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Elizabeth Mjelde, an art history professor, was interested in whether the value from the Golden Ratio formula, $$ \left(\frac{\text { larger }+\text { smaller dimension }}{\text { larger dimension }}\right) $$ was the same in the Whitney Exhibit for works from 1900 to 1919 as for works from 1920 to 1942. Thirty-seven early works were sampled, averaging 1.74 with a standard deviation of 0.11. Sixty-five of the later works were sampled, averaging 1.746 with a standard deviation of 0.1064. Do you think that there is a significant difference in the Golden Ratio calculation?

Short Answer

Expert verified
No significant difference in Golden Ratio calculations between the two periods.

Step by step solution

01

Formulate the Hypotheses

We begin by defining the null hypothesis \( H_0 \) and the alternative hypothesis \( H_1 \). The null hypothesis states that there is no significant difference in the Golden Ratio calculations for the two periods: 1900-1919 and 1920-1942. Mathematically, \( H_0: \mu_1 = \mu_2 \). The alternative hypothesis \( H_1 \) states that there is a significant difference: \( H_1: \mu_1 eq \mu_2 \).
02

Collect and Note Down the Data

From the exercise, we know for the period 1900-1919, the mean Golden Ratio is 1.74 and the standard deviation is 0.11, with a sample size of 37. For the period 1920-1942, the mean is 1.746, the standard deviation is 0.1064, with a sample size of 65.
03

Determine the Test Statistic

We will use a two-sample t-test to compare the means of two independent samples. The formula for the test statistic \( t \) is: \[ t = \frac{\bar{x}_1 - \bar{x}_2}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}} \]where \( \bar{x}_1 \) and \( \bar{x}_2 \) are the means, \( s_1 \) and \( s_2 \) are the standard deviations, and \( n_1 \) and \( n_2 \) are the sample sizes for the two periods.
04

Calculate the Test Statistic

Substitute the given values into the formula:\[ t = \frac{1.74 - 1.746}{\sqrt{\frac{0.11^2}{37} + \frac{0.1064^2}{65}}} \]Calculate the difference in means \( 1.74 - 1.746 = -0.006 \). Compute the denominator:\[ \sqrt{\frac{0.11^2}{37} + \frac{0.1064^2}{65}} \approx 0.022 \]Thus the test statistic is:\[ t \approx \frac{-0.006}{0.022} \approx -0.273 \]
05

Determine the Critical Value and Make a Decision

With degrees of freedom approximated from the two sample sizes (use or refer to a t-distribution table or software, typically df = 76), check the critical t-value for a two-tailed test at a chosen significance level (often \( \alpha = 0.05 \)). The critical value is approximately ±2.00. Our test statistic \(-0.273\) does not exceed the critical values.
06

Conclusion

Since the absolute value of the calculated t-statistic \( |-0.273| \) is less than the critical t-value, we fail to reject the null hypothesis. There is no significant evidence to suggest a difference in the Golden Ratio mean calculations between the two periods.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Two-Sample t-Test
A two-sample t-test is a statistical method used to determine if there is a significant difference between the means of two independent groups. This test is particularly useful when you want to compare differences between two separate time periods, control versus experimental groups, or any other independent groups.

The test involves comparing the means of both groups, adjusting for the variability within each group, and then determining if the difference is statistically significant. This is done by calculating a test statistic that follows a t-distribution and comparing it to a critical value.
  • If the test statistic is larger than the critical value, the difference is considered statistically significant.
  • If not, any observed difference is likely due to random chance.
This test is essential in scientific research as it helps us to validate or refute a hypothesis based on collected data.
Golden Ratio
The Golden Ratio is a mathematical ratio, roughly 1.618, and it frequently appears in geometry, art, architecture, and even nature. It is often symbolized by the Greek letter phi (φ).

When discussing art and the Golden Ratio, it often pertains to the pleasing proportions that some artworks embody. It arises from the equation:\[\phi = \frac{a + b}{a} = \frac{a}{b}\]
  • "a" represents the longer part, and "b" is the shorter part.
  • The entire length "a + b" divided by "a" is equal to "a" divided by "b".
In this exercise, the Golden Ratio's relevance is applied to assessing the proportionality differences in artworks from two different eras.
Null Hypothesis
The null hypothesis, typically denoted as \( H_0 \), suggests that there is no effect or no difference between groups or variables being studied. In our specific exercise concerning the Golden Ratio, the null hypothesis is that there is no significant difference between the Golden Ratio calculations for artworks from the two specified eras.

This forms the baseline that scientists or researchers are trying to disprove or reject, usually by showing that any observed effect is unlikely to have occurred by random chance.
  • If the data provides enough evidence against \( H_0 \), we reject it in favor of an alternative hypothesis \( H_1 \).
  • However, if the data does not provide enough evidence, we fail to reject \( H_0 \).
Test Statistic
The test statistic is a value used in hypothesis testing that helps determine whether to reject the null hypothesis. It represents the difference between your observed results and expectations under the null hypothesis, normalized by the variability or standard deviation of the results.

In the two-sample t-test, the test statistic \( t \) is calculated as follows:\[t = \frac{\bar{x}_1 - \bar{x}_2}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}}\]
  • Here, \( \bar{x}_1 \) and \( \bar{x}_2 \) are the sample means for the two groups.
  • \( s_1 \) and \( s_2 \) are the standard deviations, and \( n_1 \) and \( n_2 \) are the sample sizes of the groups.
By comparing the test statistic to a critical value from the t-distribution, researchers can determine the significance of their results.
Degrees of Freedom
Degrees of freedom (df) are a concept crucial in many statistical analyses, including the two-sample t-test. They refer to the number of independent values or quantities that can vary in analysis while estimating a parameter. In simpler terms, they are the number of values that have the freedom to vary while still conforming to a set constraint.

With a two-sample t-test, the degrees of freedom can be calculated as:
  • \( df = n_1 + n_2 - 2 \)
  • Where \( n_1 \) and \( n_2 \) are the sample sizes of the two groups.
Understanding the degrees of freedom helps in determining the critical value from the t-distribution table, which is used to assess whether the test statistic is significant. The df gives context to your test statistic and aids in drawing conclusions from your hypothesis test.

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Most popular questions from this chapter

Use the following information to answer the next 12 exercises: The U.S. Center for Disease Control reports that the mean life expectancy was 47.6 years for whites born in 1900 and 33.0 years for nonwhites. Suppose that you randomly survey death records for people born in 1900 in a certain county. Of the 124 whites, the mean life span was 45.3 years with a standard deviation of 12.7 years. Of the 82 nonwhites, the mean life span was 34.1 years with a standard deviation of 15.6 years. Conduct a hypothesis test to see if the mean life spans in the county were the same for whites and nonwhites. Explain why you chose the distribution you did for Exercise 10.24.

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Use the following information to answer the next 12 exercises: The U.S. Center for Disease Control reports that the mean life expectancy was 47.6 years for whites born in 1900 and 33.0 years for nonwhites. Suppose that you randomly survey death records for people born in 1900 in a certain county. Of the 124 whites, the mean life span was 45.3 years with a standard deviation of 12.7 years. Of the 82 nonwhites, the mean life span was 34.1 years with a standard deviation of 15.6 years. Conduct a hypothesis test to see if the mean life spans in the county were the same for whites and nonwhites. Is this a right-tailed, left-tailed, or two-tailed test?

Use the following information to answer the next two exercises. A new AIDS prevention drug was tried on a group of 224 HIV positive patients. Forty-five patients developed AIDS after four years. In a control group of 224 HIV positive patients, 68 developed AIDS after four years. We want to test whether the method of treatment reduces the proportion of patients that develop AIDS after four years or if the proportions of the treated group and the untreated group stay the same. Let the subscript t = treated patient and ut = untreated patient. The appropriate hypotheses are: a. \(H_{0} : p_{t}

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