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Use the following information to answer the next four exercises. A box is filled with several party favors. It contains 12 hats, 15 noisemakers, ten finger traps, and five bags of confetti. Let H = the event of getting a hat. Let N = the event of getting a noisemaker. Let F = the event of getting a finger trap. Let C = the event of getting a bag of confetti. Find P(H).

Short Answer

Expert verified
The probability of getting a hat, \( P(H) \), is \( \frac{2}{7} \).

Step by step solution

01

Determine the Total Number of Party Favors

First, calculate the total number of party favors in the box by adding the numbers of each type: 12 hats, 15 noisemakers, 10 finger traps, and 5 bags of confetti. This is calculated as follows: \( 12 + 15 + 10 + 5 = 42 \). Therefore, there are 42 total party favors in the box.
02

Calculate the Probability of Event H

The probability of getting a hat, \( P(H) \), is given by the formula \( \frac{\text{Number of H hats}}{\text{Total number of party favors}} \). Here, the number of hats is 12. So \( P(H) = \frac{12}{42} \).
03

Simplify the Probability Fraction

To simplify \( \frac{12}{42} \), find the greatest common divisor (GCD) of 12 and 42, which is 6. Divide both the numerator and the denominator by 6: \( \frac{12 \div 6}{42 \div 6} = \frac{2}{7} \).
04

Finalize the Probability of Getting a Hat

The simplified probability of getting a hat is \( \frac{2}{7} \). This means that if you were to randomly select one party favor from the box, there is a \( \frac{2}{7} \) chance that it will be a hat.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Event Probability
In probability, an 'event' is essentially any collection of possible outcomes. When we talk about the probability of an event, we are referring to the chance that this specific event will occur out of all the possible outcomes.

To calculate this, we use the formula for event probability, which is given by:
  • \[ P(Event) = \frac{\text{Number of favorable outcomes for the event}}{\text{Total number of possible outcomes}} \]


For example, in our box of party favors, the event might be selecting a hat. In this case, you count how many hats there are (which are your favorable outcomes), and divide it by the total number of party favors. This gives you the probability of the event occurring.
Simplifying Fractions Made Simple
Fractions are a mathematical expression representing division or part of a whole. Often fractions can be simplified for easier understanding and interpretation.

Simplifying a fraction means finding an equivalent fraction where the numerator (top number) and the denominator (bottom number) have no common factors other than 1. To do this, locate the greatest common divisor (GCD) of the numerator and the denominator and divide both by this GCD.

For example, if you have a fraction \(\frac{12}{42}\), find the GCD of 12 and 42, which is 6 in this case. Then, divide both the numerator and denominator by 6:
  • \[\frac{12 \div 6}{42 \div 6} = \frac{2}{7} \]


The fraction is now simplified, and it's easier to interpret in terms of probability or other contexts.
Counting Total Outcomes
In any probability experiment, knowing the total number of possible outcomes is crucial. It allows you to understand the base against which all probabilities are measured. Total outcomes can be counted by simply adding up all the different distinct items involved.

For example, in our box of party favors, you have several kinds of items: hats, noisemakers, finger traps, and confetti bags. To count total outcomes, you just add:
  • \(12 + 15 + 10 + 5 = 42\)
This sum, 42, represents the total number of party favors you could possibly pick if you randomly selected one from the box.

Knowing the total outcomes allows us to calculate the probability of each specific event, such as picking a hat, by comparing the number of favorable outcomes to this total.
The Process of Probability Calculation
There are various steps to calculating the probability of an event, but the process is straightforward. First, determine the event of interest and its outcomes, then count these favorable outcomes.

Next, calculate the total number of possible outcomes by adding all items together, as we did before. Once both numbers are known:
  • Plug them into the probability formula: \[ P(Event) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]


Use this formula to find the initial probability, then simplify the resulting fraction if necessary. In our example, calculating the probability for picking a hat:
  • Number of hats = 12
  • Total outcomes = 42


So the probability formula becomes: \[ P(Hat) = \frac{12}{42} \]

Simplify to get \[ \frac{2}{7} \].

And that's the step-by-step guide to probability calculation.

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Most popular questions from this chapter

Use the following information to answer the next ten exercises. On a baseball team, there are infielders and outfielders. Some players are great hitters, and some players are not great hitters. Let I = the event that a player in an infielder. Let O = the event that a player is an outfielder. Let H = the event that a player is a great hitter. Let N = the event that a player is not a great hitter Write the symbols for the probability that of all the great hitters, a player is an outfielder.

Use the following information to answer the next seven exercises. An article in the New England Journal of Medicine, reported about a study of smokers in California and Hawaii. In one part of the report, the self-reported ethnicity and smoking levels per day were given. Of the people smoking at most ten cigarettes per day, there were 9,886 African Americans, 2,745 Native Hawaiians, 12,831 Latinos, 8,378 Japanese Americans, and 7,650 Whites. Of the people smoking 11 to 20 cigarettes per day, there were 6,514 African Americans, 3,062 Native Hawaiians, 4,932 Latinos, 10,680 Japanese Americans, and 9,877 Whites. Of the people smoking 21 to 30 cigarettes per day, there were 1,671 African Americans, 1,419 Native Hawaiians, 1,406 Latinos, 4,715 Japanese Americans, and 6,062 Whites. Of the people smoking at least 31 cigarettes per day, there were 759 African Americans, 788 Native Hawaiians, 800 Latinos, 2,305 Japanese Americans, and 3,970 Whites. In words, explain what it means to pick one person from the study who is 鈥淛apanese American OR smokes 21 to 30 cigarettes per day.鈥 Also, find the probability.

Answer these questions using probability rules. Do NOT use the contingency table. Three thousand fifty-nine cases of AIDS had been reported in Santa Clara County, CA, through a certain date. Those cases will be our population. Of those cases, 6.4% obtained the disease through heterosexual contact and 7.4% are female. Out of the females with the disease, 53.3% got the disease from heterosexual contact. a. Find P(Person is female). b. Find P(Person obtained the disease through heterosexual contact). c. Find P(Person is female GIVEN person got the disease from heterosexual contact) d. Construct a Venn diagram representing this situation. Make one group females and the other group heterosexual contact. Fill in all values as probabilities.

Use the following information to answer the next ten exercises. Forty-eight percent of all Californians registered voters prefer life in prison without parole over the death penalty for a person convicted of first degree murder. Among Latino California registered voters, 55% prefer life in prison without parole over the death penalty for a person convicted of first degree murder. 37.6% of all Californians are Latino. In this problem, let: 鈥 C = Californians (registered voters) preferring life in prison without parole over the death penalty for a person convicted of first degree murder. 鈥 L = Latino Californians Suppose that one Californian is randomly selected. Find P(L AND C).

What is the probability of rolling an even number of dots with a fair, six- sided die numbered one through six?

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