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Problem 14. Prove that every countably normed space satisfies the first axiom of countability. Hint. Replace the system of neighborhoods \(U_{r, \varepsilon}\) by the subsystem such that \(E\) takes only the values $$ 1, \frac{1}{2}, \ldots, \frac{1}{n}, \ldots $$ (this can be done without changing the topology). Comment. Thus the topology in E can be described in terms of convergent sequences (recall Sec. 9.4).

Short Answer

Expert verified
Countably normed spaces have countable bases, satisfying the first axiom of countability.

Step by step solution

01

Understanding the Problem

We need to prove that every countably normed space satisfies the first axiom of countability. According to the hint, we can replace the neighborhood system \( U_{r, \varepsilon} \) by a specific subsystem.
02

Reviewing the First Axiom of Countability

The first axiom of countability states that a topological space has a countable basis at each point. A countably normed space needs to have a countable base for the neighborhoods around each point.
03

Defining Neighborhood System

In a normed space, the neighborhood around a point can be defined based on norms. For a normed space with a metric defined by the norm, we use balls \(B(p, r)\) that include all points \(x\) such that \(\|x - p\| < r\).
04

Formulating a Countable Base

For the subsystem given by the hint where \( E \) takes values \( 1, \frac{1}{2}, \frac{1}{3}, \ldots \), we create balls \( B(p, \varepsilon) \) for each point \( p \). These balls' radii \( \varepsilon \) can take countable values \(\varepsilon = \frac{1}{n}\) for integers \( n \).
05

Verifying Countable Subsystem

This subsystem forms a countable base because it uses only a countable set of values \(\left\{ 1, \frac{1}{2}, \frac{1}{3}, \ldots \right\}\) to define the neighborhood system. Thus, at each point, only countably many neighborhoods are used.
06

Concluding the Proof

Since every point in our normed space has a neighborhood system that is countably based due to these subsystems, every countably normed space satisfies the first axiom of countability.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

First Axiom of Countability
In topology, the First Axiom of Countability plays a crucial role. It states that at every point in a topological space, there should be a countable basis for the neighborhoods. A basis is essentially a set of open sets where any other open set including the point can be formed from overlapping these base sets. This concept simplifies the topology by allowing the use of sequences to study the properties of the space, making it essential for analysis in mathematics. The axiom is satisfied by any space where you can numerically describe the neighborhood around each point using a countable number of open sets. For instance, in a metric space, you often use open balls with radii from a countable set to do so.
  • This axiom is crucial in understanding and working with various types of topological spaces where sequences are prominent.
  • It allows us to describe the space and its convergence properties effectively and efficiently with just a countable collection of sets around each point.
Topology
Topology is a branch of mathematics that explores the properties of spaces that are preserved through deformation, twisting, and stretching, but not tearing or gluing. It's often referred to as a study of geometric properties and spatial relations unaffected by the continuous change of shape or size. A topology on a set gives it the structure that defines how subsets like neighborhoods behave and interact. It's defined by specifying which subsets of the set are open; these open sets must satisfy certain axioms.
  • Every topological space has a collection of open sets.
  • These sets are used to define concepts such as continuity, convergence, compactness, and connectedness.
The topology of a space can be described by convergence properties of sequences in that space, making it a powerful way to explore complex geometric and analytical properties. Countably normed spaces, as described in the original exercise, have a topology that allows a countable base for neighborhoods, making analysis easier.
Neighborhood System
In the context of topological spaces, a neighborhood of a point is an open set that contains the point. The collection of all possible neighborhoods of a point is known as the neighborhood system. This system is fundamental in understanding the local properties of a space. For normed spaces, neighborhoods can be visualized as open balls centered around points with a range defined by a radius. In the exercise's hint, replacing neighborhoods with a countable set of radii values allows us to use a simpler framework to discuss limits and convergence.
  • The neighborhood system is essential for defining limits and continuity—the bedrock of analysis.
  • It offers a structured way to understand how nearby points relate and how functions behave around those points.
By utilizing a neighborhood system with countable radii values, the topology remains unchanged, but it becomes more manageable, especially in proving concepts like the First Axiom of Countability.
Convergent Sequences
A sequence is said to converge if its terms approach a specific point, known as the limit, as the sequence progresses. Convergent sequences are fundamental in topology since they provide crucial insights into the properties of spaces.In a normed space, a sequence \(x_n\) is considered convergent to a point \(x\) if for any positive number \(\varepsilon\), no matter how small, there exists a number \(N\) such that for all \(n > N\), the distance \(\|x_n - x\| < \varepsilon\).
  • Convergent sequences help in understanding completeness, compactness, and other topological properties.
  • They are essential in defining continuity, differentiability, and integration within a space.
In the context of the exercise, the countable subsystem of neighborhoods ensures that sequences can be effectively analyzed for convergence, a key property for thorough explorations of topological structures.

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Most popular questions from this chapter

Let \(\mathrm{x}\) be any point of a locally convex topological linear space \(\mathrm{E}\), and let \(U\) be any neighborhood of \(\mathrm{x}\). Prove that \(\mathrm{x}\) has a convex neighborhood contained in \(U\). Hint. It is enough to consider the case \(\mathrm{x}=0\). Suppose \(U\) is a neighborhood of zero. Then there is a neighborhood Vof zero such that \(\mathrm{V}-\mathrm{V} \subset U\), where \(V-V\) is the same as in the hint to Problem 4 . Since \(E\) is locally convex, there is a nonempty convex open set \(V^{\prime} \subset \mathrm{V}\). If \(x_{0} \in \mathrm{V}^{\prime}\), then \(\mathrm{V}^{\prime}-x_{0}\) is a convex neighborhood of zero contained in \(U\).

Given a linear space \(\mathrm{E}, \mathrm{a}\) set \(U \subset \mathrm{E}\) is said to be symmetric if \(\mathrm{x} \in U\) implies \(-x \in U .\) Let \(\mathscr{B}\) be the set of all convex symmetric subsets of \(E\) such that each coincides with its own interior. Prove that a) \(\mathscr{B}\) is a system of neighborhoods of zero determining a locally convex topology \(\tau\) in \(\mathrm{E}\) which satisfies the first axiom of separation; b) The topology \(\tau\) is the strongest locally convex topology compatible with the linear operations in \(E\); c) Every linear functional on \(\mathrm{E}\) is continuous with respect to \(\tau\).

The norms \(\|\cdot\|_{n}\) in a countably normed space \(E\) can be assumed to satisfy the condition $$ \|x\|_{k} \leqslant\|x\|_{l} \quad \text { if } \quad k

Two norms \(\|\cdot\|_{1}\) and \(\|\cdot\|\), in a linear space \(\mathrm{E}\) are said to be compatible if, whenever a sequence \(\\{x\), in \(E\) is fundamental with respect to both norms and converges to a limit \(\mathrm{x} \in \mathrm{E}\) with respect to one of them, it also converges to the same limit \(\mathrm{x}\) with respect to the other norm. A linear space E equipped with a countable system of compatible norms \(\|\cdot\|_{n}\) is said to be countably normed. Prove that every countably normed linear space becomes a topological linear space when equipped with the topology generated by the neighborhood base consisting of all sets of the form $$ U_{r, \varepsilon}=\left\\{x: x \in E,\|x\|_{1}<\varepsilon, \ldots,\|x\|_{r}<\varepsilon\right\\} $$ for some number \(\varepsilon>0\) and positive integer \(\mathrm{r}\).

Let \(E\) be a topological linear space. Prove that a) If Uand Vare open sets, then so is \(U+V=\\{z: z=x+y, x \in U\), \(y \in V\\}\) b) If \(U\) is open, then so is \(\alpha U=\\{z: z=\mathrm{ax}, \mathrm{x} \in U\\}\) provided that \(\mathrm{a} \neq 0\) c) If \(F \subset E\) is closed, then so is \(\alpha F\) for arbitrary a.

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