Chapter 7: Problem 81
The time to wait for a particular rural bus is distributed uniformly from zero to 75 minutes. One hundred riders are randomly sampled to learn how long they waited. The \(90^{\text { th }}\) percentile sample average wait time (in minutes) for a sample of 100 riders is: a. 315.0 b. 40.3 c. 38.5 d. 65.2
Short Answer
Step by step solution
Identify Distribution and Parameters
Determine Properties of Sample Mean
Use Central Limit Theorem
Calculate the 90th Percentile of Sample Mean
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Central Limit Theorem
In this case, even though the original data follows a uniform distribution, the sample mean of these data points will form a normal distribution thanks to the CLT. Here are the key points to remember:
- The CLT applies to sample sizes generally 30 or greater.
- The mean of this new distribution of sample means () will be the same as the population mean .
- The standard deviation of the sample mean, also called the standard error, is the population standard deviation divided by the square root of the sample size (/n).
Sample Mean
- Formula for sample mean: \( \bar{x} = \frac{1}{n} \sum_{i=1}^{n} x_i \)
- This is different from a median, which is the middle value, and mode, which is the most frequently occurring value.
- In our context, the uniform distribution over 0 to 75 minutes gives us an expected sample mean of 37.5 minutes.