/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 67 You are working for a bank. The ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

You are working for a bank. The bank manager wants to know the mean waiting time for all customers who visit this bank. She has asked you to estimate this mean by taking a sample. Briefly explain how you will conduct this study. Collect data on the waiting times for 45 customers who visit a bank. Then estimate the population mean. Choose your own confidence level.

Short Answer

Expert verified
To estimate the population mean of the waiting time for customers at the bank, a simple random sample of 45 customers' waiting times will be collected and the sample mean will be calculated. A confidence interval will be constructed around the sample mean at the chosen confidence level (e.g., 95%), indicating that we expect the real (population) mean to lie within this interval 95% of the time.

Step by step solution

01

Define the Objective and Design the Study

The first step is to clearly define the objective of the study. In this case, estimate the mean waiting time for customers in this bank. To conduct the study, you should randomly select 45 customers visiting the bank and record their waiting times. This reduces bias and ensures that the sample is representative of the population.
02

Collect the Data

For each selected customer, start a timer when they arrive at the bank and stop the timer when they finish their transaction. Keep a record of these times for all 45 customers.
03

Calculate Sample Mean

Next, calculate the sample mean (average) of the waiting times. Add up all the waiting times and divide by the total number of customers (45). The formula can be represented as follows: \[ Sample \ mean = \frac{1}{N}\sum_{i=1}^{N} X_{i} \] where \(N\) is the total number of observations and \(X_{i}\) is the waiting time observed for ith customer.
04

Choose Confidence Level and Calculate Confidence Interval

Let's choose a confidence level, for example, 95%. Look up the Z-score corresponding to this confidence level from a standard normal distribution table, which is 1.96 for 95%. The confidence interval is then calculated using the following formula: \[ Confidence \ Interval = Sample \ Mean \pm (Z \times \frac{Standard \ Deviation}{\sqrt{N}}) \] This means that we are 95% confident that the true population mean falls within this interval.
05

Report the Results

Now you can report the estimated population mean with the confidence interval. This gives the bank manager both an estimate of the mean waiting time and an indication of the reliability of the estimate.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean is a crucial concept in statistical estimation. It is simply the average of a set of data points collected from a sample. In this case, you would collect the waiting times for 45 randomly selected customers at the bank. The sample mean offers an estimate of the population mean, serving as a point estimate.

To calculate the sample mean, you add up all of the observed waiting times and divide by the number of customers in your sample, which is 45. Mathematically, it is expressed as:
  • \( Sample \ mean = \frac{1}{N}\sum_{i=1}^{N} X_{i} \)
where \( N \) represents the total number of observations, and \( X_{i} \) signifies each individual waiting time.

The sample mean is important because it provides a summary statistic that represents the center of your data set. However, since the sample is just a subset of the entire population, there will always be some degree of variability or error, which is why we also consider the confidence interval.
Confidence Interval
A confidence interval gives a range of values, derived from the sample, that is likely to contain the population mean. When you calculate the confidence interval, you also set a confidence level, such as 95%, which indicates how confident you are that the interval includes the true mean.

The formula for a confidence interval is as follows:
  • \( Confidence \ Interval = Sample \ Mean \pm (Z \times \frac{Standard \ Deviation}{\sqrt{N}}) \)
Here, the \( Z \) represents the Z-score associated with your chosen confidence level. For a 95% confidence interval, the Z-score is typically 1.96.

This method allows you to understand the reliability of your sample mean. If your confidence interval is small, you feel more certain about the population mean. Conversely, a wide interval indicates more uncertainty.

Reporting a confidence interval alongside the sample mean provides a more complete picture, explaining both your point estimate and the potential error inherent in sampling.
Population Mean
The population mean is what you ultimately seek to estimate in a statistical study like the one described. It is the average of a particular characteristic—in this case, waiting times—across the entire population.

Since it is often impractical or impossible to observe the whole population, we estimate it using our sample data. It is important to remember that while the sample mean gives us an estimate, it is not guaranteed to be exactly equal to the population mean due to potential sampling errors.

The strength of statistical estimation techniques is that they allow you to infer the population mean with an associated level of confidence through both the sample mean and the confidence interval.

Understanding the population mean and its estimation ties directly into making informed decisions. In this scenario, the bank manager can better understand the likely average waiting times for future customers based on your analysis.
Random Sampling
Random sampling is a fundamental method used in statistics to ensure that the sample used in a study is representative of the population. This technique involves selecting individuals based purely on chance, reducing bias in your data collection process.

In the bank scenario, random sampling helps ensure that the waiting times you record from 45 customers are as reflective of the overall customer base as possible. It's a simple but powerful approach because:
  • It minimizes the risk of selection bias, where certain types of people might be unintentionally included or excluded.
  • It increases the reliability and validity of your results, making your findings more generalizable to the entire population.
Using random sampling helps ensure that any patterns or trends you observe, such as average waiting times, are not skewed by the data collection method itself but are instead reflective of the real situation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A sample of 20 managers was taken, and they were asked whether or not they usually take work home. The responses of these managers are given below, where yes indicates they usually take work home and no means they do not. \(\begin{array}{lllllllll}\text { Yes } & \text { Yes } & \text { No } & \text { No } & \text { No } & \text { Yes } & \text { No } & \text { No } & \text { No } & \text { No } \\ \text { Yes } & \text { Yes } & \text { No } & \text { Yes } & \text { Yes } & \text { No } & \text { No } & \text { No } & \text { No } & \text { Yes }\end{array}\) Make a \(99 \%\) confidence interval for the percentage of all managers who take work home.

Jack's Auto Insurance Company customers sometimes have to wait a long time to speak to a customer service representative when they call regarding disputed claims. A random sample of 25 such calls yielded a mean waiting time of 22 minutes with a standard deviation of 6 minutes. Construct a \(99 \%\) confidence interval for the population mean of such waiting times. Assume that such waiting times for the population follow a normal distribution.

A sample selected from a population gave a sample proportion equal to \(.73\) a. Make a \(99 \%\) confidence interval for \(p\) assuming \(n=100\). b. Construct a \(99 \%\) confidence interval for \(p\) assuming \(n=600\). c. Make a \(99 \%\) confidence interval for \(p\) assuming \(n=1500\). d. Does the width of the confidence intervals constructed in parts a through \(\mathrm{c}\) decrease as the sample size increases? If yes, explain why.

When one is attempting to determine the required sample size for estimating a population mean, and the information on the population standard deviation is not available, it may be feasible to take a small preliminary sample and use the sample standard deviation to estimate the required sample size, \(n\). Suppose that we want to estimate \(\mu\), the mean commuting distance for students at a community college, to a margin of error within 1 mile with a confidence level of \(95 \%\). A random sample of 20 students yields a standard deviation of \(4.1\) miles. Use this value of the sample standard deviation, \(s\), to estimate the required sample size, \(n\). Assume that the corresponding population has a normal distribution.

What are the parameters of a normal distribution and a \(t\) distribution? Explain.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.