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Consider a large population with \(\mu=60\) and \(\sigma=10\). Assuming \(n / N \leq .05\), find the mean and standard deviation of the sample mean, \(\bar{x}\), for a sample size of a. \(18 \quad\) b. 90

Short Answer

Expert verified
The mean of the sample mean is 60 for both sample sizes. The standard deviation of the sample mean for a sample size of 18 and 90 are \(σ_{\bar{x}} = \frac{10}{\sqrt{18}}\) and \(σ_{\bar{x}} = \frac{10}{\sqrt{90}}\) respectively.

Step by step solution

01

Finding the sample mean

Firstly, we're asked to compute the mean of the sample mean. According to the Central Limit Theorem, the mean of the sample mean is equal to the population mean, which is given as \(\mu = 60\). Hence, the mean of the sample mean will be 60 for both samples a) and b).
02

Calculating the standard deviation for a sample size of 18

To find the standard deviation of the sample mean for a sample size of 18, we apply the formula \(σ_{\bar{x}} = \frac{σ}{\sqrt{n}}\). Here, \(\sigma = 10\) is the population standard deviation and \(n = 18\) is the sample size. Plugging in the values, we get \(σ_{\bar{x}} = \frac{10}{\sqrt{18}}\). This is the standard deviation of the sample mean for a sample size of 18.
03

Calculating the standard deviation for a sample size of 90

Similarly, to find the standard deviation of the sample mean for a sample size of 90, we re-apply the formula \(σ_{\bar{x}} = \frac{σ}{\sqrt{n}}\). Here, \(\sigma = 10\) is the population standard deviation and \(n = 90\) is the sample size. Plugging in the values, we get \(σ_{\bar{x}} = \frac{10}{\sqrt{90}}\). This is the standard deviation of the sample mean for a sample size of 90.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean, denoted as \( \bar{x} \), is the average of all the observations in a sample. It's one of the critical concepts in statistics, especially when it comes to understanding the Central Limit Theorem. When we calculate the sample mean, we sum all the individual data points in our sample and then divide by the number of data points. In simpler terms, if you have collected data from a sample, say, ages of 10 students: 15, 16, 12, 14, 15, 16, 13, 14, 15, 14, the sample mean would be calculated as follows:
  • Sum all the ages: \(15 + 16 + 12 + 14 + 15 + 16 + 13 + 14 + 15 + 14 = 144\)
  • Divide by the number of students (10): \(\bar{x} = \frac{144}{10} = 14.4\)
This 14.4 would be your sample mean. The sample mean gives you a quick snapshot of your data and summarizes the central tendency of the sample.
Standard Deviation
The standard deviation of a sample, often represented as \( \sigma \), is a measure of how much the individual data points in a sample tend to deviate from the sample mean. A high standard deviation indicates that the data points are spread out over a wider range of values, while a low standard deviation indicates that the data points tend to be close to the mean.When you're dealing with a sample from a larger population, the standard deviation of the sample mean is calculated using the formula: \[ \sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}} \]where \( \sigma_{\bar{x}} \) is the standard deviation of the sample mean, \( \sigma \) is the population standard deviation, and \( n \) is the sample size.This formula helps us understand how much the sample mean would differ if you were to take different samples from the same population. As the sample size increases, the standard deviation of the sample mean typically decreases, making it a more accurate reflection of the population mean.
Population Mean
The population mean, represented by \( \mu \), is the average of all the values in a population. Unlike the sample mean, which is based on a subset of the population, the population mean is the true mean for the entire group.Let's say you're interested in analysing the test scores of all students in a school. If you had data from every single student, the average score you calculate would be the population mean.In practical terms, it is often difficult to calculate the population mean because it involves collecting data from every individual in the population. Therefore, we usually take a sample mean as an estimate. According to the Central Limit Theorem, the sample mean will approximate the population mean, especially with larger sample sizes. In our example, regardless of whether the sample size is 18 or 90, the population mean remains the same: \( \mu = 60 \).
Sample Size
The sample size, denoted by \( n \), refers to the number of observations or data points collected in a sample. It is crucial in statistics as it influences the accuracy of the sample mean as an estimator for the population mean.
  • Smaller sample sizes can lead to more variability and less reliable estimates of the population mean.
  • Larger sample sizes typically provide more reliable estimates because they tend to "average out" anomalies or extreme values.
Using the example from the exercise, consider samples with sizes 18 and 90. As the sample size increases, the standard deviation of the sample mean decreases. This means that the sample mean of a larger sample size 90 is likely to be closer to the population mean than that of a smaller sample size 18.Hence, the choice of sample size is essential in research and data analysis, as larger sample sizes generally provide estimates that are more reflective of the real-world population.

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Most popular questions from this chapter

The GPAs of all 5540 students enrolled at a university have an approximately normal distribution with a mean of \(3.02\) and a standard deviation of \(.29 .\) Let \(\bar{x}\) be the mean GPA of a random sample of 48 students selected from this university. Find the mean and standard deviation of \(\bar{x}\), and comment on the shape of its sampling distribution.

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