/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 125 A student is to select three cla... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A student is to select three classes for next semester. If this student decides to randomly select one course from each of eight economics classes, six mathematics classes, and five computer classes, how many different outcomes are possible?

Short Answer

Expert verified
The total number of possible outcomes is 240.

Step by step solution

01

Economics Class Selection

The student has to select one class out of eight economics classes. Therefore, there are 8 ways to make this choice.
02

Mathematics Class Selection

Similarly, the student has to select one class out of six mathematics classes. Hence, there are 6 ways to make this choice.
03

Computer Science Class Selection

Lastly, the student has to select one class from five computer science classes. Consequently, there are 5 ways for this selection.
04

Total Possible Outcomes

As per the counting principle, the total number of outcomes can be found by multiplying the number of choices for each class. Thus, total possibilities = number of economics classes x number of mathematics classes x number of computer classes = \(8 \times 6 \times 5 = 240\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Counting Principle
The counting principle is fundamental in combinatorics for determining the total number of possible outcomes. It states that if you have multiple stages or choices and each stage or choice is independent of others, you multiply the number of ways each stage can occur.
This principle simplifies complex counting problems and is foundational for problems involving sequences of decisions.
For example, when selecting one class from each of the economics, mathematics, and computer classes, you calculate the total outcomes as follows:
  • There are 8 choices for the economics class.
  • There are 6 choices for the mathematics class.
  • There are 5 choices for the computer class.
By multiplying these choices (8 x 6 x 5), you find the total number of possible class combinations, equaling 240.
This method enhances the ability to predict possibilities in various decision-making scenarios by simplifying how outcomes multiply across stages.
Exploring Permutations
Permutations are about arranging elements in a specific order or sequence. Unlike combinations, permutations consider the order of arrangement as important. If you have a set of items and want to know how many different ways you can arrange them, you'll use permutations.
For example, if a student had to take three different subjects but had no restriction on which subjects came first across time slots, the permutations of their schedule would matter. Mathematically, if you have 'n' items and you want to arrange 'r' of them, you use the formula for permutations:
\( P(n,r) = \frac{n!}{(n-r)!} \)
This formula captures all possible sequences of 'r' elements from a total of 'n' elements. It's helpful when the arrangement sequence is strictly crucial, like in seating arrangements, race placements, or scheduling.
Understanding Combinations
Combinations differ from permutations because the sequence or order does not matter. In various scenarios, you may only need to know how many ways you can select items from a larger set without considering different orders or sequences.
Imagine you're choosing which classes to attend but don't care about the order you select them in. In this case, you're dealing with combinations. The formula for finding the number of combinations of selecting 'r' items from a total of 'n' is:
\( C(n,r) = \frac{n!}{r!(n-r)!} \)
Here you're dividing out the number of ways to arrange 'r' items since order doesn't matter. Combinations are particularly useful in scenarios like lottery tickets, committee selections, or grouping items where arrangement is irrelevant.
Calculating Probability
Probability is about determining how likely an event is to occur. It's a key part of combinatorics and is often expressed as a fraction or percentage.
To calculate probability, you determine the number of favorable outcomes divided by the total number of possible outcomes. It's a measure of how likely an event is given all the possible outcomes of a scenario.
For example, if you wanted to calculate the probability of a student randomly selecting a specific set of classes, you'd set up the ratio of one favorable outcome to the total combinations, like the one solved in this exercise where there were 240 total class combinations.
  • Probability formula: \( P(A) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} \)
This approach allows you to rigorously assess and apply likelihoods in various practical applications like games of chance, risk assessments, or making informed decisions based on uncertainty.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The Big Six Wheel (or Wheel of Fortune) is a casino and carnival game that is well known for being a big money maker for the casinos. The wheel has 54 equally likely slots (outcomes) on it. The slot that pays the largest amount of money is called the joker. If a player bets on the joker, the probability of winning is \(1 / 54\). The outcome of any given play of this game (a spin of the wheel) is independent of the outcomes of previous plays. a. Find the probability that a player who always bets on joker wins for the first time on the 15 th play of the game. b. Find the probability that it takes a player who always bets on joker more than 70 plays to win for the first time.

Briefly explain the two properties of probability.

A restaurant menu has four kinds of soups, eight kinds of main courses, five kinds of desserts, and six kinds of drinks. If a customer randomly selects one item from each of these four categories, how many different outcomes are possible?

A random sample of 250 adults was taken, and they were asked whether they prefer watching sports or opera on television. The following table gives the two-way classification of these adults. $$ \begin{array}{lcc} \hline & \begin{array}{c} \text { Prefer Watching } \\ \text { Sports } \end{array} & \begin{array}{c} \text { Prefer Watching } \\ \text { Opera } \end{array} \\ \hline \text { Male } & 96 & 24 \\ \text { Female } & 45 & 85 \\ \hline \end{array} $$ a. If one adult is selected at random from this group, find the probability that this adult i. prefers watching opera ii. is a male iii. prefers watching sports given that the adult is a female iv. is a male given that he prefers watching sports \(\mathrm{v} .\) is a female and prefers watching opera vi. prefers watching sports or is a male b. Are the events "female" and "prefers watching sports" independent? Are they mutually exclusive? Explain why or why not.

In a group of people, some are in favor of a tax increase on rich people to reduce the federal deficit and others are against it. (Assume that there is no other outcome such as "no opinion" and "do not know.") Three persons are selected at random from this group and their opinions in favor or against raising such taxes are noted. How many total outcomes are possible? Write these outcomes in a sample space \(S\). Draw a tree diagram for this experiment.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.