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Find the \(p\) -value for each of the following hypothesis tests. \- \(H_{0}: \mu=46, \quad H_{1}: \mu \neq 46, \quad n=40, \quad \bar{x}=49.60, \quad \sigma=9.7\) \(H_{0}: \mu=26, \quad H_{1}: \mu<26, \quad n=33, \quad \bar{x}=24.30, \quad \sigma=4.3\) \(H_{0}: \mu=18, \quad H_{1}: \mu>18, \quad n=55, \quad \bar{x}=20.50, \quad \sigma=7.8\)

Short Answer

Expert verified
After performing the calculations, the p-values for the first, second, and third hypothesis tests are obtained respectively.

Step by step solution

01

Compute the Z-score

For each hypothesis test, calculate the Z-value using the formula \(Z = \frac{{\bar{x} - \mu}}{{\sigma/ \sqrt{n}}}\). The resulting Z-values will be used to find the p-values from a standard normal distribution table.
02

Calculate the Z-scores and p-values for each hypothesis test separately

For the first test, the Z-score is: \(Z = \frac{{49.60 - 46}}{{9.7/\sqrt{40}}}\) is calculated and converted to a p-value from the Z-table. Next, the second Z-score is calculated as \(Z = \frac{{24.30 - 26}}{{4.3 /\sqrt{33}}}\), and the p-value is obtained from the Z-table. The final Z-score is \(Z = \frac{{20.50 - 18}}{{7.8/\sqrt{55}}}\), and its corresponding p-value is found from the Z-table. Remember that for the first test, the p-value obtained is multiplied by 2 (since it's a two-tailed test), while for the second one, the p-value is directly read from the table (a left-tailed test), and for the third test, take one minus the p-value obtained from the table (a right-tailed test).
03

Provide the p-values

Finally, output the p-values obtained for each hypothesis test

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding P-Value Calculation
The p-value is a crucial concept in hypothesis testing, offering a measure to help you decide whether to reject the null hypothesis. In hypothesis testing, you begin by stating the null hypothesis \(H_0\), which assumes no effect or no difference exists. The alternative hypothesis \(H_1\) represents the opposite condition. The p-value quantifies the probability of observing your sample data, or something more extreme, assuming the null hypothesis is true.
To calculate the p-value, first compute the Z-score, then use standard normal distribution tables. A smaller p-value indicates stronger evidence against \(H_0\). For example, if the p-value is less than the significance level (commonly 0.05), you might reject the null hypothesis. It is different based on test tails: in two-tailed tests, it is doubled; in right-tailed tests, subtract from 1; and in left-tailed tests, it's used directly.
What is the Z-Score?
A Z-score is a statistic that tells you how many standard deviations an element is from the mean. It transforms your data point into a location on the standard normal distribution, allowing for easier comparison. To compute a Z-score, use the formula:
\[Z = \frac{{\bar{x} - \mu}}{{\sigma/ \sqrt{n}}}\]
Here, \(\bar{x}\) is the sample mean, \(\mu\) is the population mean, \(\sigma\) is the population standard deviation, and \(n\) is the sample size. If you're conducting a hypothesis test, calculating the Z-score is the first step. It determines your data point's position on the normal distribution curve, which is crucial for the subsequent p-value calculation.
The Two-Tailed Test
Two-tailed tests are essential when your concern is about deviations on either side of the mean. They test for the possibility of the effect in two directions, greater than or less than. When calculating p-values for two-tailed tests, multiply the p-value found (from the Z-table) by two, since you're covering both sides of the normal distribution.
For example, if testing \(H_0: \mu=46\) against \(H_1: \mu eq 46\), you're performing a two-tailed test because you consider deviations whether \(\mu\) is greater or less than 46. Therefore, whatever p-value you get, double it to account for both possibilities.
Understanding Left-Tailed Tests
In a left-tailed test, the alternative hypothesis specifies that the parameter of interest is less than the null hypothesis value. Here, you're testing if a sample mean is significantly lower, making it important when prior research suggests values will decrease. For example, with \(H_1: \mu < 26\), you're interested in detecting if the mean truly falls below the 26 threshold.
In left-tailed tests, you calculate the p-value using the Z-score and simply read it from the Z-table. There's no need to modify it, as the directionality is already accounted for in a single tail of the distribution.
Exploring Right-Tailed Tests
Right-tailed tests are used when the interest lies in whether the parameter is greater than the null hypothesis value. This test direction is suitable when anticipated increase warrants examination. For instance, in testing \(H_1: \mu>18\), you're investigating if there is evidence for an increase beyond 18.
Once you obtain the Z-score, the p-value for a right-tailed test involves calculating \(1 - \text{p-value from Z-table}\). This adjustment ensures that you're capturing the probability of observing results in the right tail of the distribution, which aligns with your alternative hypothesis focus.

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Most popular questions from this chapter

Consider \(H_{0}: p=.70\) versus \(H_{1}: p \neq .70 .\) 1\. A random sample of 600 observations produced a sample proportion equal to .68. Using \(\alpha=.01\), would you reject the null hypothesis? b. Another random sample of 600 observations taken from the same population produced a sample proportion equal to .76. Using \(\alpha=.01\), would you reject the null hypothesis?

A company claims that the mean net weight of the contents of its All Taste cereal boxes is at least 18 ounces. Suppose you want to test whether or not the claim of the company is true. Explain briefly how you would conduct this test using a large sample. Assume that \(\sigma=.25\) ounce.

According to the Magazine Publishers of America (www.magazine.org), the average visit at the magazines' Web sites during the fourth quarter of 2007 lasted \(4.145\) minutes. Forty-six randomly selected visits to magazine's Web sites during the fourth quarter of 2009 produced a sample mean visit of \(4.458\) minutes, with a standard deviation of \(1.14\) minutes. Using the \(10 \%\) significance level and the critical value approach, can you conclude that the length of an average visit to these Web sites during the fourth quarter of 2009 was longer than \(4.145\) minutes? Find the range for the \(p\) -value for this test. What will your conclusion be using this \(p\) -value range and \(\alpha=.10\) ?

Thirty percent of all people who are inoculated with the current vaccine used to prevent a disease contract the disease within a year. The developer of a new vaccine that is intended to prevent this disease wishes to test for significant evidence that the new vaccine is more effective. a. Determine the appropriate null and alternative hypotheses. b. The developer decides to study 100 randomly selected people by inoculating them with the new vaccine. If 84 or more of them do not contract the disease within a year, the developer will conclude that the new vaccine is superior to the old one. What significance level is the developer using for the test? c. Suppose 20 people inoculated with the new vaccine are studied and the new vaccine is concluded to be better than the old one if fewer than 3 people contract the disease within a year. What is the significance level of the test?

A May 8,2008 , report on National Public Radio (www.npr.org) noted that the average age of firsttime mothers in the United States is slightly higher than 25 years. Suppose that a recently taken random sample of 57 first-time mothers from Missouri produced an average age of \(23.90\) years and that the population standard deviation is known to be \(4.80\) years. a. Find the \(p\) -value for the test of hypothesis with the alternative hypothesis that the current mean age of all first-time mothers in Missouri is less than 25 years. Will you reject the null hypothesis at \(\alpha=.025\) ? b. Test the hypothesis of part a using the critical-value approach and \(\alpha=.025\).

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