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What is the shape of the sampling distribution of \(\hat{p}_{1}-\hat{p}_{2}\) for two large samples? What are the mean and standard deviation of this sampling distribution?

Short Answer

Expert verified
The shape of the sampling distribution of the difference between two sample proportions for large samples is approximately normal. The mean is the difference in the population proportions \(p_{1}-p_{2}\) and the standard deviation is \(\sqrt{ \frac{{p_{1}(1 - p_{1})}}{{n_{1}}} + \frac{{p_{2}(1 - p_{2})}}{{n_{2}}} }\).

Step by step solution

01

Shape of the Sampling Distribution

The Central Limit Theorem states that when sampling a population repeatedly and calculating a statistic (like the mean), the shape of the distribution of that statistic will approach a normal distribution as the sample size gets larger. Therefore, for two large samples, the shape of the sampling distribution of \(\hat{p}_{1}-\hat{p}_{2}\) is approximately normal.
02

Mean of the Sampling Distribution

The mean of the distribution of differences \(\hat{p}_{1}-\hat{p}_{2}\) is equal to the difference in the population proportions, that is \(E(\hat{p}_{1}-\hat{p}_{2})=p_{1}-p_{2}\), assuming that \(p_{1}\) and \(p_{2}\) are the true proportions in the population corresponding to the two samples.
03

Standard Deviation of the Sampling Distribution

The standard deviation of the sampling distribution of the difference between two sample proportions can be calculated with the following formula: \(\sqrt{ \frac{{p_{1}(1 - p_{1})}}{{n_{1}}} + \frac{{p_{2}(1 - p_{2})}}{{n_{2}}} }\)Here \(n_{1}\) and \(n_{2}\) are the sizes of the two samples and \(p_{1}\) and \(p_{2}\) are the sample proportions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Central Limit Theorem
The Central Limit Theorem (CLT) is a fundamental concept in statistics. It tells us that the distribution of sample means (or some other statistic) will tend to be approximately normal, regardless of the shape of the population distribution, as long as the sample size is sufficiently large. This theorem is powerful because it allows statisticians to make inferences about population parameters using the normal distribution.

For example, even if you start with a population that is skewed or not normal, the distribution of the sample mean will become more normal as your sample size increases. This is true especially when your samples are large.
  • The sample size is typically considered large if it is greater than 30.
  • The shape of the sampling distribution becomes more bell-shaped and normal as sample size grows.
For the exercise given, the CLT indicates that the sampling distribution of the difference between two sample proportions, \(\hat{p}_{1}-\hat{p}_{2} \), is approximately normal when the samples are large.

Understanding the CLT helps in predicting the behavior of data gathering processes and the reliability of statistical inferences.
Normal Distribution
The normal distribution, often termed the bell curve due to its shape, is a continuous probability distribution that is very common in statistics. It depicts the distribution of variables about the mean. This curve is symmetric, with most of the data clustered around the mean and fewer appearing as you move further from the mean, creating a bell shape.

The normal distribution is key to many statistical methodologies because of its properties, particularly the fact that it is completely defined by its mean and standard deviation. This makes it a standard choice when approximating the distributions of various data sets and test statistics.
  • The curve is symmetrical about the mean.
  • The mean, median, and mode of a normal distribution are equal.
  • The area under the curve is 1, representing a complete probability.
In the context of the problem, the sampling distribution of the difference between two proportions (\(\hat{p}_{1}-\hat{p}_{2}\) ) is assumed to be normal when the sample sizes are large. This holds true because of the Central Limit Theorem.
Mean of Sampling Distribution
The mean of a sampling distribution is a key concept in statistics. It refers to the average of all the sample means if we were to take multiple samples from the same population. For the sampling distribution of the difference between two proportions, \(\hat{p}_{1}-\hat{p}_{2}\), the mean is given by the difference in the population proportions, \(E(\hat{p}_{1}-\hat{p}_{2})=p_{1}-p_{2}\).

Here, \(p_{1}\) and \(p_{2}\) are the true proportions in each population from which the samples are being drawn. As each sample acts as a representation of the population, the expected value (\(E\)) of the sample means reflects this population parameter. This relationship allows statisticians to make predictions about the unknown population parameters based on sample data.

Understanding this concept helps in performing hypothesis tests, estimating population parameters, and understanding the variability of sample proportions.
Standard Deviation of Sampling Distribution
The standard deviation of a sampling distribution, often referred to as the standard error, measures the spread of the sample means around the population mean. For the distribution of the difference between two proportions, it shows how much variation there is in the sample proportions compared to the true population proportions.The formula for the standard deviation of the difference between two sample proportions is:\[\sqrt{ \frac{{p_{1}(1 - p_{1})}}{{n_{1}}} + \frac{{p_{2}(1 - p_{2})}}{{n_{2}}} }\]where:
  • \(p_{1}\) and \(p_{2}\) are the sample proportions.
  • \(n_{1}\) and \(n_{2}\) are the sample sizes.
This formula is derived based on the assumption that the individual sample observations are independent and vary according to a binomial distribution.

The standard deviation gives us a sense of how much fluctuation there is likely to be from sample to sample, informing us about the reliability of our sample estimates for inference. In practical terms, this helps determine how accurately we can estimate the population difference from the proportion differences observed in samples.

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Most popular questions from this chapter

The manufacturer of a gasoline additive claims that the use of this additive increases gasoline mileage. A random sample of six cars was selected, and these cars were driven for 1 week without the gasoline additive and then for 1 week with the gasoline additive. The following table gives the miles per gallon for these cars without and with the gasoline additive. \begin{tabular}{l|llllll} \hline Without & \(24.6\) & \(28.3\) & \(18.9\) & \(23.7\) & \(15.4\) & \(29.5\) \\ \hline With & \(26.3\) & \(31.7\) & \(18.2\) & \(25.3\) & \(18.3\) & \(30.9\) \\ \hline \end{tabular} a. Construct a \(99 \%\) confidence interval for the mean \(\mu_{d}\) of the population paired differences, where a paired difference is equal to the miles per gallon without the gasoline additive minus the miles per gallon with the gasoline additive. b. Using a \(2.5 \%\) significance level, can you conclude that the use of the gasoline additive increases the gasoline mileage?

When are the samples considered large enough for the sampling distribution of the difference between two sample proportions to be (approximately) normal?

The owner of a mosquito-infested fishing camp in Alaska wants to test the effectiveness of two rival brands of mosquito repellents, \(\mathrm{X}\) and \(\mathrm{Y}\). During the first month of the season, eight people are chosen at random from those guests who agree to take part in the experiment. For each of these guests, Brand \(\bar{X}\) is randomly applied to one arm and Brand \(\mathrm{Y}\) is applied to the other arm. These guests fish for 4 hours, then the owner counts the number of bites on each arm. The table below shows the number of bites on the arm with Brand \(X\) and those on the arm with Brand \(Y\) for each guest. \begin{tabular}{l|rrrrrrrr} \hline Guest & A & B & C & D & E & F & G & H \\ \hline Brand X & 12 & 23 & 18 & 36 & 8 & 27 & 22 & 32 \\ \hline Brand Y & 9 & 20 & 21 & 27 & 6 & 18 & 15 & 25 \\ \hline \end{tabular} a. Construct a \(95 \%\) confidence interval for the mean \(\mu_{d}\) of population paired differences, where a paired difference is defined as the number of bites on the arm with Brand \(X\) minus the number of bites on the arm with Brand \(Y\). b. Test at a \(5 \%\) significance level whether the mean number of bites on the arm with Brand \(\mathrm{X}\) and the mean number of bites on the arm with Brand \(Y\) are different for all such guests.

The lottery commissioner's office in a state wanted to find if the percentages of men and women who play the lottery often are different. A sample of 500 men taken by the commissioner's office showed that 160 of them play the lottery often. Another sample of 300 women showed that 66 of them play the lottery often. a. What is the point estimate of the difference between the two population proportions? b. Construct a \(99 \%\) confidence interval for the difference between the proportions of all men and all women who play the lottery often. c. Testing at a \(1 \%\) significance level, can you conclude that the proportions of all men and all women who play the lottery often are different?

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