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For a population, \(\mu=125\) and \(\sigma=36\). a. For a sample selected from this population, \(\mu_{\bar{x}}=125\) and \(\sigma_{\bar{x}}=3.6 .\) Find the sample size. Assume \(n / N \leq .05\). b. For a sample selected from this population, \(\mu_{\bar{x}}=125\) and \(\sigma_{\bar{x}}=2.25 .\) Find the sample size. Assume \(n / N \leq .05\).

Short Answer

Expert verified
a. The sample size is 100. b. The sample size is 256.

Step by step solution

01

Gather Values

Before continuing, we need to know what values we are working with. From the problem, \(\mu_{\bar{x}}=125\), \(\sigma = 36\), and \(\sigma_{\bar{x}} = 3.6\) for part a.
02

Use Standard Deviation Formula to Solve For 'n'

We know from the Central Limit Theorem that \(\sigma_{\bar{x}} = \sigma / \sqrt{n}\). We want to solve for n, so we can rearrange this formula to be \(n = (\sigma / \sigma_{\bar{x}})^2\). Plugging in the values gives \(n = (36 / 3.6)^2 = 100\).
03

Repeat process for part b

For part b, \(\sigma_{\bar{x}} = 2.25\). With the same rearranged formula \(n = (\sigma / \sigma_{\bar{x}})^2\), plugging in the values gives \(n = (36 / 2.25)^2 = 256\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Size Calculation
In statistics, determining the correct sample size is crucial for ensuring that a study's results are reliable and generalizable to the population. When dealing with problems related to the Central Limit Theorem, as in our example, a key formula helps us determine the required sample size.
The formula is derived from the relationship between the population standard deviation (\(\sigma\)) and the standard deviation of the sample mean (\(\sigma_{\bar{x}}\)). We express this as:
  • \(\sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}}\)
This equation can be rearranged to solve for the sample size (\(n\)), giving us:
  • \(n = \left(\frac{\sigma}{\sigma_{\bar{x}}}\right)^2\)
By plugging in the known values for the population standard deviation and the sample mean standard deviation, we can compute the sample size that ensures accuracy in estimating the population mean.
For example:
  • When \(\sigma = 36\) and \(\sigma_{\bar{x}} = 3.6\), the sample size calculated is 100.
  • For \(\sigma = 36\) and \(\sigma_{\bar{x}} = 2.25\), the sample size required is 256.
Population Mean
The population mean, denoted as \(\mu\), represents the average of all values within a complete dataset or population. It is a central value that gives us important insights into the population's overall behavior. In many statistical analyses, knowing the population mean helps compare individual or sample data against the entire population.
In our exercise, the population mean (\(\mu\)) is given as 125. This means that if you were to measure every single item within the population, the average measurement would be 125.
Understanding the population mean is essential because it serves as a benchmark for evaluating sample means. When researchers take a sample from a population, they often aim to make inferences about the population mean. This is because the sample mean provides an estimate of the population mean.
Population Standard Deviation
The population standard deviation, represented by \(\sigma\), is a measure of how spread out the values in a population are around the mean. It provides insight into the degree of variation existing within the dataset.
A large standard deviation signifies high variability or spread among the population's values, whereas a small standard deviation implies that the values are closely clustered around the mean.
In our example, the population standard deviation is 36. This indicates that on average, the data points deviate from the mean by a value of 36 units.
Knowing the population standard deviation is vital when calculating the sample size needed for estimating the population mean. It forms a crucial part of the formula that ties into the Central Limit Theorem: \(\sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}}\). Ensuring an accurate understanding of this standard deviation helps derive meaningful insights and conclusions in statistical analysis.
Sample Mean Standard Deviation
When working with sample data, the sample mean standard deviation, denoted as \(\sigma_{\bar{x}}\), is crucial. It is also known as the "standard error of the mean." The sample mean standard deviation measures the dispersion or spread of sample means if you were to take multiple samples from the same population.
In other words, it tells us how much we can expect the sample mean to deviate from the true population mean. A smaller \(\sigma_{\bar{x}}\) indicates that the sample mean is a good estimate of the population mean.
In our problem, we have two scenarios dealing with different standard deviations of the sample mean: 3.6 and 2.25. These values impact the required sample size:
  • A \(\sigma_{\bar{x}}\) of 3.6 requires a smaller sample size (100) to ensure the mean sample estimate closely aligns with the population mean.
  • Conversely, a lower \(\sigma_{\bar{x}}\) of 2.25 necessitates a larger sample size (256) for the same purpose.
Understanding the significance of \(\sigma_{\bar{x}}\) is essential for effectively applying statistical techniques to estimate population parameters with confidence.

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Most popular questions from this chapter

A city is planning to build a hydroelectric power plant. A local newspaper found that \(53 \%\) of the voters in this city favor the construction of this plant. Assume that this result holds true for the population of all voters in this city. a. What is the probability that more than \(50 \%\) of the voters in a random sample of 200 voters selected from this city will favor the construction of this plant? b. A politician would like to take a random sample of voters in which more than \(50 \%\) would favor the plant construction. How large a sample should be selected so that the politician is \(95 \%\) sure of this outcome?

For a population, \(N=10,000, \mu=124\), and \(\sigma=18 .\) Find the \(z\) value for each of the following for \(n=36\) a. \(\bar{x}=128.60 \quad\) b. \(\bar{x}=119.30 \quad\) c. \(\bar{x}=116.88 \quad\) d. \(\bar{x}=132.05\)

A machine at Katz Steel Corporation makes 3 -inch-long nails. The probability distribution of the lengths of these nails is normal with a mean of 3 inches and a standard deviation of \(.1\) inch. The quality control inspector takes a sample of 25 nails once a week and calculates the mean length of these nails. If the mean of this sample is either less than \(2.95\) inches or greater than \(3.05\) inches, the inspector concludes that the machine needs an adjustment. What is the probability that based on a sample of 25 nails, the inIspector will conclude that the machine needs an adjustment?

If all possible samples of the same (large) size are selected from a population, what percentage of all the sample means will be within \(1.5\) standard deviations \(\left(\sigma_{\bar{x}}\right)\) of the population mean?

A population of \(N=4000\) has a population proportion equal to \(.12 .\) In each of the following cases, which formula will you use to calculate \(\sigma_{\hat{p}}\) and why? Using the appropriate formula, calculate \(\sigma_{\hat{p}}\) for each of these cases a. \(n=800\) b. \(n=30\)

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