/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 The following data set belongs t... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 3: Problem 9

The following data set belongs to a population: \(\begin{array}{llllllll}5 & -7 & 2 & 0 & -9 & 16 & 10 & 7\end{array}\)

Short Answer

Expert verified
The Mean is 3, Median is 3.5, there is no Mode and the Range is 25.

Step by step solution

01

Compute the Mean

The Mean or average of a data set is found by adding all numbers in the data set and then dividing by the number of values in the set.\n Mean = \( \frac{(5 + -7 + 2 + 0 + -9 + 16 + 10 + 7)}{8} = 3 \)
02

Compute the Median

The Median is the middle value. To find the Median you have to put the numbers in order from smallest to largest. If the data set has an odd number, the median is the middle number. If the data set has an even number, the median is the average of the two middle numbers. So, first, put the numbers in order: -9, -7, 0, 2, 5, 7, 10, 16.Median = \( \frac{(2 + 5)}{2} = 3.5 \)
03

Compute the Mode

The Mode is the number that appears most often. If no number is repeated, then there is no mode for the list. In this case, no number is repeated so, there is no mode.
04

Compute the Range

The Range is the difference between the lowest and highest values. So, Range = Highest Value - Lowest Value. Range = 16 - (-9) = 25

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The following data give the numbers of pieces of junk mail received by 10 families during the past month. \(\begin{array}{llllllllll}41 & 33 & 28 & 21 & 29 & 19 & 14 & 31 & 39 & 36\end{array}\) Find the range, variance, and standard deviation.

The following data give the numbers of hours spent partying by 10 randomly selected college students during the past week. \(\begin{array}{lllllllllll}7 & 1 & 45 & 0 & 9 & 7 & 1 & 04 & 0 & 8\end{array}\) Compute the range, variance, and standard deviation.

The mean time taken to learn the basics of a word processor by all students is 200 minutes with a standard deviation of 20 minutes. a. Using Chebyshev's theorem, find at least what percentage of students will learn the basics of this word processor in i. 160 to 240 minutes ii. 140 to 260 minutes \({ }^{*}\) b. Using Chebyshev's theorem, find the interval that contains the time taken by at least \(75 \%\) of all students to learn this word processor.

Can the standard deviation have a negative value? Explain.

Answer the following questions a. The total weight of all pieces of luggage loaded onto an airplane is 12,372 pounds, which works out to be an average of \(51.55\) pounds per piece. How many pieces of luggage are on the plane? b. A group of seven friends, having just gotten back a chemistry exam, discuss their scores. Six of the students reveal that they received grades of \(81,75,93,88,82\), and 85, respectively, but the seventh student is reluctant to say what grade she received. After some calculation she announces that the group averaged 81 on the exam. What is her score?
See all solutions

Recommended explanations on Math Textbooks

Applied Mathematics

Read Explanation

Statistics

Read Explanation

Decision Maths

Read Explanation

Geometry

Read Explanation

Calculus

Read Explanation

Mechanics Maths

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.