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A theater group holds a fund-raiser. It sells 100 raffle tickets for \(\$ 5\) apiece. Suppose you purchase four tickets. The prize is two passes to a Broadway show, worth a total of \(\$ 150\). a. What are you interested in here? b. In words, define the random variable \(X.\) c. List the values that X may take on. d. Construct a PDF. e. If this fund-raiser is repeated often and you always purchase four tickets, what would be your expected average winnings per raffle?

Short Answer

Expert verified
The expected average winnings per raffle are \(\$6\).

Step by step solution

01

Define the purpose

In this problem, we're interested in understanding the outcomes related to purchasing raffle tickets and determining the probability distribution and expected winnings from these tickets.
02

Define the Random Variable

The random variable \(X\) represents the winnings from purchasing four raffle tickets. Therefore, \(X\) can take on values based on whether you win the prize or not.
03

Determine Potential Winnings

Since there are 100 tickets, and you hold 4, the probability of winning the prize (worth \(\$150\)) is \(\frac{4}{100} = 0.04\). If you win, \(X = 150\). If you do not win, \(X = 0\).
04

Construct the PDF

A Probability Density Function (PDF) describes the probabilities of outcomes for \(X\):- \(P(X = 150) = 0.04\)- \(P(X = 0) = 1 - 0.04 = 0.96\).
05

Calculate Expected Winnings

The expected value \(E(X)\) is calculated as the sum of each outcome multiplied by its probability: \[ E(X) = (150 \times 0.04) + (0 \times 0.96) = 6 \].So, on average, you would "win" \(\$6\) each time.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variable
In probability and statistics, a random variable is a fundamental concept that simplifies complex real-world scenarios into understandable numeric outcomes. It's a variable whose possible values are numerical outcomes of random phenomena. For instance, in the context of the raffle tickets scenario, the random variable \(X\) is defined as your winnings when purchasing four tickets. The variable \(X\) is "random" because it can yield several possible outcomes depending on the event (whether you win or not).
The values \(X\) can adopt are determined by the number of tickets purchased relative to the total tickets sold and whether they result in a winning ticket. Here, your winnings if you purchase four raffle tickets can be either \(\\(0\) (if none of your tickets win) or \(\\)150\) (if one of the tickets wins the prize). Defining \(X\) helps in analyzing the situation by reducing it to numeric values that can be worked with to calculate probabilities and expectations.
Expected Value
Expected value essentially provides you with an average outcome of a random variable if you were to repeat an experiment multiple times. It combines results and their corresponding probabilities into a single metric.
In the case of the raffle tickets, the expected value \(E(X)\) of your winnings is a figure that indicates what you can expect, on average, to win from your tickets. This is computed by multiplying each possible outcome by its probability and summing these products together. For example, if you win \(\\(150\) with a probability of \(0.04\) and win \(\\)0\) with a probability of \(0.96\), the expected value is calculated as follows:
  • \(E(X) = (150 \times 0.04) + (0 \times 0.96) = 6\)
This means, over many repetitions of the fund-raiser where you always buy four tickets, your "average" winnings will be \(\$6\) per raffle. Understanding expected value is essential because it gives insight into the profitability or expected gain/loss of an event over the long term.
Probability Density Function
A Probability Density Function (PDF) is a tool that describes the likelihood of a random variable assuming particular values. It's a way to represent the distribution of probabilities for all possible outcomes of a random variable.
Let's consider the raffle ticket example. Here, the PDF is used to illustrate the probabilities associated with your winnings being \(\\(150\) or \(\\)0\). Specifically, it is noted in the PDF that:
  • \(P(X = 150) = 0.04\)
  • \(P(X = 0) = 0.96\)
This shows how likely each outcome is, thus enabling you to visualize and make informed decisions about the situation in question. In this raffle case, the PDF conveys that although there's a small chance for a large win, the probability of not winning (and thus receiving \(\$0\)) is quite high. PDFs are indispensable in both academic studies and practical applications involving uncertainty and risks.

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