 44 & 77 & 61 & 58 & 55 & 64 & 59\end{array}\) a. Calculate the mean, median, and mode for these data. b. Calculate the \(15 \%\) trimmed mean for these data.

The mean monthly mortgage paid by all home owners in a town is \(\$ 2365\) with a standard deviation of \(\$ 340\). a. Using Chebyshev's theorem, find the minimum percentage of all home owners in this town who pay a monthly mortgage of i. \(\$ 1685\) to \(\$ 3045\) ii. \(\$ 1345\) to \(\$ 3385\) "b. Using Chebyshev's theorem, find the interval that contains the monthly mortgage payments of at least \(84 \%\) of all home owners in this town.

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