/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 140 The following data give the weig... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The following data give the weights (in pounds) of a random sample of 44 college students. (Here \(\mathrm{F}\) and \(\mathrm{M}\) indicate female and male, respectively.) \(\begin{array}{llllll}123 \mathrm{~F} & 195 \mathrm{M} & 138 \mathrm{M} & 115 \mathrm{~F} & 179 \mathrm{M} & 119 \mathrm{~F} \\ 148 \mathrm{~F} & 147 \mathrm{~F} & 180 \mathrm{M} & 146 \mathrm{~F} & 179 \mathrm{M} & 189 \mathrm{M} \\ 175 \mathrm{M} & 108 \mathrm{~F} & 193 \mathrm{M} & 114 \mathrm{~F} & 179 \mathrm{M} & 147 \mathrm{M} \\ 108 \mathrm{~F} & 128 \mathrm{~F} & 164 \mathrm{~F} & 174 \mathrm{M} & 128 \mathrm{~F} & 159 \mathrm{M} \\ 193 \mathrm{M} & 204 \mathrm{M} & 125 \mathrm{~F} & 133 \mathrm{~F} & 115 \mathrm{~F} & 168 \mathrm{M} \\ 123 \mathrm{~F} & 183 \mathrm{M} & 116 \mathrm{~F} & 182 \mathrm{M} & 174 \mathrm{M} & 102 \mathrm{~F} \\ 123 \mathrm{~F} & 99 \mathrm{~F} & 161 \mathrm{M} & 162 \mathrm{M} & 155 \mathrm{~F} & 202 \mathrm{M} \\ 110 \mathrm{~F} & 132 \mathrm{M} & & & & \end{array}\) Compute the mean, median, and standard deviation for the weights of all students, of men only, and of women only. Of the mean and median, which is the more informative measure of central tendency? Write a brief note comparing the three measures for all students, men only, and women only.

Short Answer

Expert verified
The mean, median, and standard deviation of weights would be calculated using the respective formulas. The nature of distribution would help decide if mean or median is a more informative measure of central tendency. A comparison would reveal how these measures vary for different groups.

Step by step solution

01

Organize the data

First organize the weight data for men and women separately, then combine them for all students data. Sorting them in ascending order will be helpful to calculate median later.
02

Calculate mean

The formula to find the mean or average is sum of the data divided by the number of data points. Do the math separately for Male students, Female students, and All students.
03

Calculate median

To find the median, if the data count is odd, the median is the middle number. if it's even, then it's the average of the two middle numbers. Recall that you already sorted the data in ascending order in step 1. So now it'll be easy to find the median.
04

Calculate standard deviation

To find the standard deviation, first find out the variance: subtract the mean from each data point and square the result, then find their mean, and finally, the standard deviation is the square root of the variance. Do this for each category.
05

Analyze results

Now look at the results for mean, median and standard deviation of each group. Which measure of central tendency, mean or median, provides the most information will depend on the nature of the distribution. If the distribution is symmetrical, the mean and median should be very close. If they're not close, then the data might be skewed and the median might provide more useful information. Compare these measures for all students, men only, and women only.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Calculation
The mean, often known as the average, is a fundamental measure of central tendency. It's used to get a general sense of the 'central' value for a set of numbers. To calculate the mean, add up all the values and divide by the number of values.
For our weight data, you'll calculate the mean separately for all students, men, and women.
  • For All Students: Sum up all weights, then divide by 44.
  • For Men Only: Sum the weights, then divide by the total number of men in the sample.
  • For Women Only: Do the same as above but only with the female students' weights.
Calculating the mean gives you an overall "balance point" for the data, showing the general trend.
Median Calculation
The median is another central measure that often gives a better sense of the middle value when data sets are skewed. The process to find the median is straightforward:
Arrange the data in ascending order, then identify the middle point. If the dataset count is odd, pick the central number. If even, take the average of the two central numbers.
  • For all students, simply put the weights in order and locate the middle.
  • Repeat the same for male and female groups independently.
Unlike the mean, the median is less affected by extreme values (also known as outliers), making it a reliable indicator when data have anomalies.
Standard Deviation
The standard deviation is a key metric that describes the spread or variability of data around the mean. It tells you how much variation exists from the average.
Here's how to calculate:
  • Find the mean of the data set.
  • Subtract the mean from each data point and square the result.
  • Calculate the mean of these squared differences.
  • Take the square root of that mean to get the standard deviation.
A smaller standard deviation signifies that data points tend to be closer to the mean. A larger deviation suggests more spread out data, indicating variability.
Data Analysis
Performing data analysis involves examining results from the calculations above and integrating insights. This helps in understanding the data better.
When you compare the mean and median, note which one is closer to most of your data. The median is beneficial when there's a large difference between it and the mean, as it indicates skewness in data distribution.
Consider standard deviation for a sense of data spread. In our weight example, seeing whether men or women have a higher deviation can shed light on weight distribution.
This analytical process shows how each measure offers different insights into data tendencies, balance, and variability.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The following data represent the total points scored in each of the NFL Super Bowl games played from 2001 through 2012 , in that order: \(\begin{array}{lllllllllll}41 & 37 & 69 & 61 & 45 & 31 & 46 & 31 & 50 & 48 & 56 & 38\end{array}\) Compute the range, variance, and standard deviation for these data.

Jeffrey is serving on a six-person jury for a personal-injury lawsuit. All six jurors want to award damages to the plaintiff but cannot agree on the amount of the award. The jurors have decided that each of them will suggest an amount that he or she thinks should be awarded; then they will use the mean of these six numbers as the award to recommend to the plaintiff. a. Jeffrey thinks the plaintiff should receive \(\$ 20,000\), but he thinks the mean of the other five jurors' recommendations will be about \(\$ 12,000 .\) He decides to suggest an inflated amount so that the mean for all six jurors is \(\$ 20,000\). What amount would Jeffrey have to suggest? b. How might this jury revise its procedure to prevent a juror like Jeffrey from having an undue influence on the amount of damages to be awarded to the plaintiff?

When is the value of the standard deviation for a data set zero? Give one example. Calculate the standard deviation for the example and show that its value is zero.

The Belmont Stakes is the final race in the annual Triple Crown of thoroughbred horse racing. The race is \(1.5\) miles in length, and the record for the fastest time of 2 minutes, 24 seconds is held by Secretariat, the 1973 winner. We compared Secretariat's time from 1973 with the time of each winner of the Belmont Stakes for the years \(1999-2011\). The following data represent the differences (in seconds) between each winner's time for the years \(1999-2011\) and Secretariat's time in 1973 . For example, the 1999 winner took \(3.80\) seconds longer than Secretariat to finish the race. \(\begin{array}{lllllllllllllll}3.80 & 7.20 & 2.80 & 5.71 & 4.26 & 3.50 & 4.75 & 3.81 & 4.74 & 5.65 & 3.54 & 7.57 & 6.88\end{array}\) a. Calculate the mean and median. Do these data have a mode? Why or why not? b. Compute the range, variance, and standard deviation for these data.

In the Olympic Games, when events require a subjective judgment of an athlete's performance, the highest and lowest of the judges' scores may be dropped. Consider a gymnast whose performance is judged by seven judges and the highest and the lowest of the seven scores are dropped. a. Gymnast A's scores in this event are \(9.4,9.7,9.5,9.5,9.4,9.6\), and \(9.5\). Find this gymnast's mean score after dropping the highest and the lowest scores. b. The answer to part a is an example of (approximately) what percentage of trimmed mean? c. Write another set of scores for a gymnast \(B\) so that gymnast \(A\) has a higher mean score than gymnast B based on the trimmed mean, but gymnast B would win if all seven scores were counted. Do not use any scores lower than \(9.0\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.