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A statistical experiment has eight equally likely outcomes that are denoted by \(1,2,3,4,5,6,7\), and 8\. Let event \(A=\\{2,5,7\\}\) and event \(B=\\{2,4,8\\}\). a. Are events \(A\) and \(B\) mutually exclusive events? b. Are events \(A\) and \(B\) independent events? c. What are the complements of events \(A\) and \(B\), respectively, and their probabilities?

Short Answer

Expert verified
Events A and B are not mutually exclusive nor independent events. The complements of events A and B are\{1,3,4,6,8\} and \{1,3,5,6,7\} respectively, both with a probability of \(\frac{5}{8}\).

Step by step solution

01

Check for mutually exclusive events

Mutually exclusive events are those where if one event happens, the other cannot. Here, both events A and B have a common number which is 2. Hence, they are not mutually exclusive.
02

Determine if the events are independent

Two events are independent if the probability of both events happening is the product of their individual probabilities. Here, probability of A is \(\frac{3}{8}\) and B is \(\frac{3}{8}\). Their intersection is one number, 2, hence the probability is \(\frac{1}{8}\). Since \(\frac{3}{8} * \frac{3}{8} \neq \frac{1}{8}\), they are not independent.
03

Calculate event complements and their probabilities.

The complement of an event is the set of all outcomes that are not in the event. The complement of event A, denoted as \(A'\), and B, denoted as \(B'\), are hence: \(A=\{1,3,4,6,8\}\) and \(B=\{1,3,5,6,7\}\). The probability of an event's complement is 1 minus the event's probability. Hence, \(P(A') = 1 - P(A) = \frac{5}{8}\) and \(P(B') = 1 - P(B) = \frac{5}{8}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mutually Exclusive Events
Mutually exclusive events refer to situations where the occurrence of one event means the other cannot happen at the same time. Think of them as events that completely "block" each other out. For example, if you flip a coin, getting a "Heads" means you cannot get a "Tails" simultaneously. They can't both occur together.
In the original exercise, we looked at two events: \( A = \{2, 5, 7\} \) and \( B = \{2, 4, 8\} \). If these events were mutually exclusive, it would mean they have no outcomes in common. However, since both events share the number 2, they are not mutually exclusive.
This means that both events can happen at the same time, at least partially. Understanding if events are mutually exclusive helps avoid mistakes in probability calculations, especially when determining the combined probability of multiple events.
Independent Events
In probability theory, independent events are events where the occurrence of one event does not affect the probability of the other. They are separate and do not influence each other, like two simultaneous dice rolls.
For events to be independent, the combined probability should be the product of their individual probabilities. For the given events \( A \) and \( B \), we calculate as follows:
  • Probability of A, \( P(A) = \frac{3}{8} \)
  • Probability of B, \( P(B) = \frac{3}{8} \)
  • The probability of both A and B occurring (intersection) is \( \frac{1}{8} \)
If they were independent, it should satisfy this equality: \( P(A) \times P(B) = \frac{3}{8} \times \frac{3}{8} = \frac{9}{64} \), which is not equal to \( \frac{1}{8} \).
Thus, events A and B are not independent. Realizing this helps in proper probabilistic modeling, ensuring more accurate predictions in complex scenarios.
Complementary Events
Complementary events are like two pieces of a puzzle that together make up the whole picture of possible outcomes. When one event occurs, its complement doesn't, and vice versa.
For any event, its complement consists of all outcomes that are not in the original event. Consider events \( A \) and \( B \) again:
  • The complement of \( A \), noted as \( A' \), includes outcomes not in A, thus \( A' = \{1, 3, 4, 6, 8\} \)
  • Similarly, the complement of \( B \) is \( B' = \{1, 3, 5, 6, 7\} \)
To find the probability of these complements, remember: the sum of the probabilities of an event and its complement is always 1.
So, the probability of a complement event is \( P(A') = 1 - P(A) = \frac{5}{8} \) and \( P(B') = 1 - P(B) = \frac{5}{8} \). Knowing how to calculate complements is useful because it can sometimes be easier than directly calculating the event probability itself.

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Most popular questions from this chapter

A player plays a roulette game in a casino by betting on a single number each time. Because the wheel has 38 numbers, the probability that the player will win in a single play is \(1 / 38\). Note that each play of the game is independent of all previous plays a. Find the probability that the player will win for the first time on the 10 th play. b. Find the probability that it takes the player more than 50 plays to win for the first time c. The gambler claims that because he has 1 chance in 38 of winning each time he plays, he is certain to win at least once if he plays 38 times. Does this sound reasonable to you? Find the probability that he will win at least once in 38 plays

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