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Of a total of 100 DVDs manufactured on two machines, 20 are defective. Sixty of the total DVDs were manufactured on Machine 1 , and 10 of these 60 are defective. Are the events "Machine I" and "defective" independent? (Note: Compare this exercise with Example 4-17.)

Short Answer

Expert verified
No, the events 'Machine I' and 'defective' are not independent.

Step by step solution

01

Calculate P(Machine I)

The probability of a DVD being manufactured by Machine I, denoted as P(Machine I), can be calculated as the total number of DVDs manufactured by Machine I divided by the total number of DVDs. So, P(Machine I) = Number of DVDs from Machine I / Total number of DVDs = 60 / 100 = 0.6.
02

Calculate P(Defective)

The probability of a DVD being defective, denoted as P(Defective), can be calculated as the total number of defective DVDs divided by the total number of DVDs. So, P(Defective) = Number of defective DVDs / Total number of DVDs = 20 / 100 = 0.2.
03

Calculate P(Defective|Machine I)

The probability of a DVD being defective given that it was manufactured by Machine I, denoted as P(Defective|Machine I), can be calculated as the number of defective DVDs from Machine I divided by the total number of DVDs from Machine I. So, P(Defective|Machine I) = Number of defective DVDs from Machine I / Number of DVDs from Machine I = 10 / 60 = 0.167.
04

Compare P(Defective) and P(Defective|Machine I)

For the events to be independent, P(Defective) should be equal to P(Defective|Machine I). Here, P(Defective) = 0.2 and P(Defective|Machine I) = 0.167. Since these two probabilities are not equal, we can conclude that the events 'Machine I' and 'defective' are not independent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
In probability, we often come across the term 'independent events'. These are events where the outcome of one does not influence the outcome of the other. For example, when you roll two separate dice, the result of one does not affect the result of the other. Hence, they are independent. When dealing with real-world scenarios, such as manufacturing processes, assessing independence is crucial. If events are independent, it simplifies many calculations and decision-making processes.
To determine if two events, say A and B, are independent, compare their probabilities using the condition:
  • A and B are independent if: \[ P(B|A) = P(B) \]
This means the probability of event B occurring given event A has already occurred, is the same as the probability of B occurring regardless of A. In our exercise, when examining events 'Machine I' and 'defective', we found that the condition of independence was not satisfied, making these events dependent.
Conditional Probability
Conditional probability is an essential concept in understanding how probabilities change when additional information is available. It expresses the likelihood of an event occurring, given that another event has already occurred. The notation \( P(A|B) \) signifies the probability of event A occurring given that B has occurred.
For instance, consider a weather forecast that predicts rain. The probability of you carrying an umbrella given that it will rain is an example of conditional probability. In the exercise, we calculated \( P(\text{Defective} | \text{Machine I}) \), which is the probability a DVD is defective given that it was manufactured by Machine I.
This calculation was pivotal because it helped us compare against the overall probability of defectiveness, \( P(\text{Defective}) \), to determine independence. The conditional probability was found to be 0.167, unlike the 0.2 probability across all DVDs, showing the dependency between 'Machine I' and 'defective' events.
Defective Products
In any production line, the concept of defective products is of great importance. It represents the fraction of items not meeting quality standards. High occurrence of defects can impact the reputation and financial performance of a company.Quality control processes aim to minimize defects by identifying their causes and implementing changes.
Mathematically, if you know the total number of items and the number that are defective, you can determine the probability of an item being defective using \( \frac{\text{Number of Defective Items}}{\text{Total Number of Items}} \). In the given problem, we calculated the probability of a randomly selected DVD being defective, resulting in a rate of 0.2. This signifies that 20% of the DVDs were defective. Such insights are crucial for making data-driven decisions in quality improvement and aligning manufacturing process benchmarks. Overall, assessing defects is a key part of ensuring that operations run smoothly, ultimately leading to higher customer satisfaction.

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Most popular questions from this chapter

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