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A charitable organization wishes to estimate, to within half a percentage point, the proportion of all telephone solicitations to its donors that result in a gift, with \(90 \%\) confidence. Estimate the minimum sample size required, using the information that in the past the response rate has been about \(30 \%\).

Short Answer

Expert verified
The minimum sample size required is 22,731.

Step by step solution

01

Understand the Problem

To solve this problem, we need to determine the minimum sample size required to estimate the proportion of telephone solicitations that result in a gift, with a margin of error of 0.5% at a confidence level of 90%.
02

Identify the Formulas

The formula to determine the minimum sample size for estimating a proportion with a specified margin of error is:\[ n = \left( \frac{Z^2 \cdot p \cdot (1-p)}{E^2} \right) \] where \( Z \) is the Z-score corresponding to the confidence level, \( p \) is the estimated proportion, and \( E \) is the desired margin of error.
03

Determine Z-Score

For a 90% confidence level, the Z-score can be found from a standard normal distribution table, which is approximately 1.645.
04

Insert Values into Formula

Given:- \( p = 0.30 \)- \( E = 0.005 \) (since 0.5% equals 0.005 in decimal)We substitute these values into the formula:\[ n = \left( \frac{1.645^2 \cdot 0.30 \cdot (1-0.30)}{0.005^2} \right) \]
05

Calculate

Calculate the values:\[ n = \left( \frac{1.645^2 \cdot 0.30 \cdot 0.70}{0.005^2} \right) \]\[ n = \left( \frac{2.706025 \cdot 0.21}{0.000025} \right) \]\[ n = \left( \frac{0.56826525}{0.000025} \right) \]\[ n = 22730.61 \]
06

Round Up

Since the sample size must be a whole number, we always round up to ensure the margin of error requirement is met. Thus, the minimum sample size required is 22,731.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion Estimation
Estimating a proportion means figuring out the percentage of a whole that meets a certain condition. Imagine if we want to know what fraction of telephone calls result in a donation for a charity. That's exactly what's happening with proportion estimation. It's like taking a smaller, more manageable piece of a big puzzle to understand the bigger picture.
To do this, we look at a past "response rate," which in this case, is about 30%. This rate is our estimated proportion (denoted by \( p \)). It tells us that, out of all past solicitations, 30% yielded positive responses. But, just like how picking a few pieces won't give you the whole puzzle picture, a single estimate might not be accurate for predicting future outcomes.
Using sampled data to derive this proportion, helps charities - and other organizations - to plan better by understanding typical outcomes.
Confidence Interval
A confidence interval is like a safety net around our estimate. It tells us the range within which we can be fairly certain the true proportion lies. For this charitable organization, they want that certainty to be 90%. This means that if we were to repeat the sampling process many times, 90% of those times, the true proportion should end up within our calculated range. The confidence level directly impacts the width of this interval. A higher confidence level increases the Z-score value, making the interval wider, implying more certainty. In our problem, the organization chose a 90% confidence level, aligning the balance between precision and practicality. So, we use the Z-score of approximately 1.645 for calculations.
This confidence interval empowers decision-makers with a statistical "umbrella," ensuring they have a reliable estimate to work under when forecasting the outcome of their campaigns.
Margin of Error Calculation
The margin of error reflects how close we expect our estimate to be to the true population value. It’s like setting the stakes for how precise we want to be.
In this exercise, the organization wants to reach within 0.5% of accuracy. This might sound tiny, but in statistical terms, it's quite ambitious and requires a larger sample size to achieve. Using the formula: \[ n = \left( \frac{Z^2 \cdot p \cdot (1-p)}{E^2} \right) \]where:- \( n \) is the sample size needed,- \( Z \) is the Z-score for the confidence level,- \( p \) is the estimated proportion,- \( E \) is the margin of error. By entering the values - \( Z = 1.645 \), \( p = 0.30 \) and \( E = 0.005 \) - we've calculated the result to ensure our estimate falls within the desired range.
Remember, a smaller margin of error means we need a larger sample size, to more confidently estimate the true proportion. This precision helps organizations like our charity to reliably plan and allocate their resources.

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Most popular questions from this chapter

A random sample is drawn from a population of known standard deviation 11.3. Construct a \(90 \%\) confidence interval for the population mean based on the information given (not all of the information given need be used). a. \(\quad n=36, x-=105.2, s=11.2\) b. \(\quad n=100, x-=105.2, s=11.2\)

Estimate the minimum sample size needed to form a confidence interval for the proportion of a population that has a particular characteristic, meeting the criteria given. a. \(\quad p=0.37,80 \%\) confidence, \(E=0.05\) b. \(\quad p=0.37,90 \%\) confidence, \(E=0.05\) c. \(\quad \rho=0.37,80 \%\) confidence, \(E=0.01\)

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