/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 The government of a particular c... [FREE SOLUTION] | 91Ó°ÊÓ

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The government of a particular country reports its literacy rate as \(52 \% .\) A nongovernmental organization believes it to be less. The organization takes a random sample of 600 inhabitants and obtains a literacy rate of \(42 \% .\) Perform the relevant test at the \(0.5 \%\) (one-half of \(1 \%)\) level of significance.

Short Answer

Expert verified
The literacy rate is significantly less than 52% at the 0.5% significance level.

Step by step solution

01

Set Up Hypotheses

We need to set up the null and alternative hypotheses. The null hypothesis \(H_0\) posits that the population literacy rate is \(52\%\), i.e., \(p = 0.52\). The alternative hypothesis \(H_a\) posits that the literacy rate is less than \(52\%\), i.e., \(p < 0.52\).
02

Determine the Significance Level

The significance level, \( \alpha \), is given as \(0.5\%\), which is \(0.005\) in decimal form. This will be used to determine the critical value from the z-distribution.
03

Calculate the Test Statistic

We use the formula for the test statistic in a proportion hypothesis test: \[z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}\]where \(\hat{p} = 0.42\), \(p_0 = 0.52\), and \(n = 600\). First, calculate: \[\sqrt{\frac{0.52(1-0.52)}{600}} \approx 0.02011\]Then, calculate the test statistic:\[z = \frac{0.42 - 0.52}{0.02011} \approx -4.97\]
04

Determine the Critical Value

For a one-tailed test at \(0.5\%\) significance level with \(H_a: p < 0.52\), we find the critical z-value from the z-table corresponding to \(0.005\). This critical value is approximately \(-2.576\).
05

Compare and Make Decision

Compare the calculated z-value \(-4.97\) with the critical value \(-2.576\). Since \(-4.97 < -2.576\), the calculated value falls in the rejection region, meaning we reject the null hypothesis \(H_0\).
06

Conclusion

At the \(0.5\%\) level of significance, we reject the null hypothesis. There is significant evidence to suggest that the literacy rate is less than \(52\%\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Literacy Rate
The literacy rate is a crucial measure used to gauge the education level of a population. It represents the percentage of people within a specific age group who can read and write. In the context of this exercise, the government has reported the country's literacy rate to be 52%. However, a nonprofit organization, suspecting this figure might be overstated, conducted its own survey.
They found a literacy rate of 42%, which is significantly lower than the government's report. This discrepancy sparked the need for a statistical test to verify the accuracy of these figures.
Understanding why literacy rate matters is important, as it directly impacts society's development, health, and economic growth.
  • Higher literacy rates often correlate with better job opportunities and economic stability.
  • They can lead to improved health outcomes, as educated individuals are more likely to understand health information.
  • They contribute to reduced poverty levels and promote gender equality, as education becomes accessible to everyone.
Diving into Significance Level
The significance level, denoted as \( \alpha \), plays a vital role in hypothesis testing. It represents the probability of rejecting the null hypothesis when it is actually true, commonly known as a Type I error.
For the given problem, the significance level is set at 0.5%, or 0.005.
This is a very stringent level. It reflects the high standard of evidence required to make a reliable conclusion about the country's literacy rate.
In general, the significance level serves to assure the reliability of a test's results.
  • Higher significance levels (e.g., 0.05 or 5%) allow for more flexibility and are often used when the cost of a Type I error is lower.
  • Lower significance levels (e.g., 0.01 or 1%) demand higher proof and are chosen in areas needing high precision, like pharmaceuticals or genetics.
  • The 0.5% level used here suggests that the organization needs compelling evidence against the reported literacy rate before declaring any findings.
Unpacking the Critical Value
In hypothesis testing, the critical value is a threshold that the test statistic must exceed to reject the null hypothesis. It marks the boundary of the rejection region in the test's distribution.
For this task, we are conducting a one-tailed test at a 0.5% significance level. Therefore, we need to find a critical z-value from the z-distribution that corresponds to this level.
In this problem, the critical value calculated is approximately \(-2.576\).
This means for the organization to claim that the literacy rate is indeed less than 52%, the test statistic would need to be less than this critical value.
  • A test statistic that exceeds the critical value indicates strong evidence against the null hypothesis.
  • If it doesn't exceed the critical value, we do not have enough evidence to reject the null hypothesis.
  • In our exercise, the actual test statistic \(-4.97\) was less than \(-2.576\), which means it was in the rejection region, leading to the rejection of the null hypothesis.
Exploring Proportion Hypothesis Test
A proportion hypothesis test is used when determining if the proportion of a specific characteristic in a population matches a claimed value.
It involves setting up null and alternative hypotheses, determining the significance level, calculating the test statistic, and comparing it to a critical value.
In our scenario, we are testing if the literacy rate is indeed less than the reported 52%.
  • The null hypothesis \(H_0\) states that the proportion is 52% \((p = 0.52)\).
  • The alternative hypothesis \(H_a\) suggests it’s less than 52% \((p < 0.52)\).
  • We calculate the test statistic using the formula: \[z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}} \] This approach helps determine if there is enough evidence to reject the null hypothesis in favor of the alternative.
  • Here, the organization's finding, with a sample proportion \(\hat{p}\) of 42% and sample size \(n = 600\), resulted in a test statistic of \(-4.97\).
Through this method, statistical tests help verify claims about a population proportion, offering objective insights into data.

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Most popular questions from this chapter

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