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Use the following information to answer the next ten exercises. A customer service representative must spend different amounts of time with each customer to resolve various concerns. The amount of time spent with each customer can be modeled by the following distribution: \(X \sim Exp(0.2)\) Are outcomes equally likely in this distribution? Why or why not?

Short Answer

Expert verified
No, outcomes are not equally likely. In exponential distribution, shorter times are more likely than longer ones.

Step by step solution

01

Recognizing the Distribution

The given distribution is an exponential distribution, denoted by \(X \sim Exp(0.2)\). This means the time spent on each customer follows an exponential distribution with a rate parameter \(\lambda = 0.2\).
02

Understanding Exponential Distribution

An exponential distribution is continuous and designed to model the time until an event occurs, where the event in question is often a type of 'failure' or occurrence, like servicing a customer. In this distribution, the rate \(\lambda\) is a crucial parameter.
03

Evaluating Likelihood of Outcomes

In an exponential distribution, outcomes are not equally likely. The probability of outcomes decreases exponentially with time, meaning shorter times are more probable than longer times. The probability density function (pdf) for an exponential distribution is \(f(x) = \lambda e^{-\lambda x}\) for \(x \geq 0\).
04

Conclusion on Equal Likelihood

Since the exponential distribution is characterized by a decreasing probability density function, outcomes closer to zero have a higher probability compared to distant times. Therefore, not all outcomes are equally likely in this exponential distribution, contrasting with a uniform distribution where outcomes are equally likely.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Parameter
In exponential distributions, the rate parameter, often denoted by \( \lambda \), is a fundamental component. It defines the rate or speed at which the exponential function decreases. A higher value of \( \lambda \) means the exponential function decreases more rapidly. This is essential for modeling scenarios that involve time measurements, such as the time between customer service requests.

The rate parameter helps determine how frequent or infrequent certain times or outcomes are likely to occur. In our example with \( \lambda = 0.2\), it suggests a relatively slow decrease, indicating that longer waiting times might not be as improbable as if \( \lambda \) were larger. Thus, \( \lambda \) directly affects the expected value or mean of the distribution, calculated as \( \frac{1}{\lambda} \).

To put it simply, the rate parameter \( \lambda \) is central to understanding how quickly probabilities decline as time increases in an exponential distribution.
Probability Density Function
The probability density function (pdf) of the exponential distribution describes the likelihood of various outcomes. It is defined as \( f(x) = \lambda e^{-\lambda x} \) for \( x \geq 0 \). This function tells us how probabilities are distributed across different values.

One critical aspect of the exponential pdf is that it is always positive and decreases over time. This results in a higher probability of observing short-duration events compared to long ones. For example, resolving customer issues may often take less time than more extensive troubleshooting tasks, a behavior neatly captured by the pdf’s form.

It's also important to understand that the area under the pdf curve equals 1, which reflects that we are measuring probability across all possible times. This characteristic helps ensure that the distribution's descriptions align with real-world scenarios.
Continuous Distribution
Exponential distribution is a type of continuous distribution, which means it deals with continuous data. Unlike discrete distributions, which work with countable events like the number of times a die lands on a six, continuous distributions can account for an infinite number of outcomes within a range.

In the context of an exponential distribution used to model event timing, continuous data means that we can have precise measurements of time, such as seconds, minutes, or even partial fractions of a second. It does not restrict to just whole numbers.

Continuous distributions are useful when precision matters, and for modeling real-life phenomena that do not happen at distinct intervals, exponential distribution being one exemplary application. Thus, if tasked to model something with countless possible outcomes in measurement, a continuous distribution like exponential is apt.

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Most popular questions from this chapter

Use the following information to answer the next ten questions. The data that follow are the square footage (in 1,000 feet squared) of 28 homes. $$\begin{array}{|c|c|c|c|c|c|c|}\hline 1.5 & {2.4} & {3.6} & {2.6} & {1.6} & {2.4} & {2.0} \\ \hline 3.5 & {2.5} & {1.8} & {2.4} & {2.5} & {3.5} & {4.0} \\\ \hline 2.6 & {1.6} & {2.2} & {1.8} & {3.8} & {2.5} & {1.5} \\\\\hline {2.8}&{1.8} &{4.5}&{1.9} &{1.9}& {3.1}& {1.6}\\\\\hline\end{array}$$ $$\text{Table 5.4}$$ The sample mean \(=2.50\) and the sample standard deviation \(=0.8302.\) The distribution can be written as \(X \sim U(1.5,4.5).\) Graph \(P(2 < x < 3)\)

Use the following information to answer the next ten exercises. A customer service representative must spend different amounts of time with each customer to resolve various concerns. The amount of time spent with each customer can be modeled by the following distribution: \(X \sim Exp(0.2)\) Find the \(70^{\text { th }}\) percentile.

\(f(x)\) for a continuous probability function is \(\frac{1}{5},\) and the function is restricted to \(0 \leq x \leq 5 .\) What is \(P(x < 0) ?\)

\(f(x),\) a continuous probability function, is equal to \(\frac{1}{3}\) and the function is restricted to \(1 \leq x \leq 4 .\) Describe \(P\left(x > \frac{3}{2}\right)\)

For each probability and percentile problem, draw the picture. According to a study by Dr. John McDougall of his live-in weight loss program at St. Helena Hospital, the people who follow his program lose between six and 15 pounds a month until they approach trim body weight. Let’s suppose that the weight loss is uniformly distributed. We are interested in the weight loss of a randomly selected individual following the program for one month. a. Define the random variable. X = _________ b. X ~ _________ c. Graph the probability distribution. d. f(x) = _________ e. ? = _________ f. ? = _________ g. Find the probability that the individual lost more than ten pounds in a month. h. Suppose it is known that the individual lost more than ten pounds in a month. Find the probability that he lost less than 12 pounds in the month. i. P(7 < x < 13|x > 9) = __________. State this in a probability question, similarly to parts g and h, draw the picture, and find the probability.

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