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The mean monthly mortgage paid by all home owners in a town is \(\$ 2365\) with a standard deviation of \(\$ 340\). a. Using Chebyshev's theorem, find the minimum percentage of all home owners in this town who pay a monthly mortgage of i. \(\$ 1685\) to \(\$ 3045\) ii. \(\$ 1345\) to \(\$ 3385\) "b. Using Chebyshev's theorem, find the interval that contains the monthly mortgage payments of at least \(84 \%\) of all home owners in this town.

Short Answer

Expert verified
a. i. minimum percentage is 75% ii. minimum percentage is 88.9% b. the range is approximately between \$1909.02 and \$2820.98.

Step by step solution

01

Calculation of number of standard deviations for part a

First calculate the number of standard deviations each range is from the mean. Use the formula \[ k = |x - \mu| / \sigma \]. For i. the range is from \$1685 to \$3045, the number of standard deviations from the mean for \$1685 and \$3045 will be \(2\) and \( -2 \) respectively. ii. For the range \$1345 to \$3385, the number of standard deviations from the mean will come out to be \( -3 \) and \(3\) respectively.
02

Applying Chebyshev's theorem for part a

Apply Chebyshev's theorem which gives that at least 1 - 1/k^2 of the distribution's values should be within k standard deviations from the mean. For i. Substitute \(k = 2\) which will give at least \(75 %\). For ii. Substitute \(k = 3\) which will give at least \(88.9 %\).
03

Rearranging Chebyshev's theorem for part b

Part b requires finding the interval that contains the monthly mortgage payments of at least 84% of all home owners. So rearrange Chebyshev's formula to solve for k: \(k = sqrt{1/(1 - p}\), plugging \(p = 0.84\) will give \(k \approx 1.22\).
04

Calculating the range for part b

Use this \(k\) value to calculate the range \[ x = \mu ± k*\sigma \], which comes out to be approximately between \$1909.02 and \$2820.98.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean
The mean is a fundamental statistical measure, often known as the average. It's calculated by adding up all the values in a data set and dividing by the number of values. In this way, the mean provides a central point for the data. In our case of monthly mortgages, the mean is given as \(\\(2365\), which means that when you consider all the homeowners in the town, their average mortgage payment per month is \(\\)2365\). This figure serves as a benchmark for analyzing how individual mortgage payments vary across homeowners.

The mean situates our data and acts as a helpful reference when applying other concepts like standard deviation and Chebyshev's theorem. By understanding the average mortgage, we can better grasp the spread of the data and identify how many homeowners pay significantly more or less than this standard.
Standard Deviation
Standard deviation measures the amount of variation or dispersion in a set of data points. In simpler terms, it tells us how much the individual data points deviate from the mean. For the town's mortgage payments, the standard deviation is \(\\(340\).

A smaller standard deviation means that the values tend to be closer to the mean, while a larger one indicates more spread out data. Here, the mortgage payments vary by about \(\\)340\) from the mean on average. This helps us understand the diversity in mortgage payments among homeowners.
  • Small standard deviation: Data points are closer to the mean
  • Large standard deviation: Data points are more spread out
Understanding standard deviation is crucial when applying Chebyshev's theorem. It allows us to calculate the range around the mean where most of the data points lie.
Probability Distributions
Probability distributions describe how values are distributed across possible outcomes. In the context of our exercise, we're particularly looking at how often mortgage payments fall within certain ranges.

Chebyshev's theorem applies to any data distribution, providing minimum certainty of data falling within a specific range of standard deviations from the mean. It states that at least \(1 - \frac{1}{k^2}\) of data points fall within \(k\) standard deviations of the mean. In the problem, we see this used to estimate the proportion of homeowners that fall within certain payment brackets:

  • For payments between \(\\(1685\) and \(\\)3045\): At least \(75\%\) of homeowners.
  • For payments between \(\\(1345\) and \(\\)3385\): At least \(88.9\%\) of homeowners.
While the probabilities given by Chebyshev’s theorem are quite broad, they are extremely useful for datasets without assuming any specific distribution like normal distribution.
Interval Estimation
Interval estimation involves finding a range of values that likely contain a parameter (like the mean) with a certain level of confidence. In many cases, this could be a confidence interval, but here we're using Chebyshev's theorem to determine the interval for mortgage payments.

In part b of the exercise, we sought the range which contains at least \(84\%\) of all mortgage payments using the theorem. By rearranging the theorem's formula, we determined that \(k ≈ 1.22\). From this, we calculated that the interval is approximately between \(\\(1909.02\) and \(\\)2820.98\).

This range estimation does not particularly depend on a normal distribution, unlike traditional confidence intervals. Instead, it assures us that a certain percentage of values falls within this calculated range regardless of the actual distribution shape. This flexibility makes Chebyshev's theorem valuable for real-world applications, where exact distribution forms aren't always known.

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Most popular questions from this chapter

One property of the mean is that if we know the means and sample sizes of two (or more) data sets, we can calculate the combined mean of both (or all) data sets. The combined mean for two data sets is calculated by using the formula $$ \text { Combined mean }=\bar{x}=\frac{n_{1} \bar{x}_{1}+n_{2} \bar{x}_{2}}{n_{1}+n_{2}} $$ where \(n_{1}\) and \(n_{2}\) are the sample sizes of the two data sets and \(\bar{x}_{1}\) and \(\bar{x}_{2}\) are the means of the two data sets, respectively. Suppose a sample of 10 statistics books gave a mean price of \(\$ 140\) and a sample of 8 mathematics books gave a mean price of \(\$ 160\). Find the combined mean. (Hint: For this example: \(n_{1}=10, n_{2}=8, \bar{x}_{1}=\$ 140, \bar{x}_{2}=\$ 160 .\) )

The following data represent the systolic blood pressure reading (that is, the top number in the standard blood pressure reading) in \(\mathrm{mmHg}\) for each of 20 randomly selected middle-aged males who were taking blood pressure medication. \(\begin{array}{llllllllll}139 & 151 & 138 & 153 & 134 & 136 & 141 & 126 & 109 & 144\end{array}\) \(\begin{array}{llllllllll}111 & 150 & 107 & 132 & 144 & 116 & 159 & 12.1 & 127 & 113\end{array}\) a. Calculate the mean, median, and mode for these data. b. Calculate the \(10 \%\) trimmed mean for these data.

Each year the faculty at Metro Business College chooses 10 members from the current graduating class that they feel are most likely to succeed. The data below give the current annual incomes (in thousand dollars) of the 10 members of the class of 2009 who were voted most likely to succeed. \(\begin{array}{llllllllll}59 & 68 & 84 & 78 & 107 & 382 & 56 & 74 & 97 & 60\end{array}\) a. Determine the values of the three quartiles and the interquartile range. Where does the value of 74 fall in relation to these quartiles? b. Calculate the (approximate) value of the 70 th percentile. Give a brief interpretation of this percentile. c. Find the percentile rank of 97 . Give a brief interpretation of this percentile rank.

Are the values of the mean and standard deviation that are cal- culated using grouped data exact or approximate values of the mean and standard deviation, respectively? Explain.

Briefly explain what summary measures are used to construct a box-and-whisker plot.

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