/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 Use the following information to... [FREE SOLUTION] | 91影视

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Use the following information to answer the next seven exercises: Suppose that a recent article stated that the mean time spent in jail by a first-time convicted burglar is 2.5 years. A study was then done to see if the mean time has increased in the new century. A random sample of 26 first-time convicted burglars in a recent year was picked. The mean length of time in jail from the survey was three years with a standard deviation of 1.8 years. Suppose that it is somehow known that the population standard deviation is 1.5. Conduct a hypothesis test to determine if the mean length of jail time has increased. Assume the distribution of the jail times is approximately normal. In words, define the random variable for this test.

Short Answer

Expert verified
The random variable \( X \) is the mean time spent in jail by a first-time convicted burglar in years.

Step by step solution

01

Understand the Type of Test

This scenario involves comparing the sample mean with a known population mean, where the population standard deviation is given. This calls for a z-test for a single mean.
02

Define the Random Variable

The random variable here is the mean time spent in jail by a first-time convicted burglar. We define it as follows.
03

Express the Random Variable

Let the random variable \( X \) represent the mean time a first-time convicted burglar spends in jail in years.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
Hypothesis testing is a fundamental concept in statistics, used to make decisions or inferences about populations based on sample data. In the context of this exercise, we're interested in determining if the average jail time for first-time burglars has changed from a previously reported average.

To conduct a hypothesis test, we begin by setting up two competing hypotheses:
  • The null hypothesis (\( H_0 \)) assumes that the mean jail time has not changed, meaning it is still 2.5 years.
  • The alternative hypothesis (\( H_a \)) suggests that the mean jail time has increased.
The decision on which hypothesis is supported depends on the test statistic calculated from the sample data. A z-test is suitable here because we know the population standard deviation and the sample size is relatively large (26).

We calculate a z-statistic and compare it to a critical value from the z-distribution table to make our decision. If the test statistic is greater than the critical value, we reject the null hypothesis in favor of the alternative.
Sample Mean
The sample mean is a crucial part of hypothesis testing as it provides an estimate of the population mean. In our exercise, a random sample of 26 first-time convicted burglars was selected, yielding a sample mean jail time of 3 years.

The sample mean serves as a summary statistic that helps us understand the dataset. It is calculated by averaging the values in the sample, providing a point estimate of the population parameter we are interested in, which is the mean jail time in this case.

Because the theoretical sample mean is computed from individual jail times, it inherently includes some level of random variation common in samples. This variation is taken into account when performing the z-test, where the sample mean is compared against the known population mean (2.5 years in this context).

This comparison allows us to assess whether any observed difference could be due to chance or evidence of an actual change in the mean jail time.
Population Mean
The population mean is a parameter representing the central tendency of a distribution. In this exercise, the population mean we are comparing to is given as 2.5 years, which is the reported average jail time for first-time convicted burglars.

Unlike the sample mean, which is calculated directly from sample data, the population mean is often unknown in real-world scenarios and must be inferred from sample data unless specified. Here, it acts as the baseline in our hypothesis test to determine whether the current mean time has statistically increased.

Understanding the concept of a population mean is integral when conducting hypothesis tests. It frames our expectations and points of comparison. By comparing our sample mean (3 years) with this benchmark, we are able to test our hypothesis that the mean jail time has increased.
Population Standard Deviation
The population standard deviation is a measure of the dispersion or spread of data points in a population. It provides insight into the variability of the data.

In this exercise, the known population standard deviation is 1.5 years. This value is crucial for the z-test calculation as it provides a standard measure to estimate the standard error of the sample mean.

The calculation of the standard error is vital in hypothesis testing because it affects the test statistic. The formula used in a z-test incorporates the population standard deviation, making it possible to standardize the difference between the sample mean and the population mean. Doing this allows us to interpret the result based on a standardized z-distribution.

Thus, the population standard deviation enables us to evaluate whether a sample provides evidence of a significant difference from a known population mean. By incorporating this measure, the hypothesis test can be more accurately assessed for statistical significance.

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Most popular questions from this chapter

A population has a mean is 25 and a standard deviation of five. The sample mean is 24, and the sample size is 108. What distribution should you use to perform a hypothesis test?

"Japanese Girls鈥 Names" by Kumi Furuichi It used to be very typical for Japanese girls鈥 names to end with 鈥渒o.鈥 (The trend might have started around my grandmothers鈥 generation and its peak might have been around my mother鈥檚 generation.) 鈥淜o鈥 means 鈥渃hild鈥 in Chinese characters. Parents would name their daughters with 鈥渒o鈥 attaching to other Chinese characters which have meanings that they want their daughters to become, such as Sachiko鈥攈appy child, Yoshiko鈥攁 good child, Yasuko鈥攁 healthy child, and so on. However, I noticed recently that only two out of nine of my Japanese girlfriends at this school have names which end with 鈥渒o.鈥 More and more, parents seem to have become creative, modernized, and, sometimes, westernized in naming their children. I have a feeling that, while 70 percent or more of my mother鈥檚 generation would have names with 鈥渒o鈥 at the end, the proportion has dropped among my peers. I wrote down all my Japanese friends鈥, ex-classmates鈥, co-workers, and acquaintances鈥 names that I could remember. Following are the names. (Some are repeats.) Test to see if the proportion has dropped for this generation. Ai, Akemi, Akiko, Ayumi, Chiaki, Chie, Eiko, Eri, Eriko, Fumiko, Harumi, Hitomi, Hiroko, Hiroko, Hidemi, Hisako, Hinako, Izumi, Izumi, Junko, Junko, Kana, Kanako, Kanayo, Kayo, Kayoko, Kazumi, Keiko, Keiko, Kei, Kumi, Kumiko, Kyoko, Kyoko, Madoka, Maho, Mai, Maiko, Maki, Miki, Miki, Mikiko, Mina, Minako, Miyako, Momoko, Nana, Naoko, Naoko, Naoko, Noriko, Rieko, Rika, Rika, Rumiko, Rei, Reiko, Reiko, Sachiko, Sachiko, Sachiyo, Saki, Sayaka, Sayoko, Sayuri, Seiko, Shiho, Shizuka, Sumiko, Takako, Takako, Tomoe, Tomoe, Tomoko, Touko, Yasuko, Yasuko, Yasuyo, Yoko, Yoko, Yoko, Yoshiko, Yoshiko, Yoshiko, Yuka, Yuki, Yuki, Yukiko, Yuko, Yuko.

The National Institute of Mental Health published an article stating that in any one-year period, approximately 9.5 percent of American adults suffer from depression or a depressive illness. Suppose that in a survey of 100 people in a certain town, seven of them suffered from depression or a depressive illness. Conduct a hypothesis test to determine if the true proportion of people in that town suffering from depression or a depressive illness is lower than the percent in the general adult American population. a. Is this a test of one mean or proportion? b. State the null and alternative hypotheses. \(H_{0} : \qquad \qquad \qquad H_{a} :\) c. Is this a right-tailed, left-tailed, or two-tailed test? d. What symbol represents the random variable for this test? e. In words, define the random variable for this test. f. Calculate the following: $$ \begin{array}{l}{\text { i. } x=} \\ {\text { ii. } \quad n=} \\ {\text { iil. } p^{\prime}=}\end{array} $$ g. Calculate \(\sigma_{x}=\qquad .\) Show the formula set-up. h. State the distribution to use for the hypothesis test. i. Find the \(p\) -value. j. At a pre-conceived \(\alpha=0.05,\) what is your: i. Decision: ii. Reason for the decision: iii. Conclusion (write out in a complete sentence):

If you do not reject the null hypothesis, then it must be true. Is this statement correct? State why or why not in complete sentences.

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