Chapter 8: Problem 78
If \(f(x)=\frac{4}{x-3},\) why must 3 be excluded from the domain of \(f ?\)
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Chapter 8: Problem 78
If \(f(x)=\frac{4}{x-3},\) why must 3 be excluded from the domain of \(f ?\)
These are the key concepts you need to understand to accurately answer the question.
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Graph each of the three functions in the same \([-10,10,1]\) by \([-10,10,1]\) viewing rectangle. \(y_{1}=x^{2}-2 x\) \(y_{2}=x\) \(y_{3}=\frac{y_{1}}{y_{2}}\)
Describe how to find the inverse of a one-to-one function.
Find a. \((f \circ g)(x)\), b. \((g \circ f)(x)\), c. \((f \circ g)(2)\). $$f(x)=x^{2}+1, \quad g(x)=x^{2}-3$$
The functions are all one-to-one. For each function, a. Find an equation for \(f^{-1}(x),\) the inverse function. b. Verify that your equation is correct by showing that \(f\left(f^{-1}(x)\right)=x\) and \(f^{-1}(f(x))=x\). $$f(x)=\frac{2}{x}$$
Let $$\begin{array}{l}f(x)=2 x-5 \\\g(x)=4 x-1 \\\h(x)=x^{2}+x+2\end{array}$$. Evaluate the indicated function without finding an equation for the function. $$g(f[h(1)])$$
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