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Use the following information to answer the next five exercises. A random sample of ten professional athletes produced the following data where \(x\) is the number of endorsements the player has and \(y\) is the amount of money made (in millions of dollars). $$\begin{array}{|c|c|c|c|}\hline x & {y} & {x} & {y} \\ \hline 0 & {2} & {5} & {12} \\ \hline 3 & {8} & {4} & {9} \\ \hline 2 & {7} & {3} & {9} \\\ \hline 1 & {3} & {0} & {3} \\ \hline 5 & {13} & {4} & {10} \\\ \hline\end{array}$$ Table 12.13 Draw the line of best fit on the scatter plot.

Short Answer

Expert verified
The line of best fit is \( y = 2.79 + 1.78x \).

Step by step solution

01

Calculate necessary summations

First, calculate the individual sum for the variables and their squares and products. Let's denote \( n = 10 \) (number of athletes). We need:- \( \sum x = 0 + 5 + 3 + 4 + 2 + 3 + 1 + 0 + 5 + 4 = 27 \)- \( \sum y = 2 + 12 + 8 + 9 + 7 + 9 + 3 + 3 + 13 + 10 = 76 \)- \( \sum xy = (0 \times 2) + (5 \times 12) + (3 \times 8) + (4 \times 9) + (2 \times 7) + (3 \times 9) + (1 \times 3) + (0 \times 3) + (5 \times 13) + (4 \times 10) = 241 \)- \( \sum x^2 = 0^2 + 5^2 + 3^2 + 4^2 + 2^2 + 3^2 + 1^2 + 0^2 + 5^2 + 4^2 = 93 \)These summations will be used to find the line of best fit.
02

Calculate slope and intercept for line of best fit

Using the linear regression formulas for slope \( b \) and intercept \( a \), calculate the line of best fit:- Calculate slope \( b \): \[ b = \frac{n(\sum xy) - (\sum x)(\sum y)}{n(\sum x^2) - (\sum x)^2} = \frac{10 \times 241 - 27 \times 76}{10 \times 93 - 27^2} \] Simplifying gives: \[ b = \frac{2410 - 2052}{930 - 729} = \frac{358}{201} \approx 1.78 \]- Calculate intercept \( a \): \[ a = \frac{(\sum y) - b(\sum x)}{n} = \frac{76 - 1.78 \times 27}{10} \] Simplifying gives: \[ a = \frac{76 - 48.06}{10} = 2.794 \approx 2.79 \]
03

Equation of the line of best fit

The line of best fit can now be written in the form of \( y = ax + b \). Substituting the calculated \( a \) and \( b \), the equation becomes:\[ y = 2.79 + 1.78x \]
04

Plot the scatter plot and line

To complete the drawing on a scatter plot, plot each data point based on the given \( x \) and \( y \) values. Then graph the line of best fit using the equation \( y = 2.79 + 1.78x \). Start by plotting the y-intercept at \( y = 2.79 \) when \( x = 0 \), and use the slope of 1.78 to determine other points, moving up 1.78 units on the y-axis for every unit moved on the x-axis. The line should reflect the general trend of increasing money with more endorsements.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Scatter Plot Analysis
When working with data involving two quantitative variables, a scatter plot is a handy visualization tool. It helps us understand relationships or patterns within the data. In our example with professional athletes, we have two variables: the number of endorsements (x) and the income in millions of dollars (y). By plotting these data points on a graph where each pair (x, y) denotes a point, we can visualize how the two variables interact.

Here, every data point on the graph corresponds to an athlete showing their number of endorsements against their income. If points tend to rise in a specific direction, it indicates a possible linear relationship. This is where the concept of the 'line of best fit' comes into play, helping us quantify and explain that relationship further.
  • The X-axis typically represents the independent variable - number of endorsements.
  • The Y-axis represents the dependent variable - money made.
  • Look for a pattern in the points; in our dataset, we aim to identify if there's a trend as the number of endorsements increases.
Line of Best Fit
The line of best fit is a straight line that best represents the data on a scatter plot. It's the backbone of linear regression analysis, providing insights into the relationship between two variables. The objective of drawing a line of best fit is to minimize the distance from each data point to the line itself, thus representing the data trend as accurately as possible.

This line makes predictions possible! By understanding the general trend, you can predict the dependent variable's value (y) for any given independent variable (x) value that wasn't part of the original dataset.
  • The line's slope (b) indicates how much y (money made) changes for each additional unit in x (endorsements).
  • The intercept (a) tells you what y equals when x is zero, essentially the starting point of income when there are no endorsements.

Utilizing the line of best fit, you'll notice it better captures the overall trend than connecting individual points. It's constructed mathematically using the least-squares method, which finds the most optimal slope and intercept by minimizing the square of vertical distances from the line to each point.

Ultimately, the line of best fit serves as a tool of intuition, enabling deeper understanding of the dynamics of two related variables.
Slope and Intercept Calculations
In linear regression, calculating the slope and intercept of the line of best fit is critical to understanding the relationship between your variables.To find the slope (b) and intercept (a), we use specific formulas that leverage summations of the means and products of your data points:
  • Slope (b):

    The formula for the slope is
    \[ b = \frac{n(\sum xy) - (\sum x)(\sum y)}{n(\sum x^2) - (\sum x)^2} \]
    Notice that this formula considers the covariance of x and y divided by the variance of x. In our exercise, the calculation led to a slope of approximately 1.78.
  • Intercept (a):

    Once you have the slope, you can calculate the intercept using:
    \[ a = \frac{(\sum y) - b(\sum x)}{n} \]
    This provides the starting value of y when x is zero, estimated here around 2.79 million dollars.
These calculations transform abstract data into a practical equation: \[ y = a + bx \]
In this context, once you've established a slope and intercept, you can model and forecast outcomes, helping make informed decisions based on data insights.

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Most popular questions from this chapter

Use the following information to answer the next two exercises. The price of a single issue of stock can fluctuate throughout the day. A linear equation that represents the price of stock for Shipment Express is \(y=15-1.5 x\) where \(x\) is the number of hours passed in an eight-hour day of trading. If you owned this stock, would you want a positive or negative slope? Why?

Use the following information to answer the next three exercises. A vacation resort rents SCUBA equipment to certified divers. The resort charges an up- front fee of \(\$ 25\) and another fee of \(\$ 12.50\) an hour. What are the dependent and independent variables?

Use the following information to answer the next two exercises. An electronics retailer used regression to find a simple model to predict sales growth in the first quarter of the new year (January through March). The model is good for 90 days, where x is the day. The model can be written as follows: \(\hat{y}=101.32+2.48 x\) where \(\hat{y}\) is in thousands of dollars. What would you predict the sales to be on day 90?

The maximum discount value of the Entertainment庐 card for the 鈥淔ine Dining鈥 section, Edition ten, for various pages is given in Table 12.21 $$\begin{array}{|c|c|}\hline \text { Page number } & {\text { Maximum value (s) }} \\ \hline 4 & {16} \\ \hline 14 & {19} \\ \hline 25 & {19} \\\ \hline 25 & {17} \\ \hline 43 & {17} \\ \hline 42 & {15} \\ \hline 72 & {15} \\ \hline 85 & {17} \\ \hline 90 & {17} \\ \hline\end{array}$$ a. Decide which variable should be the independent variable and which should be the dependent variable. b. Draw a scatter plot of the ordered pairs. c. Calculate the least-squares line. Put the equation in the form of: \(\hat{y}=a+b x\) d. Find the correlation coefficient. Is it significant? e. Find the estimated maximum values for the restaurants on page ten and on page 70 . f. Does it appear that the restaurants giving the maximum value are placed in the beginning of the 鈥淔ine Dining鈥 section? How did you arrive at your answer? g. Suppose that there were 200 pages of restaurants. What do you estimate to be the maximum value for a restaurant listed on page 200? h. Is the least squares line valid for page 200? Why or why not? i. What is the slope of the least-squares (best-fit) line? Interpret the slope.

Table 12.22 gives the gold medal times for every other Summer Olympics for the women鈥檚 100-meter freestyle (swimming). $$ \begin{array}{|c|c|}\hline \text { Year } & {\text { Time (seconds) }} \\\ \hline 1912 & {82.2} \\ \hline 1924 & {72.4} \\ \hline 1932 & {66.8} \\\ \hline 1952 & {66.8} \\ \hline 1960 & {61.2} \\ \hline 1968 & {60.0} \\\ \hline 1968 & {55.65} \\ \hline\end{array} $$ $$ \begin{array}{|c|c|}\hline \text { Year } & {\text { Time (seconds) }} \\\ \hline 1984 & {55.92} \\ \hline 1992 & {54.64} \\ \hline 2000 & {53.8} \\\ \hline 2008 & {53.1} \\ \hline\end{array} $$ a. Decide which variable should be the independent variable and which should be the dependent variable. b. Draw a scatter plot of the data. c. Does it appear from inspection that there is a relationship between the variables? Why or why not? d. Calculate the least squares line. Put the equation in the form of: \(\hat{y}=a+b x .\) e. Find the correlation coefficient. Is the decrease in times significant? f. Find the estimated gold medal time for 1932. Find the estimated time for 1984. g. Why are the answers from part f different from the chart values? h. Does it appear that a line is the best way to fit the data? Why or why not? i. Use the least-squares line to estimate the gold medal time for the next Summer Olympics. Do you think that your answer is reasonable? Why or why not?

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