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Use the following information to answer the next six exercises. There are 23 countries in North America, 12 countries in South America, 47 countries in Europe, 44 countries in Asia, 54 countries in Africa, and 14 in Oceania (Pacific Ocean region). Let A = the event that a country is in Asia. Let E = the event that a country is in Europe. Let F = the event that a country is in Africa. Let N = the event that a country is in North America. Let O = the event that a country is in Oceania. Let S = the event that a country is in South America. Find P(E).

Short Answer

Expert verified
The probability \(P(E)\) of a country being in Europe is \(\frac{47}{194}\).

Step by step solution

01

Identify Total Number of Countries

To find the probability of an event, we need the total number of outcomes. In this case, the total number of countries from all given regions. Add the number of countries from each region: North America (23), South America (12), Europe (47), Asia (44), Africa (54), and Oceania (14).
02

Calculate Total Number of Countries

Add the countries from all regions: \(23 + 12 + 47 + 44 + 54 + 14\). This gives the total number of countries worldwide.
03

Add the Numbers

Perform the addition: \(23 + 12 = 35\), \(35 + 47 = 82\), \(82 + 44 = 126\), \(126 + 54 = 180\), \(180 + 14 = 194\). Hence, the total number of countries is 194.
04

Number of Favorable Outcomes for Event E

Event E corresponds to a country being in Europe. Thus, the number of favorable outcomes, or successful events, is the number of European countries, which is 47.
05

Formula for Probability of an Event

The probability \(P(E)\) is calculated using the formula \(P(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\).
06

Calculate P(E)

Substitute the values into the probability formula: \(P(E) = \frac{47}{194}\).
07

Simplify the Probability Fraction

Check if \(\frac{47}{194}\) can be simplified. Both numbers only divide by 1, so the fraction is already in its simplest form.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Events in Probability
In probability, events are specific outcomes or sets of outcomes from a random experiment. When we talk about an event, we often denote it with a capital letter. For example, event E represents the scenario where a country is in Europe.
A key part of understanding events is knowing that they are subsets of the sample space. The sample space is simply all the possible outcomes of an experiment.
When calculating probabilities, we focus on the number of favorable outcomes, which are the outcomes where the event occurs.
This is compared to the total number of possible outcomes, which make up the sample space.
This ratio helps us figure out how likely an event is to happen.
Calculating Total Outcomes
Calculating total outcomes is important when determining the probability of an event.
It involves counting all possible results that can come from an experiment. This total forms the denominator in our probability calculations.
In the exercise, calculating the total number of countries was crucial. Each country represents a possible outcome.
So, we added the countries from each geographical region: North America, South America, Europe, Asia, Africa, and Oceania. This helped determine the complete set of outcomes.
  • North America: 23 countries
  • South America: 12 countries
  • Europe: 47 countries
  • Asia: 44 countries
  • Africa: 54 countries
  • Oceania: 14 countries
Adding them gives a total of 194 outcomes.
This number is essential for calculating any event's probability related to these countries.
Simplifying Fractions
When a probability is expressed as a fraction, simplification might be necessary. Simplifying a fraction means finding an equivalent fraction where the numerator and denominator have no common factors except 1.
For example, if we have a probability expressed as \( \frac{6}{8} \), we simplify it by dividing both numbers by 2, resulting in \( \frac{3}{4} \).
In the exercise, we found \( P(E) = \frac{47}{194} \). After checking for common factors, we see both numbers are relatively prime, meaning they are only divisible by 1 and themselves.
Hence, \( \frac{47}{194} \) is already in its simplest form.
Simplifying makes fractions easier to understand and work with, aiding in clearer communication of results.
Geographical Regions
Understanding geographical regions helps us comprehend the sample space in probability when dealing with global data.
In this exercise, regions such as North America, South America, Europe, Asia, Africa, and Oceania represent different groupings of countries based on location.
These regions help determine where each country fits within the probability framework by categorizing them according to their geographical attributes.
Knowing how countries are distributed globally can aid in predicting and making sense of the probability outcomes we calculate. For instance, if we want to find the probability of picking a European country, knowing how many countries are in Europe compared to other regions is crucial.
Sample Space in Probability
The sample space is a fundamental concept that represents all possible outcomes of a probability experiment.
In our exercise, the sample space includes all 194 countries across the various geographical regions. Each country is a unique outcome contributing to this total.
  • North America: 23 outcomes
  • South America: 12 outcomes
  • Europe: 47 outcomes
  • Asia: 44 outcomes
  • Africa: 54 outcomes
  • Oceania: 14 outcomes
This comprehensive collection of outcomes enables us to determine the likelihood of any single event, such as selecting a country from Europe or any other region.
Understanding the sample space is vital for accurately calculating probabilities and making informed predictions.

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Most popular questions from this chapter

Use the following information to answer the next seven exercises. An article in the New England Journal of Medicine, reported about a study of smokers in California and Hawaii. In one part of the report, the self-reported ethnicity and smoking levels per day were given. Of the people smoking at most ten cigarettes per day, there were 9,886 African Americans, 2,745 Native Hawaiians, 12,831 Latinos, 8,378 Japanese Americans, and 7,650 Whites. Of the people smoking 11 to 20 cigarettes per day, there were 6,514 African Americans, 3,062 Native Hawaiians, 4,932 Latinos, 10,680 Japanese Americans, and 9,877 Whites. Of the people smoking 21 to 30 cigarettes per day, there were 1,671 African Americans, 1,419 Native Hawaiians, 1,406 Latinos, 4,715 Japanese Americans, and 6,062 Whites. Of the people smoking at least 31 cigarettes per day, there were 759 African Americans, 788 Native Hawaiians, 800 Latinos, 2,305 Japanese Americans, and 3,970 Whites. Suppose that one person from the study is randomly selected. Find the probability that person smoked 11 to 20 cigarettes per day.

Use the following information to answer the next two exercises. You are rolling a fair, six-sided number cube. Let E = the event that it lands on an even number. Let M = the event that it lands on a multiple of three. What does P(E OR M) mean in words?

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A shelf holds 12 books. Eight are fiction and the rest are nonfiction. Each is a different book with a unique title. The fiction books are numbered one to eight. The nonfiction books are numbered one to four. Randomly select one book Let F = event that book is fiction Let N = event that book is nonfiction What is the sample space?

Use the following information to answer the next ten exercises. Forty-eight percent of all Californians registered voters prefer life in prison without parole over the death penalty for a person convicted of first degree murder. Among Latino California registered voters, 55% prefer life in prison without parole over the death penalty for a person convicted of first degree murder. 37.6% of all Californians are Latino. In this problem, let: • C = Californians (registered voters) preferring life in prison without parole over the death penalty for a person convicted of first degree murder. • L = Latino Californians Suppose that one Californian is randomly selected. Are L and C mutually exclusive events? Show why or why not.

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