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91Ó°ÊÓ

Briefly describe an impossible event and a sure event. What is the probability of the occurrence of each of these two events?

Short Answer

Expert verified
An impossible event is something like pulling a red card from a deck that only contains black and white cards, and its probability is 0. A sure event is something like getting a head or a tail when flipping a coin, and its probability is 1.

Step by step solution

01

Define Impossible Event

An impossible event is one that cannot happen under any circumstances. For example, pulling a red card from a standard deck that only contains black and white cards.
02

Define Probability of an Impossible Event

The probability of an event that cannot possibly occur (an impossible event) is always equal to 0. This is because the number of favorable outcomes is 0, so the fraction of the number of favorable outcomes to the total number of outcomes is 0.
03

Define Sure Event

A sure event is one that will definitely happen. For example, getting a head or a tail when a fair coin is flipped.
04

Define Probability of a Sure Event

The probability of a sure event is 1. This is because the number of favorable outcomes equals the total number of outcomes, so the fraction of the number of favorable outcomes to the total number of outcomes is 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Impossible Event
An impossible event is a situation that cannot occur under any circumstances. It is important to understand this concept when studying probability, as it helps us differentiate between what is possible and what isn't. For instance, consider rolling a six-sided die and hoping for a result of 7. Since a die only has sides numbered 1 through 6, getting a 7 is impossible. Similarly, drawing a red card from a deck that contains only black and white cards is also impossible.

Calculating the probability of an impossible event is simple. Since there are no favorable outcomes, it makes the probability equal to 0. In mathematical terms, if the number of favorable outcomes is 0 and the total number of possible outcomes is some positive number, then:\[P( ext{impossible event}) = \frac{0}{ ext{total outcomes}} = 0\]This concept helps solidify the idea that some events just can't happen!
Sure Event
A sure event is a situation that is guaranteed to occur. When dealing with probability, identifying sure events is essential, as it provides a baseline for understanding the full range of event outcomes. For example, when you toss a standard coin, the outcome will either be heads or tails. Since one of these outcomes must occur, it is a sure event.

The probability of a sure event is always 1. This is because every possible outcome contributes to the event happening. Therefore, there are as many favorable outcomes as there are total outcomes. The mathematical representation is:\[P( ext{sure event}) = \frac{ ext{total outcomes}}{ ext{total outcomes}} = 1\]Recognizing sure events helps verify the total set of possible outcomes and ensures nothing is overlooked during problem-solving.
Favorable Outcomes
Favorable outcomes are the specific results that are of interest in a probability problem. When calculating probabilities, these outcomes align with the conditions needed for a particular event to happen. For example, when rolling a die, if you are interested in getting an even number, then the favorable outcomes are 2, 4, and 6.

To determine the probability of getting a specific event, we count the number of favorable outcomes. This number is then divided by the total number of possible outcomes to calculate the event's probability:\[P( ext{event}) = \frac{ ext{number of favorable outcomes}}{ ext{total outcomes}}\]Understanding favorable outcomes allows you to tailor your probability calculations to the specific conditions and goals of the problem at hand.
Total Outcomes
Total outcomes refer to all the possible results that can happen in an experiment or activity. Identifying these outcomes is the first step in calculating any probability because they form the denominator of the probability fraction. For example, when rolling a standard six-sided die, the total outcomes are 1, 2, 3, 4, 5, and 6. That's 6 total outcomes.

When you consider the total outcomes, you ensure that you haven't missed any possibilities in your probability calculation. It gives a complete picture of what can occur, setting the stage for comparing the number of favorable outcomes against the whole set. If we revisit the example of a six-sided die and wanting an even number, the total outcomes remain the same, providing the base:\[P( ext{event}) = \frac{ ext{number of favorable outcomes}}{6}\]Total outcomes act as an anchor ensuring the probability values are calculated accurately and completely.

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Most popular questions from this chapter

A small ice cream shop has 10 flavors of ice cream and 5 kinds of toppings for its sundaes. How many different selections of one flavor of ice cream and one kind of topping are possible?

The following table gives a two-way classification of all basketball players at a state university who began their college careers between 2004 and 2008 , based on gender and whether or not they graduated. $$ \begin{array}{lcc} \hline & \text { Graduated } & \text { Did Not Graduate } \\ \hline \text { Male } & 126 & 55 \\ \text { Female } & 133 & 32 \\ \hline \end{array} $$ If one of these players is selected at random, find the following probabilities. a. \(P\) (female or did not graduate) b. \(P(\) graduated or male \()\)

When is the following addition rule used to find the probability of the union of two events \(A\) and \(B\) ? $$ P(A \text { or } B)=P(A)+P(B) $$ Give one example where you might use this formula.

Consider the following addition rule to find the probability of the union of two events \(A\) and \(B\) : $$ P(A \text { or } B)=P(A)+P(B)-P(A \text { and } B) $$ When and why is the term \(P(A\) and \(B\) ) subtracted from the sum of \(P(A)\) and \(P(B)\) ? Give one example where you might use this formula.

Two thousand randomly selected adults were asked whether or not they have ever shopped on the Internet. The following table gives a two-way classification of the responses. $$ \begin{array}{lcc} \hline & \text { Have Shopped } & \text { Have Never Shopped } \\ \hline \text { Male } & 500 & 700 \\ \text { Female } & 300 & 500 \\ \hline \end{array} $$ a. If one adult is selected at random from these 2000 adults, find the probability that this adult i. has never shopped on the Internet ii. is a male iii. has shopped on the Internet given that this adult is a female iv. is a male given that this adult has never shopped on the Internet b. Are the events "male" and "female" mutually exclusive? What about the events "have shopped" and "male?" Why or why not? c. Are the events "female" and "have shopped" independent? Why or why not?

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