/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 94 Use the following information to... [FREE SOLUTION] | 91Ó°ÊÓ

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Use the following information to answer the next nine exercises: The population parameters below describe the full-time equivalent number of students (FTES) each year at Lake Tahoe Community College from 1976–1977 through 2004–2005. \(\bullet \mu=1000 \mathrm{FTES}\) \(\bullet\) median \(=1,014 \mathrm{FTES}\) \(\bullet \quad \sigma=474 \mathrm{FTES}\) \(\cdot\) first quartile \(=528.5\) FTES \(\cdot\) third quartile \(=1,447.5\) FTES \(\cdot n=29\) years A sample of 11 years is taken. About how many are expected to have a FTES of 1014 or above? Explain how you determined your answer.

Short Answer

Expert verified
Approximately 6 years.

Step by step solution

01

Understand the Context

The problem provides population parameters concerning a set of student data. We need to find out how many years in a sample of 11 can be expected to have FTES of 1014 or more.
02

Analyze the Median

The median value given is 1014 FTES. This means that 50% of the distribution lies below this value, and 50% lies above it.
03

Determine the Expected Sample Count

Since half of the FTES values are expected to be below the median of 1014 FTES, and half above, in a randomly selected sample of 11 years, approximately half of those years should have FTES above 1014.
04

Calculate Approximate Number

Calculate the approximate count by dividing the sample size by two: \[\text{Expected count} \approx \frac{11}{2} = 5.5\]Since you cannot have half a year, round 5.5 to the nearest whole number.
05

Final Conclusion

Round 5.5 to 6, since it’s customary to round to the nearest whole number when talking about counts. Therefore, about 6 out of 11 years are expected to have FTES of 1014 or above.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Parameters
When studying statistics in education, population parameters play a crucial role. These parameters, such as mean, median, and standard deviation, represent characteristics of a whole population. For Lake Tahoe Community College's data, these figures provide insights into the student enrollment trends over nearly three decades. The mean, denoted as \( \mu \), is 1000 FTES, suggesting the average number of full-time students equivalent over the years. The standard deviation, \( \sigma \), is 474 FTES, indicating how much variation there is from the average. These parameters help summarize large datasets into understandable figures, which is valuable for administrators and educators who want to track or predict trends without analyzing each year individually.
Median
The median is the middle value that separates a dataset into two equal halves. For instance, in our student data with 29 years record, the median FTES is 1014. This means that half of the years had less than 1014 FTES, and the other half had more. Understanding the median is important because it provides a measure of central tendency that is not affected by extremely high or low values, known as outliers. When deciding how many years in our sample likely have an FTES of 1014 or more, knowing the median helps in estimating that half of the observations will be above this value when sampling from the population.
Sampling
Sampling involves selecting a subset of individuals from a population to make inferences about the entire population. In our exercise, we are drawing 11 years from a 29-year span. Sampling allows us to estimate population characteristics without examining the entire dataset. Random sampling, which assumes every year had an equal chance of being chosen, is crucial for achieving unbiased results. By taking 11 years as a sample, we can estimate what proportions of certain characteristics—such as FTES greater than the median—exist in the entire population. This technique is especially useful in statistics education, enabling predictions and analyses with limited resources.
Expected Value
The concept of expected value is fundamental in statistics when predicting outcomes. It refers to the average of all possible values of a random variable weighted by their probabilities. For our problem, we want to predict how many years in a random sample of 11 will have FTES of 1014 or more. Since the median indicates that 50% of the data is above and 50% is below 1014 FTES, we expect half of our sample years to meet or exceed this value. This means, for our sample size of 11, the expected number of years with an FTES of 1014 or greater is approximately 5.5, and we round this to the nearest whole number, getting 6. Understanding expected value helps in making informed predictions and decisions, which is vital in fields like education administration where such data informs strategic planning.

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Most popular questions from this chapter

In a recent issue of the IEEE Spectrum, 84 engineering conferences were announced. Four conferences lasted two days. Thirty-six lasted three days. Eighteen lasted four days. Nineteen lasted five days. Four lasted six days. One lasted seven days. One lasted eight days. One lasted nine days. Let \(X=\) the length (in days) of an engineering conference. a. Organize the data in a chart. b. Find the median, the first quartile, and the third quartile. c. Find the 65th percentile. d. Find the 10th percentile. e. Construct a box plot of the data. f. The middle 50\(\%\) of the conferences last from _____ days to _____ days. g. Calculate the sample mean of days of engineering conferences. h. Calculate the sample standard deviation of days of engineering conferences. i. Find the mode. j. If you were planning an engineering conference, which would you choose as the length of the conference: mean; median; or mode? Explain why you made that choice. k. Give two reasons why you think that three to five days seem to be popular lengths of engineering conferences.

Forty randomly selected students were asked the number of pairs of sneakers they owned. Let \(X=\) the number of pairs of sneakers owned.The results are as follows: $$\begin{array}{|l|l|}\hline X & {\text { Frequency }} \\ \hline 1 & {2} \\\ \hline 2 & {5} \\ \hline 3 & {8} \\ \hline 4 & {12} \\ \hline 5 & {12} \\\ \hline 6 & {0} \\ \hline 7 & {1} \\ \hline\end{array}$$ a. Find the sample mean \(\overline{x}\) b. Find the sample standard deviation, s c. Construct a histogram of the data. d. Complete the columns of the chart. e. Find the first quartile. f. Find the median. g. Find the third quartile. h. Construct a box plot of the data. i. What percent of the students owned at least five pairs? j. Find the \(40^{\text { th }}\) percentile. k. Find the \(90^{\text { th }}\) percentile. I. Construct a line graph of the data m. Construct a stemplot of the data

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