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91Ó°ÊÓ

The distribution of results from a cholesterol test has a mean of 180 and a standard deviation of 20. A sample size of 40 is drawn randomly. Find the sum that is one standard deviation above the mean of the sums.

Short Answer

Expert verified
7326.4

Step by step solution

01

Identify the known parameters

We are given that the mean of the cholesterol levels is 180, and the standard deviation is 20. The sample size is 40. These are the main parameters we will use in our calculations.
02

Calculate the mean of the sample sums

The mean of the sample sums can be calculated by multiplying the mean of the population by the sample size. Therefore, \[ \text{mean of sums} = 180 \times 40 = 7200. \]
03

Determine the standard deviation of the sample sums

The standard deviation of the sample sums is calculated by multiplying the population's standard deviation by the square root of the sample size. This is given by,\[ \text{standard deviation of sums} = 20 \times \sqrt{40}. \] Evaluating this gives,\[ 20 \times 6.32 = 126.4. \]
04

Calculate the sum one standard deviation above the mean of the sums

Add the standard deviation of the sample sums to the mean of the sample sums: \[ \text{sum} = 7200 + 126.4 = 7326.4. \]
05

Conclusion

Thus, the sum that is one standard deviation above the mean of the sums is 7326.4.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean of Sums
When dealing with sums of random variables, especially large samples, the Central Limit Theorem plays a crucial role. This theorem states that the distribution of the sum of a large number of independent, identically distributed variables will be approximately normal. To find the mean of the sums, we multiply the mean of the individual population by the sample size. For instance, in the cholesterol test example, the mean level is 180. Hence, for a sample size of 40, the mean of samples is calculated as:
  • Mean of Sums = 180 (mean) × 40 (sample size) = 7200.
This gives the central point around which the sums of all samples are distributed. It is essential to understand this concept as it determines the expected behavior of the aggregated data in larger samples.
Standard Deviation of Sums
The standard deviation of the sums tells us how much the sums are expected to vary around their mean. For the sums of samples, it is calculated by
  • multiplying the standard deviation of the individual values by the square root of the sample size.
In our cholesterol test scenario, the standard deviation is given as 20. Thus, the formula looks like this:
  • Standard Deviation of Sums = 20 × \( \sqrt{40} \).
  • Evaluating this gives approximately 126.4.
This value shows us the expected spread or dispersion of the sum of the sample around its mean. The larger this value, the broader the range of possible sums we expect.
Sample Size Effect
Sample size has a profound effect on both the mean and the standard deviation of sums. Generally, as the sample size increases, the sums become more stable due to the Central Limit Theorem.
  • Larger sample sizes lead to smaller standard errors.
  • This means less variability and a tighter interval around the mean of sums.
In our exercise, a sample size of 40 balances providing a robust average and managing variability. The concept here is crucial for understanding why larger samples give more reliable estimates of population parameters. They tend to normalize irregularities that might occur in smaller samples, providing more precise and dependable analysis results.

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Most popular questions from this chapter

Suppose in a local Kindergarten through \(12^{\text { th }}\) grade \((\mathrm{K}-12)\) school district, 53 percent of the population favor a charter school for grades \(\mathrm{K}\) through five. A simple rample of 300 is surveyed. Callowing using the normal approximation to the binomial distribtion. a. Find the probability that less than 100 favor a charter school for grades K through 5. b. Find the probability that 170 or more favor a charter school for grades K through 5. c. Find the probability that no more than 140 favor a charter school for grades K through 5. d. Find the probability that there are fewer than 130 that favor a charter school for grades K through 5. e. Find the probability that exactly 150 favor a charter school for grades K through 5.

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