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A contractor has submitted bids on three state jobs: an office building, a theater, and a parking garage. State rules do not allow a contractor to be offered more than one of these jobs. If this contractor is awarded any of these jobs, the profits earned from these contracts are \(\$ 10\) million from the office building, \(\$ 5\) million from the theater, and \(\$ 2\) million from the parking garage. His profit is zero if he gets no contract. The contractor estimates that the probabilities of getting the office building contract, the theater contract, the parking garage contract, or nothing are \(15, .30, .45\), and \(.10\), respectively. Let \(x\) be the random variable that represents the contractor's profits in millions of dollars. Write the probability distribution of \(x\). Find the mean and standard deviation of \(x\). Give a brief interpretation of the values of the mean and standard deviation.

Short Answer

Expert verified
The probability distribution of \(x\), the contractor's profits in millions of dollars, is {(0, 0.10), (2, 0.45), (5, 0.30), (10, 0.15)}. The mean (expected value) and standard deviation can be calculated using these probabilities and corresponding profit values. The mean gives an average profit expected, while the standard deviation gives a sense of spread of the profit around this mean value.

Step by step solution

01

Write the Probability Distribution of x

Create a table with two columns - one for \(x\) (profits in millions) and the other for \(P(x)\) (probability). Populate the profits column with the corresponding profits from each job: $0 for none, $2 million for parking garage, $5 million for the theater, and $10 million for the office building. Populate the probability column with the corresponding probabilities: 0.15 for office, 0.30 for theater, 0.45 for garage, 0.10 for none.
02

Calculate the Mean (Expected Value)

The mean or expected value of a random variable for a probability distribution is the sum of all values of the variable each multiplied by their respective probabilities. Symbolically, \(μ = Σ [x * P(x)]\). Compute this sum using the values from the table created in step 1.
03

Compute the Standard Deviation

The standard deviation provides a measure of the dispersion or spread of the distribution. It is computed as the square root of the Variance. Variance for a discrete random variable is computed as \(σ^2 = Σ [(x - μ)^2 * P(x)]\). Calculate the variance first, then get the square root of the result to find the standard deviation.
04

Interpretation of the Mean and Standard Deviation

The mean value symbolizes the average profit that the contractor is expected to earn considering all possibilities and their probabilities. It is a measure of central tendency. The standard deviation signifies the variability of the profit outcomes around this mean value. A smaller standard deviation means that the profit outcomes are more concentrated around the mean, while a larger one signifies more spread or variability.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variables
In probability theory, a random variable is a crucial concept that represents a real-valued function defined on a sample space. Simply put, it's a way to assign numerical values to the different outcomes of a probabilistic event. Random variables can be either discrete, taking on a finite or countable set of values, or continuous, where they can assume an infinite number of possible values within a given range. In our example with the contractor, the random variable \(x\) represents the profits in millions from bidding on state projects. The values \(x\) can take are \(0\), \(2\), \(5\), and \(10\) million dollars, depending on which jobs, if any, the contractor wins.
Understanding that each of these outcomes has an associated probability is vital. By evaluating the probability distribution of a random variable, you can grasp the likelihood of each potential result. This involves aligning each possible value of \(x\) with its probability \(P(x)\), providing a comprehensive overview of the expected outcomes of the contractor's bidding efforts. This arrangement allows us to perform further analysis, such as calculating the mean and standard deviation.
Mean and Expected Value
The mean, often referred to as the expected value in probability distributions, is a fundamental concept serving as the weighted average of all possible values. This allows us to determine a central or expected outcome in probabilistic scenarios. To calculate the mean of a random variable \(x\), you multiply each outcome by its probability and then add these products together. This is expressed mathematically as follows: \[ μ = ∑ [x \, P(x)] \] For our contractor example, this means summing up \((0 \times 0.10 + 2 \times 0.45 + 5 \times 0.30 + 10 \times 0.15)\). By calculating this, one can find the average profit expected from the contractor’s bids considering all probabilities. This provides insight into how much profit, on average, the contractor might anticipate.
The expected value allows businesses to plan strategies and manage resources based on likely outcomes. It captures the idea of what can be expected as an average, thus assisting in making informed decisions.
Standard Deviation
Standard deviation is a statistical measure that quantifies the variation or spread of a set of values. In the context of probability distributions, it indicates how much the outcomes of the random variable differ from the mean. To calculate standard deviation, one must first determine the variance, which is the expected value of the squared deviations from the mean:\[ σ^2 = ∑ [(x - μ)^2 \, P(x)] \] After obtaining the variance, the standard deviation \(σ\) is simply the square root of that value. In our scenario with the contractor, this involves computing the variance from the outcome probabilities and the already calculated mean:\((x - μ)\). Doing so provides understanding into the degree of unpredictability or risk associated with the contractor's potential profits.
A lower standard deviation suggests profits are consistent with the average expectation, while a higher deviation points to greater variability. Thus, for decision-making, knowing the standard deviation helps the contractor gauge potential profit risks, enabling more effective planning for various financial outcomes.

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