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91Ó°ÊÓ

The following data give the numbers of hours spent partying by 10 randomly selected college students during the past week. \(\begin{array}{lllllllllll}7 & 1 & 45 & 0 & 9 & 7 & 1 & 04 & 0 & 8\end{array}\) Compute the range, variance, and standard deviation.

Short Answer

Expert verified
The range of the data is 45, the variance is 138.16, and the standard deviation is 11.75.

Step by step solution

01

Compute the Range

The range is calculated as the maximum value minus the minimum value. From the data, the maximum value is 45 and the minimum value is 0. So, Range = 45 - 0 = 45.
02

Compute the Variance

The variance is calculated as the mean of squared deviations from the mean. First, calculate the mean of the data set. The mean (x̄) = (7+1+45+0+9+7+1+4+0+8) / 10 = 8.2. Next, compute the deviations from the mean and square each deviation. Finally, calculate the mean of these squares to get the variance. Here, Variance (σ²) = [(7-8.2)² + (1-8.2)² + (45-8.2)² + (0-8.2)² + (9-8.2)² + (7-8.2)² + (1-8.2)² + (4-8.2)² + (0-8.2)² + (8-8.2)²] /10 = 138.16.
03

Compute the Standard Deviation

The standard deviation (σ) is the square root of the variance. So, σ = √138.16 = 11.75.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Range Calculation
The range in a set of numbers represents the spread between the smallest and the largest values, giving us an idea of how far apart the numbers are. It's one of the basic measures of dispersion in descriptive statistics.
To calculate the range, you simply identify the maximum and minimum values in your data set and subtract the minimum from the maximum.
  • Find the maximum value (the largest number in your set).
  • Find the minimum value (the smallest number in your set).
  • Subtract the minimum value from the maximum value.
In our example of hours spent partying, the range is calculated as 45 (maximum value) minus 0 (minimum value) which equals 45. This tells us there is a broad variability in how much time students spend partying.
Diving Into Variance Computation
Variance gives us insight into the degree of spread or dispersion in a data set. Unlike the range, which only considers the extreme values, variance takes into account how all the values in the set distribute themselves around the mean.
To compute the variance, follow these steps:
  • First, calculate the mean (average) of your data numbers. This is done by adding up all the numbers and dividing by the count of numbers.
  • Next, subtract the mean from each number to find the deviation of each number from the mean.
  • Square each of these deviations to eliminate any negative values and to emphasize larger deviations.
  • Finally, calculate the average of these squared deviations. This result is your variance.
In the aforementioned data, the mean is 8.2, and after calculating the squared deviations and their average, we arrive at a variance of 138.16. This value indicates how much the students' partying hours differ from the average.
Exploring Standard Deviation Calculation
The standard deviation is a related concept to variance; however, it provides a more intuitive sense of the spread of a data set because it is in the same units as the original data. By finding the square root of the variance, we bring the measure back to the original scale.
Here is how you calculate the standard deviation:
  • First, make sure you have the variance (we calculated this as 138.16).
  • Take the square root of the variance to find the standard deviation.
This step converts the variance into a more comprehensible value. In our problem, the square root of the variance (138.16) gives us a standard deviation of approximately 11.75. This means that, on average, the hours spent partying deviates by 11.75 hours from the mean. The lower the standard deviation, the closer the data points tend to be to the mean, suggesting less variability.

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Most popular questions from this chapter

Prepare a box-and-whisker plot for the following data: \(\begin{array}{llllllll}36 & 43 & 28 & 52 & 41 & 59 & 47 & 61 \\ 24 & 55 & 63 & 73 & 32 & 25 & 35 & 49 \\ 31 & 22 & 61 & 42 & 58 & 65 & 98 & 34\end{array}\)

According to an article in the Washington Post ( Washington Post, January 5, 2009), the average employee share of health insurance premiums at large U.S. companies is expected to be \(\$ 3423\) in \(2009 .\) Suppose that the current annual payments by all such employees toward health insurance premiums have a bell-shaped distribution with a mean of \(\$ 3423\) and a standard deviation of \(\$ 520\). Using the empirical rule, find the approximate percentage of employees whose annual payments toward such premiums are between a. \(\$ 1863\) and \(\$ 4983\) b. \(\$ 2903\) and \(\$ 3943\) c. \(\$ 2383\) and \(\$ 4463\)

Although the standard workweek is 40 hours a week, many people work a lot more than 40 hours a week. The following data give the numbers of hours worked last week by 50 people. \(\begin{array}{llllllllll}40.5 & 41.3 & 41.4 & 41.5 & 42.0 & 42.2 & 42.4 & 42.4 & 42.6 & 43.3 \\ 43.7 & 43.9 & 45.0 & 45.0 & 45.2 & 45.8 & 45.9 & 46.2 & 47.2 & 47.5 \\ 47.8 & 48.2 & 48.3 & 48.8 & 49.0 & 49.2 & 49.9 & 50.1 & 50.6 & 50.6 \\ 50.8 & 51.5 & 51.5 & 52.3 & 52.3 & 52.6 & 52.7 & 52.7 & 53.4 & 53.9 \\\ 54.4 & 54.8 & 55.0 & 55.4 & 55.4 & 55.4 & 56.2 & 56.3 & 57.8 & 58.7\end{array}\) a. The sample mean and sample standard deviation for this data set are \(49.012\) and \(5.080\), respectively. Using Chebyshev's theorem, calculate the intervals that contain at least \(75 \%, 88.89 \%\), and \(93.75 \%\) of the data. b. Determine the actual percentages of the given data values that fall in each of the intervals that you calculated in part a. Also calculate the percentage of the data values that fall within one standard deviation of the mean. c. Do you think the lower endpoints provided by Chebyshev's theorem in part a are useful for this problem? Explain your answer. d. Suppose that the individual with the first number (54.4) in the fifth row of the data is a workaholic who actually worked \(84.4\) hours last week and not \(54.4\) hours. With this change now \(\bar{x}=49.61\) and \(s=7.10\). Recalculate the intervals for part a and the actual percentages for part b. Did your percentages change a lot or a little? e. How many standard deviations above the mean would you have to go to capture all 50 data values? What is the lower bound for the percentage of the data that should fall in the interval, according to the Chebyshev theorem.

Refer to the data of Exercise \(3.109\) on the current annual incomes (in thousands of dollars) of the 10 members of the class of 2000 of the Metro Business College who were voted most likely to succeed. \(\begin{array}{llllllllll}59 & 68 & 84 & 78 & 107 & 382 & 56 & 74 & 97 & 60\end{array}\) a. Determine the values of the three quartiles and the interquartile range. Where does the value of 74 fall in relation to these quartiles? b. Calculate the (approximate) value of the 70 th percentile. Give a brief interpretation of this percentile. c. Find the percentile rank of 97 . Give a brief interpretation of this percentile rank.

Suppose that on a certain section of I-95 with a posted speed limit of \(65 \mathrm{mph}\), the speeds of all vehicles have a bell-shaped distribution with a mean of \(72 \mathrm{mph}\) and a standard deviation of \(3 \mathrm{mph}\). a. Using the empirical rule, find the percentage of vehicles with the following speeds on this section of I-95. i. 63 to \(81 \mathrm{mph}\) ii. 69 to \(75 \mathrm{mph}\) *b. Using the empirical rule, find the interval that contains the speeds of \(95 \%\) of vehicles traveling on this section of \(\mathrm{I}-95\).

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