/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Use the following information to... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the following information to answer the next two exercises. You see a game at a local fair. You have to throw a dart at a color wheel. Each section on the color wheel is equal in area. Let B = the event of landing on blue. Let R = the event of landing on red. Let G = the event of landing on green. Let Y = the event of landing on yellow. If you land on Y, you get the biggest prize. Find P(Y).

Short Answer

Expert verified
The probability of landing on yellow, \(P(Y)\), is \(\frac{1}{4}\).

Step by step solution

01

Understand the Problem

The problem involves a color wheel at a fair, where each section is equal in area. We need to calculate the probability of landing on yellow, which is denoted as event Y. The problem does not specify the number of sections, so we assume each color has an equal likelihood.
02

Determine Total Possible Outcomes

Since each section on the wheel is equal in area and the problem mentions four colors (B, R, G, Y), we infer that there are four equal sections or outcomes. The total number of possible outcomes when throwing a dart is 4.
03

Determine Favorable Outcomes for Landing on Yellow (Y)

The favorable outcome for event Y, landing on yellow, is just one section out of the total sections mentioned: B, R, G, and Y. So, there is 1 favorable outcome for Y.
04

Calculate the Probability of Landing on Yellow (P(Y))

The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. Thus, the probability is calculated as follows: \[ P(Y) = \frac{\text{Number of favorable outcomes for } Y}{\text{Total possible outcomes}} = \frac{1}{4} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equal Sections
In probability, especially in games of chance, understanding equal sections of a setup is crucial. The concept of equal sections means that each part of a setup, such as a color wheel, has an identical area or size. This ensures that each section has an equal chance of being selected. In our dart game example, the color wheel comprises segments for different colors like blue (B), red (R), green (G), and yellow (Y). Each section on the wheel is equal, meaning the dart can land on any color with the same likelihood.

This concept of equal sections is foundational in calculating simple probabilities. If each section were not equal, then some outcomes would have a higher or lower probability, complicating the calculation process. However, in our scenario, you don't need to think about that complexity. Just remember, equal sections pave the way for fair calculations.
Favorable Outcomes
When calculating probabilities, it's essential to recognize which outcomes are favorable for the event you're interested in. A favorable outcome is a specific event or events that we're focusing on in a probability problem. In the dart game, the favorable outcome is landing on yellow (Y), as that's how you win the biggest prize.

Since the wheel is divided into four equal parts, and the event we focus on is the yellow section, this section is our sole favorable outcome. There’s just 1 favorable outcome out of the 4 possible.

Favorable outcomes are what you count on for an event to occur. The more favorable outcomes there are relative to total outcomes, the higher the probability of the event.
Calculate Probability
Calculating probability is straightforward when you understand the principles of favorable and possible outcomes. Probability measures the chance of a specific event happening out of all possible outcomes. It's expressed as a fraction. First, you count how many outcomes lead to success (favorable outcomes) and then you count all possible outcomes.

Use the formula: \[ P( ext{Event}) = \frac{\text{Number of favorable outcomes}}{\text{Total possible outcomes}} \] Applying this to our example: - There is 1 favorable outcome (landing on yellow)- There are 4 total possible outcomes (B, R, G, Y) Thus: \[ P(Y) = \frac{1}{4} \] This means there's a 25% chance of landing on the yellow section.
Probability of an Event
The probability of an event is a mathematical concept that represents the likelihood of a particular outcome occurring. You assess this likelihood based on dividing favorable outcomes by all possible outcomes. For instance, the probability of landing on yellow (event Y) when throwing a dart at the fair involves specifically one favorable outcome.

This concept extends beyond games and is fundamental in everyday decision-making, science, and various forms of analysis. Probability - Can be expressed in fractions, decimals, or percentages - Helps us make predictions about various events - Always ranges from 0 (impossible event) to 1 (certain event) In our exercise, the choice of a dart randomly landing on yellow illustrates a simple but effective way to practice determining the probability of an event.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the following information to answer the next ten exercises. On a baseball team, there are infielders and outfielders. Some players are great hitters, and some players are not great hitters. Let I = the event that a player in an infielder. Let O = the event that a player is an outfielder. Let H = the event that a player is a great hitter. Let N = the event that a player is not a great hitter Write the symbols for the probability that of all the outfielders, a player is not a great hitter.

Use the following information to answer the next six exercises. A jar of 150 jelly beans contains 22 red jelly beans, 38 yellow, 20 green, 28 purple, 26 blue, and the rest are orange. Let B = the event of getting a blue jelly bean Let G = the event of getting a green jelly bean. Let O = the event of getting an orange jelly bean. Let P = the event of getting a purple jelly bean. Let R = the event of getting a red jelly bean. Let Y = the event of getting a yellow jelly bean. Find P(P).

Consider the following scenario: Let P(C) = 0.4. Let P(D) = 0.5. Let P(C|D) = 0.6. a. Find P(C AND D). b. Are C and D mutually exclusive? Why or why not? c. Are C and D independent events? Why or why not? d. Find P(C OR D). e. Find P(D|C)

On February 28, 2013, a Field Poll Survey reported that 61% of California registered voters approved of allowing two people of the same gender to marry and have regular marriage laws apply to them. Among 18 to 39 year olds (California registered voters), the approval rating was 78%. Six in ten California registered voters said that the upcoming Supreme Court’s ruling about the constitutionality of California’s Proposition 8 was either very or somewhat important to them. Out of those CA registered voters who support same-sex marriage, 75% say the ruling is important to them. In this problem, let: • C = California registered voters who support same-sex marriage. • B = California registered voters who say the Supreme Court’s ruling about the constitutionality of California’s Proposition 8 is very or somewhat important to them • A = California registered voters who are 18 to 39 years old. a. Find P(C). b. Find P(B). c. Find P(C|A). d. Find P(B|C). e. In words, what is C|A? f. In words, what is B|C? g. Find P(C AND B). h. In words, what is C AND B? i. Find P(C OR B). j. Are C and B mutually exclusive events? Show why or why not.

Use the following information to answer the next six exercises. A jar of 150 jelly beans contains 22 red jelly beans, 38 yellow, 20 green, 28 purple, 26 blue, and the rest are orange. Let B = the event of getting a blue jelly bean Let G = the event of getting a green jelly bean. Let O = the event of getting an orange jelly bean. Let P = the event of getting a purple jelly bean. Let R = the event of getting a red jelly bean. Let Y = the event of getting a yellow jelly bean. Find P(B)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.