/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 94 The probability that any given p... [FREE SOLUTION] | 91Ó°ÊÓ

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The probability that any given person is allergic to a certain drug is .03. What is the probability that none of three randomly selected persons is allergic to this drug? Assume that all three persons are independent.

Short Answer

Expert verified
The probability that none of three randomly selected persons is allergic to this drug, assuming that they are independent, is approximately 91.27%.

Step by step solution

01

Understand given information

The question states that the probability for any given person to be allergic to a certain drug is 0.03. Since we are searching for the probability that a person is not allergic, we must subtract this probability from 1. Therefore, the probability that any given person is not allergic is given as \(1 - 0.03 = 0.97\).
02

Determine the probability for multiple independent events

We want to know the probability that none of three randomly selected persons is allergic to the drug. Since the persons are picked independently from one another, we calculate the joint probability as the product of the individual probabilities. Therefore, the probability that none of three people is allergic is given as \(0.97 * 0.97 * 0.97\).
03

Calculate the final result

Now, it's just a matter of calculation. Multiplying the numbers gives us the final probability \(0.97 * 0.97 * 0.97 = 0.912673\) or approximately \(91.27\%\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
In probability, when we say events are independent, it means the outcome of one event does not affect the outcome of another. This is crucial for determining probabilities in situations where multiple events are involved.
For example, when selecting three people to check for allergy, each person has a standalone probability of being allergic or not. The allergy status of one person doesn't alter the probability for the others.
This independence allows us to calculate the overall probability with a straightforward rule: multiply the probabilities of each event. In our case, the probability that none of the three people are allergic is calculated by multiplying their individual probabilities of not being allergic. This is because each person contributes independently to the overall event of "none being allergic".
Joint Probability
Joint probability refers to the likelihood of two or more events occurring at the same time. When events are independent, as explained before, finding their joint probability becomes a simple task.
We multiply the probabilities of each event together to get the joint probability. This is under the assumption that each event is unaffected by the others. In practical terms, if we have Person 1, Person 2, and Person 3, each has a probability of 0.97 of not being allergic. To find the joint probability that all three are not allergic, we perform the calculation: \[ P( ext{None allergic}) = 0.97 \times 0.97 \times 0.97 \] This equation showcases the principle of joint probability for independent events. It simplifies complex scenarios into manageable multiplication tasks, offering insights into combined outcomes.
Complementary Probability
Complementary probability is about considering the opposite scenario of an event. It revolves around the idea that for any event with probability \( P(A) \), the event not happening, which we call the complement, has a probability of \( 1 - P(A) \).
This concept helps us figure out situations where we’re more interested in the event not happening. For instance, if the probability of a person being allergic is 0.03, then the probability of the same person not being allergic is its complement: 0.97.
Understanding complementary probabilities is handy for scenarios like determining the chance that none of the selected persons are allergic. By focusing on the probability of them not being allergic, we're inherently applying the concept of complementary probability to grasp these odds clearly.

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Most popular questions from this chapter

The probability of a student getting an A grade in an economics class is \(.24\) and that of getting a B grade is \(.28\). What is the probability that a randomly selected student from this class will get an \(\mathrm{A}\) or a \(\mathrm{B}\) in this class? Explain why this probability is not equal to \(1.0\)

A statistical experiment has eight equally likely outcomes that are denoted by \(1,2,3,4,5,6,7\), and 8\. Let event \(A=\\{2,5,7\\}\) and event \(B=\\{2,4,8\\}\). a. Are events \(A\) and \(B\) mutually exclusive events? b. Are events \(A\) and \(B\) independent events? c. What are the complements of events \(A\) and \(B\), respectively, and their probabilities?

A gambler has given you two jars and 20 marbles. Of these 20 marbles, 10 are red and 10 are green You must put all 20 marbles in these two jars in such a way that each jar must have at least one marble in it. Then a friend of yours, who is blindfolded, will select one of the two jars at random and then will randomly select a marble from this jar. If the selected marble is red, you and your friend win \(\$ 100\) a. If you put 5 red marbles and 5 green marbles in each jar, what is the probability that your friend selects a red marble? b. If you put 2 red marbles and 2 green marbles in one jar and the remaining marbles in the other jar, what is the probability that your friend selects a red marble? c. How should these 20 marbles be distributed among the two jars in order to give your friend the highest possible probability of selecting a red marble?

In a political science class of 35 students, 21 favor abolishing the electoral college and thus electing the President of the United States by popular vote. If two students are selected at random from this class, what is the probability that both of them favor abolition of the electoral college? Draw a tree diagram for this problem.

Two thousand randomly selected adults were asked if they think they are financially better off than their parents. The following table gives the two- way classification of the responses based on the education levels of the persons included in the survey and whether they are financially better off, the same as. or worse off than their parents. $$\begin{array}{lccc} \hline & \begin{array}{c} \text { Less Than } \\ \text { High School } \end{array} & \begin{array}{c} \text { High } \\ \text { School } \end{array} & \begin{array}{c} \text { More Than } \\ \text { High School } \end{array} \\ \hline \text { Better off } & 140 & 450 & 420 \\ \text { Same as } & 60 & 250 & 110 \\ \text { Worse off } & 200 & 300 & 70 \end{array}$$ Suppose one adult is selected at random from these 2000 adults. Find the following probabilities. a. \(P(\) better off or high school \()\) b. \(P(\) more than high school or worse off \()\) c. \(P\) (better off or worse off)

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