/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Let \(x\) be a continuous random... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(x\) be a continuous random variable that is normally distributed with a mean of 65 and a standard deviation of 15 . Find the probability that \(x\) assumes a value a. less than 45 b. greater than 79 c. greater than 54 d. less than 70

Short Answer

Expert verified
a. 0.0925, b. 0.1762, c. 0.7673, d. 0.6293

Step by step solution

01

Definition of Z-score

The Z-score of a data point is defined as \(Z = \frac{x - \mu}{\sigma}\) where \(x\) is the value of the data point, \(\mu\) is the mean of the distribution and \(\sigma\) is the standard deviation. We'll use this formula to convert the given random variable values to their respective Z-scores.
02

Using Z-score formula for a.

We have \(x = 45\), \(\mu = 65\), and \(\sigma = 15\). Plug these values into the Z-score formula to get \(Z = \frac{45 - 65}{15} = -1.33\). This gives us the Z-score for a.
03

Using Z-score table for a.

Using a Z-score table, find the probability that the Z-score is less than -1.33. The value corresponding to Z = -1.33 from the table is approximately 0.0925, which is our answer for a.
04

Using Z-score formula for b.

We have \(x = 79\), \(\mu = 65\), and \(\sigma = 15\). Plugging these values into the Z-score formula gives us \(Z = \frac{79 - 65}{15} = 0.93\). This gives us the Z-score for b.
05

Using Z-score table for b.

Since we want the probability that the Z-score is greater than 0.93, we need to subtract the value corresponding to Z = 0.93 from 1. The value for Z = 0.93 from the table is approximately 0.8238. So, 1- 0.8238 = 0.1762, which is our answer for b.
06

Using Z-score formula for c.

We have \(x = 54\), \(\mu = 65\), and \(\sigma = 15\). Using the Z-score formula gives us \(Z = \frac{54 - 65}{15} = -0.73\). This gives us the Z-score for c.
07

Using Z-score table for c.

To find the probability that the Z-score is greater than -0.73, subtract the value corresponding to Z = -0.73 from 1. The value from the Z = -0.73 from the table is approximately 0.2327. So, 1 - 0.2327 = 0.7673, which is our answer for c.
08

Using Z-score formula for d.

We have \(x = 70\), \(\mu = 65\), and \(\sigma = 15\). The Z-score is given by \(Z = \frac{70 - 65}{15} = 0.33\). This gives us the Z-score for d.
09

Using Z-score table for d.

The probability that Z is less than 0.33 is found directly from the Z-score table. The value corresponding to Z = 0.33 is approximately 0.6293, which is our answer for d.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For a continuous probability distribution, why is \(P(a

For a binomial probability distribution, \(n=120\) and \(p=.60\). Let \(x\) be the number of successes in 120 trials. a. Find the mean and standard deviation of this binomial distribution. b. Find \(P(x \leq 69)\) using the normal approximation. c. Find \(P(67 \leq x \leq 73)\) using the normal approximation.

A machine at Kasem Steel Corporation makes iron rods that are supposed to be 50 inches long. However, the machine does not make all rods of exactly the same length. It is known that the probability distribution of the lengths of rods made on this machine is normal with a mean of 50 inches and a standard deviation of \(.06\) inch. The rods that are either shorter than \(49.85\) inches or longer than \(50.15\) inches are discarded. What percentage of the rods made on this machine are discarded?

Fast Auto Service guarantees that the maximum waiting time for its customers is 20 minutes for oil and lube service on their cars. It also guarantees that any customer who has to wait longer than 20 minutes for this service will receive a \(50 \%\) discount on the charges. It is estimated that the mean time taken for oil and lube service at this garage is 15 minutes per car and the standard deviation is \(2.4\) minutes. Suppose the time taken for oil and lube service on a car follows a normal distribution. a. What percentage of the customers will receive the \(50 \%\) discount on their charges? b. Is it possible that a car may take longer than 25 minutes for oil and lube service? Explain

Briefly describe the standard normal distribution curve.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.